Calculus Examples

$y = x^{2} e^{5 x}$

Step 1

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{2}$ and $g (x) = e^{5 x}$ .

$x^{2} \frac{d}{d x} [e^{5 x}] + e^{5 x} \frac{d}{d x} [x^{2}]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = 5 x$ .

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Step 2.1

To apply the Chain Rule, set $u$ as $5 x$ .

$x^{2} (\frac{d}{d u} [e^{u}] \frac{d}{d x} [5 x]) + e^{5 x} \frac{d}{d x} [x^{2}]$

Step 2.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u} [a^{u}]$ is $a^{u} \ln (a)$ where $a$ = $e$ .

$x^{2} (e^{u} \frac{d}{d x} [5 x]) + e^{5 x} \frac{d}{d x} [x^{2}]$

Step 2.3

Replace all occurrences of $u$ with $5 x$ .

$x^{2} (e^{5 x} \frac{d}{d x} [5 x]) + e^{5 x} \frac{d}{d x} [x^{2}]$

Step 3

Differentiate.

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Step 3.1

Since $5$ is constant with respect to $x$ , the derivative of $5 x$ with respect to $x$ is $5 \frac{d}{d x} [x]$ .

$x^{2} (e^{5 x} (5 \frac{d}{d x} [x])) + e^{5 x} \frac{d}{d x} [x^{2}]$

Step 3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$x^{2} (e^{5 x} (5 \cdot 1)) + e^{5 x} \frac{d}{d x} [x^{2}]$

Step 3.3

Simplify the expression.

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Step 3.3.1

Multiply $5$ by $1$ .

$x^{2} (e^{5 x} \cdot 5) + e^{5 x} \frac{d}{d x} [x^{2}]$

Step 3.3.2

Move $5$ to the left of $e^{5 x}$ .

$x^{2} (5 \cdot e^{5 x}) + e^{5 x} \frac{d}{d x} [x^{2}]$

Step 3.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$x^{2} (5 e^{5 x}) + e^{5 x} (2 x)$

Step 4

Simplify.

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Step 4.1

Reorder terms.

$5 e^{5 x} x^{2} + 2 e^{5 x} x$

Step 4.2

Reorder factors in $5 e^{5 x} x^{2} + 2 e^{5 x} x$ .

$5 x^{2} e^{5 x} + 2 x e^{5 x}$