Calculus Examples

$y = \frac{\sec (x)}{1 + \sec (x)}$

Step 1

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = \sec (x)$ and $g (x) = 1 + \sec (x)$ .

$\frac{(1 + \sec (x)) \frac{d}{d x} [\sec (x)] - \sec (x) \frac{d}{d x} [1 + \sec (x)]}{{(1 + \sec (x))}^{2}}$

Step 2

The derivative of $\sec (x)$ with respect to $x$ is $\sec (x) \tan (x)$ .

$\frac{(1 + \sec (x)) (\sec (x) \tan (x)) - \sec (x) \frac{d}{d x} [1 + \sec (x)]}{{(1 + \sec (x))}^{2}}$

Step 3

Differentiate.

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Step 3.1

By the Sum Rule, the derivative of $1 + \sec (x)$ with respect to $x$ is $\frac{d}{d x} [1] + \frac{d}{d x} [\sec (x)]$ .

$\frac{(1 + \sec (x)) (\sec (x) \tan (x)) - \sec (x) (\frac{d}{d x} [1] + \frac{d}{d x} [\sec (x)])}{{(1 + \sec (x))}^{2}}$

Step 3.2

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$\frac{(1 + \sec (x)) (\sec (x) \tan (x)) - \sec (x) (0 + \frac{d}{d x} [\sec (x)])}{{(1 + \sec (x))}^{2}}$

Step 4

The derivative of $\sec (x)$ with respect to $x$ is $\sec (x) \tan (x)$ .

$\frac{(1 + \sec (x)) (\sec (x) \tan (x)) - \sec (x) (0 + \sec (x) \tan (x))}{{(1 + \sec (x))}^{2}}$

Step 5

Add $0$ and $\sec (x) \tan (x)$ .

$\frac{(1 + \sec (x)) (\sec (x) \tan (x)) - \sec (x) (\sec (x) \tan (x))}{{(1 + \sec (x))}^{2}}$

Step 6

Simplify.

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Step 6.1

Apply the distributive property.

$\frac{1 (\sec (x) \tan (x)) + \sec (x) (\sec (x) \tan (x)) - \sec (x) (\sec (x) \tan (x))}{{(1 + \sec (x))}^{2}}$

Step 6.2

Simplify the numerator.

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Step 6.2.1

Combine the opposite terms in $1 (\sec (x) \tan (x)) + \sec (x) (\sec (x) \tan (x)) - \sec (x) (\sec (x) \tan (x))$ .

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Step 6.2.1.1

Subtract $\sec (x) (\sec (x) \tan (x))$ from $\sec (x) (\sec (x) \tan (x))$ .

$\frac{1 (\sec (x) \tan (x)) + 0}{{(1 + \sec (x))}^{2}}$

Step 6.2.1.2

Add $1 (\sec (x) \tan (x))$ and $0$ .

$\frac{1 (\sec (x) \tan (x))}{{(1 + \sec (x))}^{2}}$

Step 6.2.2

Multiply $\sec (x) \tan (x)$ by $1$ .

$\frac{\sec (x) \tan (x)}{{(1 + \sec (x))}^{2}}$