Calculus Examples

$g (t) = \frac{7}{t^{2}}$

Step 1

Since $7$ is constant with respect to $t$ , the derivative of $\frac{7}{t^{2}}$ with respect to $t$ is $7 \frac{d}{d t} [\frac{1}{t^{2}}]$ .

$7 \frac{d}{d t} [\frac{1}{t^{2}}]$

Step 2

Apply basic rules of exponents.

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Step 2.1

Rewrite $\frac{1}{t^{2}}$ as ${(t^{2})}^{- 1}$ .

$7 \frac{d}{d t} [{(t^{2})}^{- 1}]$

Step 2.2

Multiply the exponents in ${(t^{2})}^{- 1}$ .

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Step 2.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$7 \frac{d}{d t} [t^{2 \cdot - 1}]$

Step 2.2.2

Multiply $2$ by $- 1$ .

$7 \frac{d}{d t} [t^{- 2}]$

Step 3

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = - 2$ .

$7 (- 2 t^{- 3})$

Step 4

Multiply $- 2$ by $7$ .

$- 14 t^{- 3}$

Step 5

Simplify.

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Step 5.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$- 14 \frac{1}{t^{3}}$

Step 5.2

Combine terms.

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Step 5.2.1

Combine $- 14$ and $\frac{1}{t^{3}}$ .

$\frac{- 14}{t^{3}}$

Step 5.2.2

Move the negative in front of the fraction.

$- \frac{14}{t^{3}}$