Calculus Examples

$y = {(\csc (x) + \cot (x))}^{- 1}$

Step 1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{- 1}$ and $g (x) = \csc (x) + \cot (x)$ .

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Step 1.1

To apply the Chain Rule, set $u$ as $\csc (x) + \cot (x)$ .

$\frac{d}{d u} [u^{- 1}] \frac{d}{d x} [\csc (x) + \cot (x)]$

Step 1.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = - 1$ .

$- u^{- 2} \frac{d}{d x} [\csc (x) + \cot (x)]$

Step 1.3

Replace all occurrences of $u$ with $\csc (x) + \cot (x)$ .

$- {(\csc (x) + \cot (x))}^{- 2} \frac{d}{d x} [\csc (x) + \cot (x)]$

Step 2

By the Sum Rule, the derivative of $\csc (x) + \cot (x)$ with respect to $x$ is $\frac{d}{d x} [\csc (x)] + \frac{d}{d x} [\cot (x)]$ .

$- {(\csc (x) + \cot (x))}^{- 2} (\frac{d}{d x} [\csc (x)] + \frac{d}{d x} [\cot (x)])$

Step 3

The derivative of $\csc (x)$ with respect to $x$ is $- \csc (x) \cot (x)$ .

$- {(\csc (x) + \cot (x))}^{- 2} (- \csc (x) \cot (x) + \frac{d}{d x} [\cot (x)])$

Step 4

The derivative of $\cot (x)$ with respect to $x$ is $- \csc^{2} (x)$ .

$- {(\csc (x) + \cot (x))}^{- 2} (- \csc (x) \cot (x) - \csc^{2} (x))$