Calculus Examples

$f (x) = 3 x^{3} - 3 x^{2} - 3 x + 2$ , $[- 1, 0]$

Step 1

Find the critical points.

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Step 1.1

Find the first derivative.

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Step 1.1.1

Find the first derivative.

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Step 1.1.1.1

By the Sum Rule, the derivative of $3 x^{3} - 3 x^{2} - 3 x + 2$ with respect to $x$ is $\frac{d}{d x} [3 x^{3}] + \frac{d}{d x} [- 3 x^{2}] + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [2]$ .

$\frac{d}{d x} [3 x^{3}] + \frac{d}{d x} [- 3 x^{2}] + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [2]$

Step 1.1.1.2

Evaluate $\frac{d}{d x} [3 x^{3}]$ .

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Step 1.1.1.2.1

Since $3$ is constant with respect to $x$ , the derivative of $3 x^{3}$ with respect to $x$ is $3 \frac{d}{d x} [x^{3}]$ .

$3 \frac{d}{d x} [x^{3}] + \frac{d}{d x} [- 3 x^{2}] + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [2]$

Step 1.1.1.2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$3 (3 x^{2}) + \frac{d}{d x} [- 3 x^{2}] + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [2]$

Step 1.1.1.2.3

Multiply $3$ by $3$ .

$9 x^{2} + \frac{d}{d x} [- 3 x^{2}] + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [2]$

Step 1.1.1.3

Evaluate $\frac{d}{d x} [- 3 x^{2}]$ .

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Step 1.1.1.3.1

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3 x^{2}$ with respect to $x$ is $- 3 \frac{d}{d x} [x^{2}]$ .

$9 x^{2} - 3 \frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [2]$

Step 1.1.1.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$9 x^{2} - 3 (2 x) + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [2]$

Step 1.1.1.3.3

Multiply $2$ by $- 3$ .

$9 x^{2} - 6 x + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [2]$

Step 1.1.1.4

Evaluate $\frac{d}{d x} [- 3 x]$ .

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Step 1.1.1.4.1

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3 x$ with respect to $x$ is $- 3 \frac{d}{d x} [x]$ .

$9 x^{2} - 6 x - 3 \frac{d}{d x} [x] + \frac{d}{d x} [2]$

Step 1.1.1.4.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$9 x^{2} - 6 x - 3 \cdot 1 + \frac{d}{d x} [2]$

Step 1.1.1.4.3

Multiply $- 3$ by $1$ .

$9 x^{2} - 6 x - 3 + \frac{d}{d x} [2]$

Step 1.1.1.5

Differentiate using the Constant Rule.

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Step 1.1.1.5.1

Since $2$ is constant with respect to $x$ , the derivative of $2$ with respect to $x$ is $0$ .

$9 x^{2} - 6 x - 3 + 0$

Step 1.1.1.5.2

Add $9 x^{2} - 6 x - 3$ and $0$ .

$f' (x) = 9 x^{2} - 6 x - 3$

Step 1.1.2

The first derivative of $f (x)$ with respect to $x$ is $9 x^{2} - 6 x - 3$ .

$9 x^{2} - 6 x - 3$

Step 1.2

Set the first derivative equal to $0$ then solve the equation $9 x^{2} - 6 x - 3 = 0$ .

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Step 1.2.1

Set the first derivative equal to $0$ .

$9 x^{2} - 6 x - 3 = 0$

Step 1.2.2

Factor the left side of the equation.

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Step 1.2.2.1

Factor $3$ out of $9 x^{2} - 6 x - 3$ .

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Step 1.2.2.1.1

Factor $3$ out of $9 x^{2}$ .

$3 (3 x^{2}) - 6 x - 3 = 0$

Step 1.2.2.1.2

Factor $3$ out of $- 6 x$ .

$3 (3 x^{2}) + 3 (- 2 x) - 3 = 0$

Step 1.2.2.1.3

Factor $3$ out of $- 3$ .

$3 (3 x^{2}) + 3 (- 2 x) + 3 (- 1) = 0$

Step 1.2.2.1.4

Factor $3$ out of $3 (3 x^{2}) + 3 (- 2 x)$ .

