Calculus Examples

$1 - \sin (x)$

Step 1

By the Sum Rule, the derivative of $1 - \sin (x)$ with respect to $Z$ is $\frac{d}{d Z} [1] + \frac{d}{d Z} [- \sin (x)]$ .

$\frac{d}{d Z} [1] + \frac{d}{d Z} [- \sin (x)]$

Step 2

Since $1$ is constant with respect to $Z$ , the derivative of $1$ with respect to $Z$ is $0$ .

$0 + \frac{d}{d Z} [- \sin (x)]$

Step 3

Since $- \sin (x)$ is constant with respect to $Z$ , the derivative of $- \sin (x)$ with respect to $Z$ is $0$ .

$0 + 0$

Step 4

Add $0$ and $0$ .

$0$