Calculus Examples

$2 x \sin (2 x + 2)$

Step 1

Since $2$ is constant with respect to $x$ , the derivative of $2 x \sin (2 x + 2)$ with respect to $x$ is $2 \frac{d}{d x} [x \sin (2 x + 2)]$ .

$2 \frac{d}{d x} [x \sin (2 x + 2)]$

Step 2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = \sin (2 x + 2)$ .

$2 (x \frac{d}{d x} [\sin (2 x + 2)] + \sin (2 x + 2) \frac{d}{d x} [x])$

Step 3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \sin (x)$ and $g (x) = 2 x + 2$ .

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Step 3.1

To apply the Chain Rule, set $u$ as $2 x + 2$ .

$2 (x (\frac{d}{d u} [\sin (u)] \frac{d}{d x} [2 x + 2]) + \sin (2 x + 2) \frac{d}{d x} [x])$

Step 3.2

The derivative of $\sin (u)$ with respect to $u$ is $\cos (u)$ .

$2 (x (\cos (u) \frac{d}{d x} [2 x + 2]) + \sin (2 x + 2) \frac{d}{d x} [x])$

Step 3.3

Replace all occurrences of $u$ with $2 x + 2$ .

$2 (x (\cos (2 x + 2) \frac{d}{d x} [2 x + 2]) + \sin (2 x + 2) \frac{d}{d x} [x])$

Step 4

Differentiate.

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Step 4.1

By the Sum Rule, the derivative of $2 x + 2$ with respect to $x$ is $\frac{d}{d x} [2 x] + \frac{d}{d x} [2]$ .

$2 (x (\cos (2 x + 2) (\frac{d}{d x} [2 x] + \frac{d}{d x} [2])) + \sin (2 x + 2) \frac{d}{d x} [x])$

Step 4.2

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$2 (x (\cos (2 x + 2) (2 \frac{d}{d x} [x] + \frac{d}{d x} [2])) + \sin (2 x + 2) \frac{d}{d x} [x])$

Step 4.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 (x (\cos (2 x + 2) (2 \cdot 1 + \frac{d}{d x} [2])) + \sin (2 x + 2) \frac{d}{d x} [x])$

Step 4.4

Multiply $2$ by $1$ .

$2 (x (\cos (2 x + 2) (2 + \frac{d}{d x} [2])) + \sin (2 x + 2) \frac{d}{d x} [x])$

Step 4.5

Since $2$ is constant with respect to $x$ , the derivative of $2$ with respect to $x$ is $0$ .

$2 (x (\cos (2 x + 2) (2 + 0)) + \sin (2 x + 2) \frac{d}{d x} [x])$

Step 4.6

Simplify the expression.

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Step 4.6.1

Add $2$ and $0$ .

$2 (x (\cos (2 x + 2) \cdot 2) + \sin (2 x + 2) \frac{d}{d x} [x])$

Step 4.6.2

Move $2$ to the left of $\cos (2 x + 2)$ .

$2 (x (2 \cdot \cos (2 x + 2)) + \sin (2 x + 2) \frac{d}{d x} [x])$

Step 4.7

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 (x (2 \cos (2 x + 2)) + \sin (2 x + 2) \cdot 1)$

Step 4.8

Multiply $\sin (2 x + 2)$ by $1$ .

$2 (x (2 \cos (2 x + 2)) + \sin (2 x + 2))$

Step 5

Simplify.

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Step 5.1

Apply the distributive property.

$2 (x (2 \cos (2 x + 2))) + 2 \sin (2 x + 2)$

Step 5.2

Multiply $2$ by $2$ .

$4 x \cos (2 x + 2) + 2 \sin (2 x + 2)$