Calculus Examples

$\frac{8 + e^{t}}{3 t^{4} - t}$

Step 1

Differentiate using the Quotient Rule which states that $\frac{d}{d t} [\frac{f (t)}{g (t)}]$ is $\frac{g (t) \frac{d}{d t} [f (t)] - f (t) \frac{d}{d t} [g (t)]}{{g (t)}^{2}}$ where $f (t) = 8 + e^{t}$ and $g (t) = 3 t^{4} - t$ .

$\frac{(3 t^{4} - t) \frac{d}{d t} [8 + e^{t}] - (8 + e^{t}) \frac{d}{d t} [3 t^{4} - t]}{{(3 t^{4} - t)}^{2}}$

Step 2

Differentiate.

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Step 2.1

By the Sum Rule, the derivative of $8 + e^{t}$ with respect to $t$ is $\frac{d}{d t} [8] + \frac{d}{d t} [e^{t}]$ .

$\frac{(3 t^{4} - t) (\frac{d}{d t} [8] + \frac{d}{d t} [e^{t}]) - (8 + e^{t}) \frac{d}{d t} [3 t^{4} - t]}{{(3 t^{4} - t)}^{2}}$

Step 2.2

Since $8$ is constant with respect to $t$ , the derivative of $8$ with respect to $t$ is $0$ .

$\frac{(3 t^{4} - t) (0 + \frac{d}{d t} [e^{t}]) - (8 + e^{t}) \frac{d}{d t} [3 t^{4} - t]}{{(3 t^{4} - t)}^{2}}$

Step 2.3

Add $0$ and $\frac{d}{d t} [e^{t}]$ .

$\frac{(3 t^{4} - t) \frac{d}{d t} [e^{t}] - (8 + e^{t}) \frac{d}{d t} [3 t^{4} - t]}{{(3 t^{4} - t)}^{2}}$

Step 3

Differentiate using the Exponential Rule which states that $\frac{d}{d t} [a^{t}]$ is $a^{t} \ln (a)$ where $a$ = $e$ .

$\frac{(3 t^{4} - t) e^{t} - (8 + e^{t}) \frac{d}{d t} [3 t^{4} - t]}{{(3 t^{4} - t)}^{2}}$

Step 4

Differentiate.

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Step 4.1

By the Sum Rule, the derivative of $3 t^{4} - t$ with respect to $t$ is $\frac{d}{d t} [3 t^{4}] + \frac{d}{d t} [- t]$ .

$\frac{(3 t^{4} - t) e^{t} - (8 + e^{t}) (\frac{d}{d t} [3 t^{4}] + \frac{d}{d t} [- t])}{{(3 t^{4} - t)}^{2}}$

Step 4.2

Since $3$ is constant with respect to $t$ , the derivative of $3 t^{4}$ with respect to $t$ is $3 \frac{d}{d t} [t^{4}]$ .

$\frac{(3 t^{4} - t) e^{t} - (8 + e^{t}) (3 \frac{d}{d t} [t^{4}] + \frac{d}{d t} [- t])}{{(3 t^{4} - t)}^{2}}$

Step 4.3

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 4$ .

$\frac{(3 t^{4} - t) e^{t} - (8 + e^{t}) (3 (4 t^{3}) + \frac{d}{d t} [- t])}{{(3 t^{4} - t)}^{2}}$

Step 4.4

Multiply $4$ by $3$ .

$\frac{(3 t^{4} - t) e^{t} - (8 + e^{t}) (12 t^{3} + \frac{d}{d t} [- t])}{{(3 t^{4} - t)}^{2}}$

Step 4.5

Since $- 1$ is constant with respect to $t$ , the derivative of $- t$ with respect to $t$ is $- \frac{d}{d t} [t]$ .

$\frac{(3 t^{4} - t) e^{t} - (8 + e^{t}) (12 t^{3} - \frac{d}{d t} [t])}{{(3 t^{4} - t)}^{2}}$

Step 4.6

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 1$ .

$\frac{(3 t^{4} - t) e^{t} - (8 + e^{t}) (12 t^{3} - 1 \cdot 1)}{{(3 t^{4} - t)}^{2}}$

Step 4.7

Multiply $- 1$ by $1$ .

$\frac{(3 t^{4} - t) e^{t} - (8 + e^{t}) (12 t^{3} - 1)}{{(3 t^{4} - t)}^{2}}$

Step 5

Simplify.

