Calculus Examples

$\frac{2 x^{5} + 7}{x^{3}}$

Step 1

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = 2 x^{5} + 7$ and $g (x) = x^{3}$ .

$\frac{x^{3} \frac{d}{d x} [2 x^{5} + 7] - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{{(x^{3})}^{2}}$

Step 2

Differentiate.

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Step 2.1

Multiply the exponents in ${(x^{3})}^{2}$ .

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Step 2.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{x^{3} \frac{d}{d x} [2 x^{5} + 7] - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{x^{3 \cdot 2}}$

Step 2.1.2

Multiply $3$ by $2$ .

$\frac{x^{3} \frac{d}{d x} [2 x^{5} + 7] - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 2.2

By the Sum Rule, the derivative of $2 x^{5} + 7$ with respect to $x$ is $\frac{d}{d x} [2 x^{5}] + \frac{d}{d x} [7]$ .

$\frac{x^{3} (\frac{d}{d x} [2 x^{5}] + \frac{d}{d x} [7]) - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 2.3

Since $2$ is constant with respect to $x$ , the derivative of $2 x^{5}$ with respect to $x$ is $2 \frac{d}{d x} [x^{5}]$ .

$\frac{x^{3} (2 \frac{d}{d x} [x^{5}] + \frac{d}{d x} [7]) - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 2.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 5$ .

$\frac{x^{3} (2 (5 x^{4}) + \frac{d}{d x} [7]) - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 2.5

Multiply $5$ by $2$ .

$\frac{x^{3} (10 x^{4} + \frac{d}{d x} [7]) - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 2.6

Since $7$ is constant with respect to $x$ , the derivative of $7$ with respect to $x$ is $0$ .

$\frac{x^{3} (10 x^{4} + 0) - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 2.7

Add $10 x^{4}$ and $0$ .

$\frac{x^{3} (10 x^{4}) - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3

Multiply $x^{3}$ by $x^{4}$ by adding the exponents.

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Step 3.1

Move $x^{4}$ .

$\frac{x^{4} x^{3} \cdot 10 - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{x^{4 + 3} \cdot 10 - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.3

Add $4$ and $3$ .

$\frac{x^{7} \cdot 10 - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 4

Move $10$ to the left of $x^{7}$ .

$\frac{10 \cdot x^{7} - (2 x^{5} + 7) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$\frac{10 x^{7} - (2 x^{5} + 7) (3 x^{2})}{x^{6}}$

Step 6

Simplify with factoring out.

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Step 6.1

Multiply $3$ by $- 1$ .

$\frac{10 x^{7} - 3 (2 x^{5} + 7) x^{2}}{x^{6}}$

Step 6.2

Factor $x^{2}$ out of $10 x^{7} - 3 (2 x^{5} + 7) x^{2}$ .

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Step 6.2.1

Factor $x^{2}$ out of $10 x^{7}$ .

$\frac{x^{2} (10 x^{5}) - 3 (2 x^{5} + 7) x^{2}}{x^{6}}$

Step 6.2.2

Factor $x^{2}$ out of $- 3 (2 x^{5} + 7) x^{2}$ .

$\frac{x^{2} (10 x^{5}) + x^{2} (- 3 (2 x^{5} + 7))}{x^{6}}$

Step 6.2.3

Factor $x^{2}$ out of $x^{2} (10 x^{5}) + x^{2} (- 3 (2 x^{5} + 7))$ .

$\frac{x^{2} (10 x^{5} - 3 (2 x^{5} + 7))}{x^{6}}$

Step 7

Cancel the common factors.

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Step 7.1

Factor $x^{2}$ out of $x^{6}$ .

$\frac{x^{2} (10 x^{5} - 3 (2 x^{5} + 7))}{x^{2} x^{4}}$

Step 7.2

Cancel the common factor.

$\frac{x^{2} (10 x^{5} - 3 (2 x^{5} + 7))}{x^{2} x^{4}}$

Step 7.3

Rewrite the expression.

$\frac{10 x^{5} - 3 (2 x^{5} + 7)}{x^{4}}$

Step 8

Simplify.

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Step 8.1

Apply the distributive property.

$\frac{10 x^{5} - 3 (2 x^{5}) - 3 \cdot 7}{x^{4}}$

Step 8.2

Simplify the numerator.

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Step 8.2.1

Simplify each term.

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Step 8.2.1.1

Multiply $2$ by $- 3$ .

$\frac{10 x^{5} - 6 x^{5} - 3 \cdot 7}{x^{4}}$

Step 8.2.1.2

Multiply $- 3$ by $7$ .

$\frac{10 x^{5} - 6 x^{5} - 21}{x^{4}}$

Step 8.2.2

Subtract $6 x^{5}$ from $10 x^{5}$ .

$\frac{4 x^{5} - 21}{x^{4}}$