Calculus Examples

$y = {(x + (x + {(\sin^{2} (x))}^{5}))}^{3}$

Step 1

Simplify by adding terms.

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Step 1.1

Multiply the exponents in ${(\sin^{2} (x))}^{5}$ .

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Step 1.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{d}{d x} [{(x + x + {\sin (x)}^{2 \cdot 5})}^{3}]$

Step 1.1.2

Multiply $2$ by $5$ .

$\frac{d}{d x} [{(x + x + \sin^{10} (x))}^{3}]$

Step 1.2

Add $x$ and $x$ .

$\frac{d}{d x} [{(2 x + \sin^{10} (x))}^{3}]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{3}$ and $g (x) = 2 x + \sin^{10} (x)$ .

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Step 2.1

To apply the Chain Rule, set $u_{1}$ as $2 x + \sin^{10} (x)$ .

$\frac{d}{d u_{1}} [{u_{1}}^{3}] \frac{d}{d x} [2 x + \sin^{10} (x)]$

Step 2.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 3$ .

$3 {u_{1}}^{2} \frac{d}{d x} [2 x + \sin^{10} (x)]$

Step 2.3

Replace all occurrences of $u_{1}$ with $2 x + \sin^{10} (x)$ .

$3 {(2 x + \sin^{10} (x))}^{2} \frac{d}{d x} [2 x + \sin^{10} (x)]$

Step 3

Differentiate.

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Step 3.1

By the Sum Rule, the derivative of $2 x + \sin^{10} (x)$ with respect to $x$ is $\frac{d}{d x} [2 x] + \frac{d}{d x} [\sin^{10} (x)]$ .

$3 {(2 x + \sin^{10} (x))}^{2} (\frac{d}{d x} [2 x] + \frac{d}{d x} [\sin^{10} (x)])$

Step 3.2

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$3 {(2 x + \sin^{10} (x))}^{2} (2 \frac{d}{d x} [x] + \frac{d}{d x} [\sin^{10} (x)])$

Step 3.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$3 {(2 x + \sin^{10} (x))}^{2} (2 \cdot 1 + \frac{d}{d x} [\sin^{10} (x)])$

Step 3.4

Multiply $2$ by $1$ .

$3 {(2 x + \sin^{10} (x))}^{2} (2 + \frac{d}{d x} [\sin^{10} (x)])$

Step 4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{10}$ and $g (x) = \sin (x)$ .

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Step 4.1

To apply the Chain Rule, set $u_{2}$ as $\sin (x)$ .

$3 {(2 x + \sin^{10} (x))}^{2} (2 + \frac{d}{d u_{2}} [{u_{2}}^{10}] \frac{d}{d x} [\sin (x)])$

Step 4.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = 10$ .

$3 {(2 x + \sin^{10} (x))}^{2} (2 + 10 {u_{2}}^{9} \frac{d}{d x} [\sin (x)])$

Step 4.3

Replace all occurrences of $u_{2}$ with $\sin (x)$ .

$3 {(2 x + \sin^{10} (x))}^{2} (2 + 10 \sin^{9} (x) \frac{d}{d x} [\sin (x)])$

Step 5

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$3 {(2 x + \sin^{10} (x))}^{2} (2 + 10 \sin^{9} (x) \cos (x))$