$3 (3 x^{2} - 2 x) + 3 (- 1) = 0$

Step 1.2.2.1.5

Factor $3$ out of $3 (3 x^{2} - 2 x) + 3 (- 1)$ .

$3 (3 x^{2} - 2 x - 1) = 0$

Step 1.2.2.2

Factor.

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Step 1.2.2.2.1

Factor by grouping.

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Step 1.2.2.2.1.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 3 \cdot - 1 = - 3$ and whose sum is $b = - 2$ .

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Step 1.2.2.2.1.1.1

Factor $- 2$ out of $- 2 x$ .

$3 (3 x^{2} - 2 x - 1) = 0$

Step 1.2.2.2.1.1.2

Rewrite $- 2$ as $1$ plus $- 3$

$3 (3 x^{2} + (1 - 3) x - 1) = 0$

Step 1.2.2.2.1.1.3

Apply the distributive property.

$3 (3 x^{2} + 1 x - 3 x - 1) = 0$

Step 1.2.2.2.1.1.4

Multiply $x$ by $1$ .

$3 (3 x^{2} + x - 3 x - 1) = 0$

Step 1.2.2.2.1.2

Factor out the greatest common factor from each group.

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Step 1.2.2.2.1.2.1

Group the first two terms and the last two terms.

$3 ((3 x^{2} + x) - 3 x - 1) = 0$

Step 1.2.2.2.1.2.2

Factor out the greatest common factor (GCF) from each group.

$3 (x (3 x + 1) - (3 x + 1)) = 0$

Step 1.2.2.2.1.3

Factor the polynomial by factoring out the greatest common factor, $3 x + 1$ .

$3 ((3 x + 1) (x - 1)) = 0$

Step 1.2.2.2.2

Remove unnecessary parentheses.

$3 (3 x + 1) (x - 1) = 0$

Step 1.2.3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$3 x + 1 = 0$

$x - 1 = 0$

Step 1.2.4

Set $3 x + 1$ equal to $0$ and solve for $x$ .

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Step 1.2.4.1

Set $3 x + 1$ equal to $0$ .

$3 x + 1 = 0$

Step 1.2.4.2

Solve $3 x + 1 = 0$ for $x$ .

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Step 1.2.4.2.1

Subtract $1$ from both sides of the equation.

$3 x = - 1$

Step 1.2.4.2.2

Divide each term in $3 x = - 1$ by $3$ and simplify.

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Step 1.2.4.2.2.1

Divide each term in $3 x = - 1$ by $3$ .

$\frac{3 x}{3} = \frac{- 1}{3}$

Step 1.2.4.2.2.2

Simplify the left side.

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Step 1.2.4.2.2.2.1

Cancel the common factor of $3$ .

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Step 1.2.4.2.2.2.1.1

Cancel the common factor.

$\frac{3 x}{3} = \frac{- 1}{3}$

Step 1.2.4.2.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 1}{3}$

Step 1.2.4.2.2.3

Simplify the right side.

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Step 1.2.4.2.2.3.1

Move the negative in front of the fraction.

$x = - \frac{1}{3}$

Step 1.2.5

Set $x - 1$ equal to $0$ and solve for $x$ .

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Step 1.2.5.1

Set $x - 1$ equal to $0$ .

$x - 1 = 0$

Step 1.2.5.2

Add $1$ to both sides of the equation.

$x = 1$

Step 1.2.6

The final solution is all the values that make $3 (3 x + 1) (x - 1) = 0$ true.

$x = - \frac{1}{3}, 1$

Step 1.3

Find the values where the derivative is undefined.

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Step 1.3.1

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Step 1.4

Evaluate $3 x^{3} - 3 x^{2} - 3 x + 2$ at each $x$ value where the derivative is $0$ or undefined.

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Step 1.4.1

Evaluate at $x = - \frac{1}{3}$ .

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Step 1.4.1.1

Substitute $- \frac{1}{3}$ for $x$ .

$3 {(- \frac{1}{3})}^{3} - 3 {(- \frac{1}{3})}^{2} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2

Simplify.

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Step 1.4.1.2.1

Simplify each term.

