Calculus Examples

$lim_{x \to 3} \frac{x - 3}{\sqrt{x - 2} - \sqrt{4 - x}}$

Step 1

Apply L'Hospital's rule.

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Step 1.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 1.1.1

Take the limit of the numerator and the limit of the denominator.

$\frac{lim_{x \to 3} x - 3}{lim_{x \to 3} \sqrt{x - 2} - \sqrt{4 - x}}$

Step 1.1.2

Evaluate the limit of the numerator.

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Step 1.1.2.1

Evaluate the limit.

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Step 1.1.2.1.1

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $3$ .

$\frac{lim_{x \to 3} x - lim_{x \to 3} 3}{lim_{x \to 3} \sqrt{x - 2} - \sqrt{4 - x}}$

Step 1.1.2.1.2

Evaluate the limit of $3$ which is constant as $x$ approaches $3$ .

$\frac{lim_{x \to 3} x - 1 \cdot 3}{lim_{x \to 3} \sqrt{x - 2} - \sqrt{4 - x}}$

Step 1.1.2.2

Evaluate the limit of $x$ by plugging in $3$ for $x$ .

$\frac{3 - 1 \cdot 3}{lim_{x \to 3} \sqrt{x - 2} - \sqrt{4 - x}}$

Step 1.1.2.3

Simplify the answer.

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Step 1.1.2.3.1

Multiply $- 1$ by $3$ .

$\frac{3 - 3}{lim_{x \to 3} \sqrt{x - 2} - \sqrt{4 - x}}$

Step 1.1.2.3.2

Subtract $3$ from $3$ .

$\frac{0}{lim_{x \to 3} \sqrt{x - 2} - \sqrt{4 - x}}$

Step 1.1.3

Evaluate the limit of the denominator.

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Step 1.1.3.1

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $3$ .

$\frac{0}{lim_{x \to 3} \sqrt{x - 2} - lim_{x \to 3} \sqrt{4 - x}}$

Step 1.1.3.2

Move the limit under the radical sign.

$\frac{0}{\sqrt{lim_{x \to 3} x - 2} - lim_{x \to 3} \sqrt{4 - x}}$

Step 1.1.3.3

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $3$ .

$\frac{0}{\sqrt{lim_{x \to 3} x - lim_{x \to 3} 2} - lim_{x \to 3} \sqrt{4 - x}}$

Step 1.1.3.4

Evaluate the limit of $2$ which is constant as $x$ approaches $3$ .

$\frac{0}{\sqrt{lim_{x \to 3} x - 1 \cdot 2} - lim_{x \to 3} \sqrt{4 - x}}$

Step 1.1.3.5

Move the limit under the radical sign.

$\frac{0}{\sqrt{lim_{x \to 3} x - 1 \cdot 2} - \sqrt{lim_{x \to 3} 4 - x}}$

Step 1.1.3.6

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $3$ .

$\frac{0}{\sqrt{lim_{x \to 3} x - 1 \cdot 2} - \sqrt{lim_{x \to 3} 4 - lim_{x \to 3} x}}$

Step 1.1.3.7

Evaluate the limit of $4$ which is constant as $x$ approaches $3$ .

$\frac{0}{\sqrt{lim_{x \to 3} x - 1 \cdot 2} - \sqrt{4 - lim_{x \to 3} x}}$

Step 1.1.3.8

Evaluate the limits by plugging in $3$ for all occurrences of $x$ .

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Step 1.1.3.8.1

Evaluate the limit of $x$ by plugging in $3$ for $x$ .

$\frac{0}{\sqrt{3 - 1 \cdot 2} - \sqrt{4 - lim_{x \to 3} x}}$

Step 1.1.3.8.2

Evaluate the limit of $x$ by plugging in $3$ for $x$ .

$\frac{0}{\sqrt{3 - 1 \cdot 2} - \sqrt{4 - 3}}$

Step 1.1.3.9

Simplify the answer.

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Step 1.1.3.9.1

Simplify each term.

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Step 1.1.3.9.1.1

Multiply $- 1$ by $2$ .

$\frac{0}{\sqrt{3 - 2} - \sqrt{4 - 3}}$

Step 1.1.3.9.1.2

Subtract $2$ from $3$ .

$\frac{0}{\sqrt{1} - \sqrt{4 - 3}}$

Step 1.1.3.9.1.3

Any root of $1$ is $1$ .

$\frac{0}{1 - \sqrt{4 - 3}}$

Step 1.1.3.9.1.4

Subtract $3$ from $4$ .

