Calculus Examples

$y = 5^{x^{3} + \cos (2 x)}$

Step 1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = 5^{x}$ and $g (x) = x^{3} + \cos (2 x)$ .

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Step 1.1

To apply the Chain Rule, set $u_{1}$ as $x^{3} + \cos (2 x)$ .

$\frac{d}{d u_{1}} [5^{u_{1}}] \frac{d}{d x} [x^{3} + \cos (2 x)]$

Step 1.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{1}} [a^{u_{1}}]$ is $a^{u_{1}} \ln (a)$ where $a$ = $5$ .

$5^{u_{1}} \ln (5) \frac{d}{d x} [x^{3} + \cos (2 x)]$

Step 1.3

Replace all occurrences of $u_{1}$ with $x^{3} + \cos (2 x)$ .

$5^{x^{3} + \cos (2 x)} \ln (5) \frac{d}{d x} [x^{3} + \cos (2 x)]$

Step 2

Differentiate.

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Step 2.1

By the Sum Rule, the derivative of $x^{3} + \cos (2 x)$ with respect to $x$ is $\frac{d}{d x} [x^{3}] + \frac{d}{d x} [\cos (2 x)]$ .

$5^{x^{3} + \cos (2 x)} \ln (5) (\frac{d}{d x} [x^{3}] + \frac{d}{d x} [\cos (2 x)])$

Step 2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$5^{x^{3} + \cos (2 x)} \ln (5) (3 x^{2} + \frac{d}{d x} [\cos (2 x)])$

Step 3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \cos (x)$ and $g (x) = 2 x$ .

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Step 3.1

To apply the Chain Rule, set $u_{2}$ as $2 x$ .

$5^{x^{3} + \cos (2 x)} \ln (5) (3 x^{2} + \frac{d}{d u_{2}} [\cos (u_{2})] \frac{d}{d x} [2 x])$

Step 3.2

The derivative of $\cos (u_{2})$ with respect to $u_{2}$ is $- \sin (u_{2})$ .

$5^{x^{3} + \cos (2 x)} \ln (5) (3 x^{2} - \sin (u_{2}) \frac{d}{d x} [2 x])$

Step 3.3

Replace all occurrences of $u_{2}$ with $2 x$ .

$5^{x^{3} + \cos (2 x)} \ln (5) (3 x^{2} - \sin (2 x) \frac{d}{d x} [2 x])$

Step 4

Differentiate.

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Step 4.1

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$5^{x^{3} + \cos (2 x)} \ln (5) (3 x^{2} - \sin (2 x) (2 \frac{d}{d x} [x]))$

Step 4.2

Multiply $2$ by $- 1$ .

$5^{x^{3} + \cos (2 x)} \ln (5) (3 x^{2} - 2 \sin (2 x) \frac{d}{d x} [x])$

Step 4.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$5^{x^{3} + \cos (2 x)} \ln (5) (3 x^{2} - 2 \sin (2 x) \cdot 1)$

Step 4.4

Simplify the expression.

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Step 4.4.1

Multiply $- 2$ by $1$ .

$5^{x^{3} + \cos (2 x)} \ln (5) (3 x^{2} - 2 \sin (2 x))$

Step 4.4.2

Reorder the factors of $5^{x^{3} + \cos (2 x)} \ln (5) (3 x^{2} - 2 \sin (2 x))$ .

$5^{x^{3} + \cos (2 x)} (3 x^{2} - 2 \sin (2 x)) \ln (5)$