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Step 1.4.1.2.1.1

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 1.4.1.2.1.1.1

Apply the product rule to $- \frac{1}{3}$ .

$3 ({(- 1)}^{3} {(\frac{1}{3})}^{3}) - 3 {(- \frac{1}{3})}^{2} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.1.2

Apply the product rule to $\frac{1}{3}$ .

$3 ({(- 1)}^{3} \frac{1^{3}}{3^{3}}) - 3 {(- \frac{1}{3})}^{2} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.2

Raise $- 1$ to the power of $3$ .

$3 (- \frac{1^{3}}{3^{3}}) - 3 {(- \frac{1}{3})}^{2} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.3

One to any power is one.

$3 (- \frac{1}{3^{3}}) - 3 {(- \frac{1}{3})}^{2} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.4

Raise $3$ to the power of $3$ .

$3 (- \frac{1}{27}) - 3 {(- \frac{1}{3})}^{2} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.5

Cancel the common factor of $3$ .

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Step 1.4.1.2.1.5.1

Move the leading negative in $- \frac{1}{27}$ into the numerator.

$3 (\frac{- 1}{27}) - 3 {(- \frac{1}{3})}^{2} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.5.2

Factor $3$ out of $27$ .

$3 \frac{- 1}{3 (9)} - 3 {(- \frac{1}{3})}^{2} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.5.3

Cancel the common factor.

$3 \frac{- 1}{3 \cdot 9} - 3 {(- \frac{1}{3})}^{2} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.5.4

Rewrite the expression.

$\frac{- 1}{9} - 3 {(- \frac{1}{3})}^{2} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.6

Move the negative in front of the fraction.

$- \frac{1}{9} - 3 {(- \frac{1}{3})}^{2} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.7

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 1.4.1.2.1.7.1

Apply the product rule to $- \frac{1}{3}$ .

$- \frac{1}{9} - 3 ({(- 1)}^{2} {(\frac{1}{3})}^{2}) - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.7.2

Apply the product rule to $\frac{1}{3}$ .

$- \frac{1}{9} - 3 ({(- 1)}^{2} \frac{1^{2}}{3^{2}}) - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.8

Raise $- 1$ to the power of $2$ .

$- \frac{1}{9} - 3 (1 \frac{1^{2}}{3^{2}}) - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.9

Multiply $\frac{1^{2}}{3^{2}}$ by $1$ .

$- \frac{1}{9} - 3 \frac{1^{2}}{3^{2}} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.10

One to any power is one.

$- \frac{1}{9} - 3 \frac{1}{3^{2}} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.11

Raise $3$ to the power of $2$ .

$- \frac{1}{9} - 3 (\frac{1}{9}) - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.12

Cancel the common factor of $3$ .

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Step 1.4.1.2.1.12.1

Factor $3$ out of $- 3$ .

$- \frac{1}{9} + 3 (- 1) \frac{1}{9} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.12.2

Factor $3$ out of $9$ .

$- \frac{1}{9} + 3 \cdot - 1 \frac{1}{3 \cdot 3} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.12.3

Cancel the common factor.

$- \frac{1}{9} + 3 \cdot - 1 \frac{1}{3 \cdot 3} - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.12.4

Rewrite the expression.

$- \frac{1}{9} - 1 (\frac{1}{3}) - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.13

Rewrite $- 1 (\frac{1}{3})$ as $- (\frac{1}{3})$ .

$- \frac{1}{9} - (\frac{1}{3}) - 3 (- \frac{1}{3}) + 2$

Step 1.4.1.2.1.14

Cancel the common factor of $3$ .

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Step 1.4.1.2.1.14.1

Move the leading negative in $- \frac{1}{3}$ into the numerator.

$- \frac{1}{9} - \frac{1}{3} - 3 (\frac{- 1}{3}) + 2$

Step 1.4.1.2.1.14.2

Factor $3$ out of $- 3$ .

$- \frac{1}{9} - \frac{1}{3} + 3 (- 1) \frac{- 1}{3} + 2$

Step 1.4.1.2.1.14.3

Cancel the common factor.