$\frac{0}{1 - \sqrt{1}}$

Step 1.1.3.9.1.5

Any root of $1$ is $1$ .

$\frac{0}{1 - 1 \cdot 1}$

Step 1.1.3.9.1.6

Multiply $- 1$ by $1$ .

$\frac{0}{1 - 1}$

Step 1.1.3.9.2

Subtract $1$ from $1$ .

$\frac{0}{0}$

Step 1.1.3.9.3

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 1.1.3.10

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 1.1.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 1.2

Since $\frac{0}{0}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to 3} \frac{x - 3}{\sqrt{x - 2} - \sqrt{4 - x}} = lim_{x \to 3} \frac{\frac{d}{d x} [x - 3]}{\frac{d}{d x} [\sqrt{x - 2} - \sqrt{4 - x}]}$

Step 1.3

Find the derivative of the numerator and denominator.

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Step 1.3.1

Differentiate the numerator and denominator.

$lim_{x \to 3} \frac{\frac{d}{d x} [x - 3]}{\frac{d}{d x} [\sqrt{x - 2} - \sqrt{4 - x}]}$

Step 1.3.2

By the Sum Rule, the derivative of $x - 3$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [- 3]$ .

$lim_{x \to 3} \frac{\frac{d}{d x} [x] + \frac{d}{d x} [- 3]}{\frac{d}{d x} [\sqrt{x - 2} - \sqrt{4 - x}]}$

Step 1.3.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$lim_{x \to 3} \frac{1 + \frac{d}{d x} [- 3]}{\frac{d}{d x} [\sqrt{x - 2} - \sqrt{4 - x}]}$

Step 1.3.4

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3$ with respect to $x$ is $0$ .

$lim_{x \to 3} \frac{1 + 0}{\frac{d}{d x} [\sqrt{x - 2} - \sqrt{4 - x}]}$

Step 1.3.5

Add $1$ and $0$ .

$lim_{x \to 3} \frac{1}{\frac{d}{d x} [\sqrt{x - 2} - \sqrt{4 - x}]}$

Step 1.3.6

By the Sum Rule, the derivative of $\sqrt{x - 2} - \sqrt{4 - x}$ with respect to $x$ is $\frac{d}{d x} [\sqrt{x - 2}] + \frac{d}{d x} [- \sqrt{4 - x}]$ .

$lim_{x \to 3} \frac{1}{\frac{d}{d x} [\sqrt{x - 2}] + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7

Evaluate $\frac{d}{d x} [\sqrt{x - 2}]$ .

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Step 1.3.7.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x - 2}$ as ${(x - 2)}^{\frac{1}{2}}$ .

$lim_{x \to 3} \frac{1}{\frac{d}{d x} [{(x - 2)}^{\frac{1}{2}}] + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = x - 2$ .

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Step 1.3.7.2.1

To apply the Chain Rule, set $u_{1}$ as $x - 2$ .

$lim_{x \to 3} \frac{1}{\frac{d}{d u_{1}} [{u_{1}}^{\frac{1}{2}}] \frac{d}{d x} [x - 2] + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = \frac{1}{2}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2} {u_{1}}^{\frac{1}{2} - 1} \frac{d}{d x} [x - 2] + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.2.3

Replace all occurrences of $u_{1}$ with $x - 2$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2} {(x - 2)}^{\frac{1}{2} - 1} \frac{d}{d x} [x - 2] + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.3

By the Sum Rule, the derivative of $x - 2$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [- 2]$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2} {(x - 2)}^{\frac{1}{2} - 1} (\frac{d}{d x} [x] + \frac{d}{d x} [- 2]) + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2} {(x - 2)}^{\frac{1}{2} - 1} (1 + \frac{d}{d x} [- 2]) + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.5

Since $- 2$ is constant with respect to $x$ , the derivative of $- 2$ with respect to $x$ is $0$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2} {(x - 2)}^{\frac{1}{2} - 1} (1 + 0) + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.6

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2} {(x - 2)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} (1 + 0) + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.7

Combine $- 1$ and $\frac{2}{2}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2} {(x - 2)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} (1 + 0) + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.8

Combine the numerators over the common denominator.

$lim_{x \to 3} \frac{1}{\frac{1}{2} {(x - 2)}^{\frac{1 - 1 \cdot 2}{2}} (1 + 0) + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.9

Simplify the numerator.

