Calculus Examples

$2 \cos (2 t)$

Step 1

Since $2$ is constant with respect to $t$ , the derivative of $2 \cos (2 t)$ with respect to $t$ is $2 \frac{d}{d t} [\cos (2 t)]$ .

$2 \frac{d}{d t} [\cos (2 t)]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = \cos (t)$ and $g (t) = 2 t$ .

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Step 2.1

To apply the Chain Rule, set $u$ as $2 t$ .

$2 (\frac{d}{d u} [\cos (u)] \frac{d}{d t} [2 t])$

Step 2.2

The derivative of $\cos (u)$ with respect to $u$ is $- \sin (u)$ .

$2 (- \sin (u) \frac{d}{d t} [2 t])$

Step 2.3

Replace all occurrences of $u$ with $2 t$ .

$2 (- \sin (2 t) \frac{d}{d t} [2 t])$

Step 3

Differentiate.

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Step 3.1

Multiply $- 1$ by $2$ .

$- 2 (\sin (2 t) \frac{d}{d t} [2 t])$

Step 3.2

Since $2$ is constant with respect to $t$ , the derivative of $2 t$ with respect to $t$ is $2 \frac{d}{d t} [t]$ .

$- 2 \sin (2 t) (2 \frac{d}{d t} [t])$

Step 3.3

Multiply $2$ by $- 2$ .

$- 4 \sin (2 t) \frac{d}{d t} [t]$

Step 3.4

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 1$ .

$- 4 \sin (2 t) \cdot 1$

Step 3.5

Multiply $- 4$ by $1$ .

$- 4 \sin (2 t)$