$- \frac{1}{9} - \frac{1}{3} + 3 \cdot - 1 \frac{- 1}{3} + 2$

Step 1.4.1.2.1.14.4

Rewrite the expression.

$- \frac{1}{9} - \frac{1}{3} - 1 \cdot - 1 + 2$

Step 1.4.1.2.1.15

Multiply $- 1$ by $- 1$ .

$- \frac{1}{9} - \frac{1}{3} + 1 + 2$

Step 1.4.1.2.2

Find the common denominator.

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Step 1.4.1.2.2.1

Multiply $\frac{1}{3}$ by $\frac{3}{3}$ .

$- \frac{1}{9} - (\frac{1}{3} \cdot \frac{3}{3}) + 1 + 2$

Step 1.4.1.2.2.2

Multiply $\frac{1}{3}$ by $\frac{3}{3}$ .

$- \frac{1}{9} - \frac{3}{3 \cdot 3} + 1 + 2$

Step 1.4.1.2.2.3

Write $1$ as a fraction with denominator $1$ .

$- \frac{1}{9} - \frac{3}{3 \cdot 3} + \frac{1}{1} + 2$

Step 1.4.1.2.2.4

Multiply $\frac{1}{1}$ by $\frac{9}{9}$ .

$- \frac{1}{9} - \frac{3}{3 \cdot 3} + \frac{1}{1} \cdot \frac{9}{9} + 2$

Step 1.4.1.2.2.5

Multiply $\frac{1}{1}$ by $\frac{9}{9}$ .

$- \frac{1}{9} - \frac{3}{3 \cdot 3} + \frac{9}{9} + 2$

Step 1.4.1.2.2.6

Write $2$ as a fraction with denominator $1$ .

$- \frac{1}{9} - \frac{3}{3 \cdot 3} + \frac{9}{9} + \frac{2}{1}$

Step 1.4.1.2.2.7

Multiply $\frac{2}{1}$ by $\frac{9}{9}$ .

$- \frac{1}{9} - \frac{3}{3 \cdot 3} + \frac{9}{9} + \frac{2}{1} \cdot \frac{9}{9}$

Step 1.4.1.2.2.8

Multiply $\frac{2}{1}$ by $\frac{9}{9}$ .

$- \frac{1}{9} - \frac{3}{3 \cdot 3} + \frac{9}{9} + \frac{2 \cdot 9}{9}$

Step 1.4.1.2.2.9

Multiply $3$ by $3$ .

$- \frac{1}{9} - \frac{3}{9} + \frac{9}{9} + \frac{2 \cdot 9}{9}$

Step 1.4.1.2.3

Combine the numerators over the common denominator.

$\frac{- 1 - 3 + 9 + 2 \cdot 9}{9}$

Step 1.4.1.2.4

Simplify the expression.

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Step 1.4.1.2.4.1

Multiply $2$ by $9$ .

$\frac{- 1 - 3 + 9 + 18}{9}$

Step 1.4.1.2.4.2

Subtract $3$ from $- 1$ .

$\frac{- 4 + 9 + 18}{9}$

Step 1.4.1.2.4.3

Add $- 4$ and $9$ .

$\frac{5 + 18}{9}$

Step 1.4.1.2.4.4

Add $5$ and $18$ .

$\frac{23}{9}$

Step 1.4.2

Evaluate at $x = 1$ .

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Step 1.4.2.1

Substitute $1$ for $x$ .

$3 {(1)}^{3} - 3 {(1)}^{2} - 3 \cdot 1 + 2$

Step 1.4.2.2

Simplify.

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Step 1.4.2.2.1

Simplify each term.

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Step 1.4.2.2.1.1

One to any power is one.

$3 \cdot 1 - 3 {(1)}^{2} - 3 \cdot 1 + 2$

Step 1.4.2.2.1.2

Multiply $3$ by $1$ .

$3 - 3 {(1)}^{2} - 3 \cdot 1 + 2$

Step 1.4.2.2.1.3

One to any power is one.

$3 - 3 \cdot 1 - 3 \cdot 1 + 2$

Step 1.4.2.2.1.4

Multiply $- 3$ by $1$ .