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Step 1.3.7.9.1

Multiply $- 1$ by $2$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2} {(x - 2)}^{\frac{1 - 2}{2}} (1 + 0) + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.9.2

Subtract $2$ from $1$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2} {(x - 2)}^{\frac{- 1}{2}} (1 + 0) + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.10

Move the negative in front of the fraction.

$lim_{x \to 3} \frac{1}{\frac{1}{2} {(x - 2)}^{- \frac{1}{2}} (1 + 0) + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.11

Add $1$ and $0$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2} {(x - 2)}^{- \frac{1}{2}} \cdot 1 + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.12

Combine $\frac{1}{2}$ and ${(x - 2)}^{- \frac{1}{2}}$ .

$lim_{x \to 3} \frac{1}{\frac{{(x - 2)}^{- \frac{1}{2}}}{2} \cdot 1 + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.13

Multiply $\frac{{(x - 2)}^{- \frac{1}{2}}}{2}$ by $1$ .

$lim_{x \to 3} \frac{1}{\frac{{(x - 2)}^{- \frac{1}{2}}}{2} + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.7.14

Move ${(x - 2)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} + \frac{d}{d x} [- \sqrt{4 - x}]}$

Step 1.3.8

Evaluate $\frac{d}{d x} [- \sqrt{4 - x}]$ .

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Step 1.3.8.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{4 - x}$ as ${(4 - x)}^{\frac{1}{2}}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} + \frac{d}{d x} [- {(4 - x)}^{\frac{1}{2}}]}$

Step 1.3.8.2

Since $- 1$ is constant with respect to $x$ , the derivative of $- {(4 - x)}^{\frac{1}{2}}$ with respect to $x$ is $- \frac{d}{d x} [{(4 - x)}^{\frac{1}{2}}]$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - \frac{d}{d x} [{(4 - x)}^{\frac{1}{2}}]}$

Step 1.3.8.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = 4 - x$ .

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Step 1.3.8.3.1

To apply the Chain Rule, set $u_{2}$ as $4 - x$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{d}{d u_{2}} [{u_{2}}^{\frac{1}{2}}] \frac{d}{d x} [4 - x])}$

Step 1.3.8.3.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = \frac{1}{2}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {u_{2}}^{\frac{1}{2} - 1} \frac{d}{d x} [4 - x])}$

Step 1.3.8.3.3

Replace all occurrences of $u_{2}$ with $4 - x$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{\frac{1}{2} - 1} \frac{d}{d x} [4 - x])}$

Step 1.3.8.4

By the Sum Rule, the derivative of $4 - x$ with respect to $x$ is $\frac{d}{d x} [4] + \frac{d}{d x} [- x]$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{\frac{1}{2} - 1} (\frac{d}{d x} [4] + \frac{d}{d x} [- x]))}$

Step 1.3.8.5

Since $4$ is constant with respect to $x$ , the derivative of $4$ with respect to $x$ is $0$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{\frac{1}{2} - 1} (0 + \frac{d}{d x} [- x]))}$

Step 1.3.8.6

Since $- 1$ is constant with respect to $x$ , the derivative of $- x$ with respect to $x$ is $- \frac{d}{d x} [x]$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{\frac{1}{2} - 1} (0 - \frac{d}{d x} [x]))}$

Step 1.3.8.7

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{\frac{1}{2} - 1} (0 - 1 \cdot 1))}$

Step 1.3.8.8

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} (0 - 1 \cdot 1))}$

Step 1.3.8.9

Combine $- 1$ and $\frac{2}{2}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} (0 - 1 \cdot 1))}$

Step 1.3.8.10

Combine the numerators over the common denominator.

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{\frac{1 - 1 \cdot 2}{2}} (0 - 1 \cdot 1))}$

Step 1.3.8.11

Simplify the numerator.

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Step 1.3.8.11.1

Multiply $- 1$ by $2$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{\frac{1 - 2}{2}} (0 - 1 \cdot 1))}$

Step 1.3.8.11.2

Subtract $2$ from $1$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{\frac{- 1}{2}} (0 - 1 \cdot 1))}$

Step 1.3.8.12

Move the negative in front of the fraction.