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Step 5.1

Apply the distributive property.

$\frac{3 t^{4} e^{t} - t e^{t} - (8 + e^{t}) (12 t^{3} - 1)}{{(3 t^{4} - t)}^{2}}$

Step 5.2

Apply the distributive property.

$\frac{3 t^{4} e^{t} - t e^{t} + (- 1 \cdot 8 - e^{t}) (12 t^{3} - 1)}{{(3 t^{4} - t)}^{2}}$

Step 5.3

Simplify the numerator.

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Step 5.3.1

Simplify each term.

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Step 5.3.1.1

Multiply $- 1$ by $8$ .

$\frac{3 t^{4} e^{t} - t e^{t} + (- 8 - e^{t}) (12 t^{3} - 1)}{{(3 t^{4} - t)}^{2}}$

Step 5.3.1.2

Expand $(- 8 - e^{t}) (12 t^{3} - 1)$ using the FOIL Method.

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Step 5.3.1.2.1

Apply the distributive property.

$\frac{3 t^{4} e^{t} - t e^{t} - 8 (12 t^{3} - 1) - e^{t} (12 t^{3} - 1)}{{(3 t^{4} - t)}^{2}}$

Step 5.3.1.2.2

Apply the distributive property.

$\frac{3 t^{4} e^{t} - t e^{t} - 8 (12 t^{3}) - 8 \cdot - 1 - e^{t} (12 t^{3} - 1)}{{(3 t^{4} - t)}^{2}}$

Step 5.3.1.2.3

Apply the distributive property.

$\frac{3 t^{4} e^{t} - t e^{t} - 8 (12 t^{3}) - 8 \cdot - 1 - e^{t} (12 t^{3}) - e^{t} \cdot - 1}{{(3 t^{4} - t)}^{2}}$

Step 5.3.1.3

Simplify each term.

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Step 5.3.1.3.1

Multiply $12$ by $- 8$ .

$\frac{3 t^{4} e^{t} - t e^{t} - 96 t^{3} - 8 \cdot - 1 - e^{t} (12 t^{3}) - e^{t} \cdot - 1}{{(3 t^{4} - t)}^{2}}$

Step 5.3.1.3.2

Multiply $- 8$ by $- 1$ .

$\frac{3 t^{4} e^{t} - t e^{t} - 96 t^{3} + 8 - e^{t} (12 t^{3}) - e^{t} \cdot - 1}{{(3 t^{4} - t)}^{2}}$

Step 5.3.1.3.3

Rewrite using the commutative property of multiplication.

$\frac{3 t^{4} e^{t} - t e^{t} - 96 t^{3} + 8 - 1 \cdot 12 e^{t} t^{3} - e^{t} \cdot - 1}{{(3 t^{4} - t)}^{2}}$

Step 5.3.1.3.4

Multiply $- 1$ by $12$ .

$\frac{3 t^{4} e^{t} - t e^{t} - 96 t^{3} + 8 - 12 e^{t} t^{3} - e^{t} \cdot - 1}{{(3 t^{4} - t)}^{2}}$

Step 5.3.1.3.5

Multiply $- e^{t} \cdot - 1$ .

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Step 5.3.1.3.5.1

Multiply $- 1$ by $- 1$ .

$\frac{3 t^{4} e^{t} - t e^{t} - 96 t^{3} + 8 - 12 e^{t} t^{3} + 1 e^{t}}{{(3 t^{4} - t)}^{2}}$

Step 5.3.1.3.5.2

Multiply $e^{t}$ by $1$ .

$\frac{3 t^{4} e^{t} - t e^{t} - 96 t^{3} + 8 - 12 e^{t} t^{3} + e^{t}}{{(3 t^{4} - t)}^{2}}$

Step 5.3.2

Reorder factors in $3 t^{4} e^{t} - t e^{t} - 96 t^{3} + 8 - 12 e^{t} t^{3} + e^{t}$ .

$\frac{3 t^{4} e^{t} - t e^{t} - 96 t^{3} + 8 - 12 t^{3} e^{t} + e^{t}}{{(3 t^{4} - t)}^{2}}$

Step 5.4

Reorder terms.

$\frac{- 96 t^{3} + 3 e^{t} t^{4} - e^{t} t - 12 e^{t} t^{3} + 8 + e^{t}}{{(3 t^{4} - t)}^{2}}$