$3 - 3 - 3 \cdot 1 + 2$

Step 1.4.2.2.1.5

Multiply $- 3$ by $1$ .

$3 - 3 - 3 + 2$

Step 1.4.2.2.2

Simplify by adding and subtracting.

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Step 1.4.2.2.2.1

Subtract $3$ from $3$ .

$0 - 3 + 2$

Step 1.4.2.2.2.2

Subtract $3$ from $0$ .

$- 3 + 2$

Step 1.4.2.2.2.3

Add $- 3$ and $2$ .

$- 1$

Step 1.4.3

List all of the points.

$(- \frac{1}{3}, \frac{23}{9}), (1, - 1)$

Step 2

Exclude the points that are not on the interval.

$(- \frac{1}{3}, \frac{23}{9})$

Step 3

Evaluate at the included endpoints.

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Step 3.1

Evaluate at $x = - 1$ .

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Step 3.1.1

Substitute $- 1$ for $x$ .

$3 {(- 1)}^{3} - 3 {(- 1)}^{2} - 3 \cdot - 1 + 2$

Step 3.1.2

Simplify.

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Step 3.1.2.1

Simplify each term.

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Step 3.1.2.1.1

Raise $- 1$ to the power of $3$ .

$3 \cdot - 1 - 3 {(- 1)}^{2} - 3 \cdot - 1 + 2$

Step 3.1.2.1.2

Multiply $3$ by $- 1$ .

$- 3 - 3 {(- 1)}^{2} - 3 \cdot - 1 + 2$

Step 3.1.2.1.3

Raise $- 1$ to the power of $2$ .

$- 3 - 3 \cdot 1 - 3 \cdot - 1 + 2$

Step 3.1.2.1.4

Multiply $- 3$ by $1$ .

$- 3 - 3 - 3 \cdot - 1 + 2$

Step 3.1.2.1.5

Multiply $- 3$ by $- 1$ .

$- 3 - 3 + 3 + 2$

Step 3.1.2.2

Simplify by adding and subtracting.

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Step 3.1.2.2.1

Subtract $3$ from $- 3$ .

$- 6 + 3 + 2$

Step 3.1.2.2.2

Add $- 6$ and $3$ .

$- 3 + 2$

Step 3.1.2.2.3

Add $- 3$ and $2$ .

$- 1$

Step 3.2

Evaluate at $x = 0$ .

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Step 3.2.1

Substitute $0$ for $x$ .

$3 {(0)}^{3} - 3 {(0)}^{2} - 3 \cdot 0 + 2$

Step 3.2.2

Simplify.

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Step 3.2.2.1

Simplify each term.

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Step 3.2.2.1.1

Raising $0$ to any positive power yields $0$ .

$3 \cdot 0 - 3 {(0)}^{2} - 3 \cdot 0 + 2$

Step 3.2.2.1.2

Multiply $3$ by $0$ .

$0 - 3 {(0)}^{2} - 3 \cdot 0 + 2$

Step 3.2.2.1.3

Raising $0$ to any positive power yields $0$ .

$0 - 3 \cdot 0 - 3 \cdot 0 + 2$

Step 3.2.2.1.4

Multiply $- 3$ by $0$ .

$0 + 0 - 3 \cdot 0 + 2$

Step 3.2.2.1.5

Multiply $- 3$ by $0$ .

$0 + 0 + 0 + 2$

Step 3.2.2.2

Simplify by adding numbers.

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Step 3.2.2.2.1

Add $0$ and $0$ .

$0 + 0 + 2$

Step 3.2.2.2.2

Add $0$ and $0$ .

$0 + 2$

Step 3.2.2.2.3

Add $0$ and $2$ .

$2$

Step 3.3

List all of the points.

$(- 1, - 1), (0, 2)$

Step 4

Compare the $f (x)$ values found for each value of $x$ in order to determine the absolute maximum and minimum over the given interval. The maximum will occur at the highest $f (x)$ value and the minimum will occur at the lowest $f (x)$ value.

Absolute Maximum: $(- \frac{1}{3}, \frac{23}{9})$

Absolute Minimum: $(- 1, - 1)$

Step 5