Calculus Examples

${(5 x + 2)}^{3}$

Step 1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{3}$ and $g (x) = 5 x + 2$ .

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Step 1.1

To apply the Chain Rule, set $u$ as $5 x + 2$ .

$\frac{d}{d u} [u^{3}] \frac{d}{d x} [5 x + 2]$

Step 1.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 3$ .

$3 u^{2} \frac{d}{d x} [5 x + 2]$

Step 1.3

Replace all occurrences of $u$ with $5 x + 2$ .

$3 {(5 x + 2)}^{2} \frac{d}{d x} [5 x + 2]$

Step 2

Differentiate.

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Step 2.1

By the Sum Rule, the derivative of $5 x + 2$ with respect to $x$ is $\frac{d}{d x} [5 x] + \frac{d}{d x} [2]$ .

$3 {(5 x + 2)}^{2} (\frac{d}{d x} [5 x] + \frac{d}{d x} [2])$

Step 2.2

Since $5$ is constant with respect to $x$ , the derivative of $5 x$ with respect to $x$ is $5 \frac{d}{d x} [x]$ .

$3 {(5 x + 2)}^{2} (5 \frac{d}{d x} [x] + \frac{d}{d x} [2])$

Step 2.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$3 {(5 x + 2)}^{2} (5 \cdot 1 + \frac{d}{d x} [2])$

Step 2.4

Multiply $5$ by $1$ .

$3 {(5 x + 2)}^{2} (5 + \frac{d}{d x} [2])$

Step 2.5

Since $2$ is constant with respect to $x$ , the derivative of $2$ with respect to $x$ is $0$ .

$3 {(5 x + 2)}^{2} (5 + 0)$

Step 2.6

Simplify the expression.

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Step 2.6.1

Add $5$ and $0$ .

$3 {(5 x + 2)}^{2} \cdot 5$

Step 2.6.2

Multiply $5$ by $3$ .

$15 {(5 x + 2)}^{2}$