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{- \frac{1}{2}} (0 - 1 \cdot 1))}$

Step 1.3.8.13

Multiply $- 1$ by $1$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{- \frac{1}{2}} (0 - 1))}$

Step 1.3.8.14

Subtract $1$ from $0$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{1}{2} {(4 - x)}^{- \frac{1}{2}} \cdot - 1)}$

Step 1.3.8.15

Combine $\frac{1}{2}$ and ${(4 - x)}^{- \frac{1}{2}}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - (\frac{{(4 - x)}^{- \frac{1}{2}}}{2} \cdot - 1)}$

Step 1.3.8.16

Combine $\frac{{(4 - x)}^{- \frac{1}{2}}}{2}$ and $- 1$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - \frac{{(4 - x)}^{- \frac{1}{2}} \cdot - 1}{2}}$

Step 1.3.8.17

Move $- 1$ to the left of ${(4 - x)}^{- \frac{1}{2}}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - \frac{- 1 \cdot {(4 - x)}^{- \frac{1}{2}}}{2}}$

Step 1.3.8.18

Rewrite $- 1 {(4 - x)}^{- \frac{1}{2}}$ as $- {(4 - x)}^{- \frac{1}{2}}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - \frac{- {(4 - x)}^{- \frac{1}{2}}}{2}}$

Step 1.3.8.19

Move ${(4 - x)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - \frac{- 1}{2 {(4 - x)}^{\frac{1}{2}}}}$

Step 1.3.8.20

Move the negative in front of the fraction.

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} - - \frac{1}{2 {(4 - x)}^{\frac{1}{2}}}}$

Step 1.3.8.21

Multiply $- 1$ by $- 1$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} + 1 \frac{1}{2 {(4 - x)}^{\frac{1}{2}}}}$

Step 1.3.8.22

Multiply $\frac{1}{2 {(4 - x)}^{\frac{1}{2}}}$ by $1$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 {(x - 2)}^{\frac{1}{2}}} + \frac{1}{2 {(4 - x)}^{\frac{1}{2}}}}$

Step 1.4

Convert fractional exponents to radicals.

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Step 1.4.1

Rewrite ${(x - 2)}^{\frac{1}{2}}$ as $\sqrt{x - 2}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 \sqrt{x - 2}} + \frac{1}{2 {(4 - x)}^{\frac{1}{2}}}}$

Step 1.4.2

Rewrite ${(4 - x)}^{\frac{1}{2}}$ as $\sqrt{4 - x}$ .

$lim_{x \to 3} \frac{1}{\frac{1}{2 \sqrt{x - 2}} + \frac{1}{2 \sqrt{4 - x}}}$

Step 2

Evaluate the limit.

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Step 2.1

Split the limit using the Limits Quotient Rule on the limit as $x$ approaches $3$ .

$\frac{lim_{x \to 3} 1}{lim_{x \to 3} \frac{1}{2 \sqrt{x - 2}} + \frac{1}{2 \sqrt{4 - x}}}$

Step 2.2

Evaluate the limit of $1$ which is constant as $x$ approaches $3$ .

$\frac{1}{lim_{x \to 3} \frac{1}{2 \sqrt{x - 2}} + \frac{1}{2 \sqrt{4 - x}}}$

Step 2.3

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $3$ .

$\frac{1}{lim_{x \to 3} \frac{1}{2 \sqrt{x - 2}} + lim_{x \to 3} \frac{1}{2 \sqrt{4 - x}}}$

Step 2.4

Move the term $\frac{1}{2}$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{\frac{1}{2} lim_{x \to 3} \frac{1}{\sqrt{x - 2}} + lim_{x \to 3} \frac{1}{2 \sqrt{4 - x}}}$

Step 2.5

Split the limit using the Limits Quotient Rule on the limit as $x$ approaches $3$ .

$\frac{1}{\frac{1}{2} \cdot \frac{lim_{x \to 3} 1}{lim_{x \to 3} \sqrt{x - 2}} + lim_{x \to 3} \frac{1}{2 \sqrt{4 - x}}}$

Step 2.6

Evaluate the limit of $1$ which is constant as $x$ approaches $3$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{lim_{x \to 3} \sqrt{x - 2}} + lim_{x \to 3} \frac{1}{2 \sqrt{4 - x}}}$

Step 2.7

Move the limit under the radical sign.

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{lim_{x \to 3} x - 2}} + lim_{x \to 3} \frac{1}{2 \sqrt{4 - x}}}$

Step 2.8

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $3$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{lim_{x \to 3} x - lim_{x \to 3} 2}} + lim_{x \to 3} \frac{1}{2 \sqrt{4 - x}}}$

Step 2.9

Evaluate the limit of $2$ which is constant as $x$ approaches $3$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{lim_{x \to 3} x - 1 \cdot 2}} + lim_{x \to 3} \frac{1}{2 \sqrt{4 - x}}}$

Step 2.10

Move the term $\frac{1}{2}$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{lim_{x \to 3} x - 1 \cdot 2}} + \frac{1}{2} lim_{x \to 3} \frac{1}{\sqrt{4 - x}}}$

Step 2.11

Split the limit using the Limits Quotient Rule on the limit as $x$ approaches $3$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{lim_{x \to 3} x - 1 \cdot 2}} + \frac{1}{2} \cdot \frac{lim_{x \to 3} 1}{lim_{x \to 3} \sqrt{4 - x}}}$

Step 2.12

Evaluate the limit of $1$ which is constant as $x$ approaches $3$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{lim_{x \to 3} x - 1 \cdot 2}} + \frac{1}{2} \cdot \frac{1}{lim_{x \to 3} \sqrt{4 - x}}}$

Step 2.13

Move the limit under the radical sign.

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{lim_{x \to 3} x - 1 \cdot 2}} + \frac{1}{2} \cdot \frac{1}{\sqrt{lim_{x \to 3} 4 - x}}}$

Step 2.14

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $3$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{lim_{x \to 3} x - 1 \cdot 2}} + \frac{1}{2} \cdot \frac{1}{\sqrt{lim_{x \to 3} 4 - lim_{x \to 3} x}}}$

Step 2.15

Evaluate the limit of $4$ which is constant as $x$ approaches $3$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{lim_{x \to 3} x - 1 \cdot 2}} + \frac{1}{2} \cdot \frac{1}{\sqrt{4 - lim_{x \to 3} x}}}$

Step 3

Evaluate the limits by plugging in $3$ for all occurrences of $x$ .

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Step 3.1

Evaluate the limit of $x$ by plugging in $3$ for $x$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{3 - 1 \cdot 2}} + \frac{1}{2} \cdot \frac{1}{\sqrt{4 - lim_{x \to 3} x}}}$

Step 3.2

Evaluate the limit of $x$ by plugging in $3$ for $x$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{3 - 1 \cdot 2}} + \frac{1}{2} \cdot \frac{1}{\sqrt{4 - 3}}}$

Step 4

Simplify the answer.

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Step 4.1

Simplify the denominator.

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Step 4.1.1

Multiply $- 1$ by $2$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{3 - 2}} + \frac{1}{2} \cdot \frac{1}{\sqrt{4 - 3}}}$

Step 4.1.2

Subtract $2$ from $3$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{\sqrt{1}} + \frac{1}{2} \cdot \frac{1}{\sqrt{4 - 3}}}$

Step 4.1.3

Any root of $1$ is $1$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{1} + \frac{1}{2} \cdot \frac{1}{\sqrt{4 - 3}}}$

Step 4.2

Simplify the denominator.

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Step 4.2.1

Subtract $3$ from $4$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{1} + \frac{1}{2} \cdot \frac{1}{\sqrt{1}}}$

Step 4.2.2

Any root of $1$ is $1$ .

$\frac{1}{\frac{1}{2} \cdot \frac{1}{1} + \frac{1}{2} \cdot \frac{1}{1}}$

Step 4.3

Simplify the denominator.

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Step 4.3.1

Cancel the common factor of $1$ .

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Step 4.3.1.1

Cancel the common factor.

$\frac{1}{\frac{1}{2} \cdot \frac{1}{1} + \frac{1}{2} \cdot \frac{1}{1}}$

Step 4.3.1.2

Rewrite the expression.

$\frac{1}{\frac{1}{2} \cdot 1 + \frac{1}{2} \cdot \frac{1}{1}}$

Step 4.3.2

Multiply $\frac{1}{2}$ by $1$ .

$\frac{1}{\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{1}}$

Step 4.3.3

Cancel the common factor of $1$ .

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Step 4.3.3.1

Cancel the common factor.

$\frac{1}{\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{1}}$

Step 4.3.3.2

Rewrite the expression.

$\frac{1}{\frac{1}{2} + \frac{1}{2} \cdot 1}$

Step 4.3.4

Multiply $\frac{1}{2}$ by $1$ .

$\frac{1}{\frac{1}{2} + \frac{1}{2}}$

Step 4.3.5

Combine the numerators over the common denominator.

$\frac{1}{\frac{1 + 1}{2}}$

Step 4.3.6

Add $1$ and $1$ .

$\frac{1}{\frac{2}{2}}$

Step 4.3.7

Divide $2$ by $2$ .

$\frac{1}{1}$

Step 4.4

Divide $1$ by $1$ .

$1$