Calculus Examples

$g (x) = \frac{1 + 2 x}{3 - 4 x}$

Step 1

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = 1 + 2 x$ and $g (x) = 3 - 4 x$ .

$\frac{(3 - 4 x) \frac{d}{d x} [1 + 2 x] - (1 + 2 x) \frac{d}{d x} [3 - 4 x]}{{(3 - 4 x)}^{2}}$

Step 2

Differentiate.

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Step 2.1

By the Sum Rule, the derivative of $1 + 2 x$ with respect to $x$ is $\frac{d}{d x} [1] + \frac{d}{d x} [2 x]$ .

$\frac{(3 - 4 x) (\frac{d}{d x} [1] + \frac{d}{d x} [2 x]) - (1 + 2 x) \frac{d}{d x} [3 - 4 x]}{{(3 - 4 x)}^{2}}$

Step 2.2

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$\frac{(3 - 4 x) (0 + \frac{d}{d x} [2 x]) - (1 + 2 x) \frac{d}{d x} [3 - 4 x]}{{(3 - 4 x)}^{2}}$

Step 2.3

Add $0$ and $\frac{d}{d x} [2 x]$ .

$\frac{(3 - 4 x) \frac{d}{d x} [2 x] - (1 + 2 x) \frac{d}{d x} [3 - 4 x]}{{(3 - 4 x)}^{2}}$

Step 2.4

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$\frac{(3 - 4 x) (2 \frac{d}{d x} [x]) - (1 + 2 x) \frac{d}{d x} [3 - 4 x]}{{(3 - 4 x)}^{2}}$

Step 2.5

Move $2$ to the left of $3 - 4 x$ .

$\frac{2 \cdot (3 - 4 x) \frac{d}{d x} [x] - (1 + 2 x) \frac{d}{d x} [3 - 4 x]}{{(3 - 4 x)}^{2}}$

Step 2.6

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{2 (3 - 4 x) \cdot 1 - (1 + 2 x) \frac{d}{d x} [3 - 4 x]}{{(3 - 4 x)}^{2}}$

Step 2.7

Multiply $2$ by $1$ .

$\frac{2 (3 - 4 x) - (1 + 2 x) \frac{d}{d x} [3 - 4 x]}{{(3 - 4 x)}^{2}}$

Step 2.8

By the Sum Rule, the derivative of $3 - 4 x$ with respect to $x$ is $\frac{d}{d x} [3] + \frac{d}{d x} [- 4 x]$ .

$\frac{2 (3 - 4 x) - (1 + 2 x) (\frac{d}{d x} [3] + \frac{d}{d x} [- 4 x])}{{(3 - 4 x)}^{2}}$

Step 2.9

Since $3$ is constant with respect to $x$ , the derivative of $3$ with respect to $x$ is $0$ .

$\frac{2 (3 - 4 x) - (1 + 2 x) (0 + \frac{d}{d x} [- 4 x])}{{(3 - 4 x)}^{2}}$

Step 2.10

Add $0$ and $\frac{d}{d x} [- 4 x]$ .

$\frac{2 (3 - 4 x) - (1 + 2 x) \frac{d}{d x} [- 4 x]}{{(3 - 4 x)}^{2}}$

Step 2.11

Since $- 4$ is constant with respect to $x$ , the derivative of $- 4 x$ with respect to $x$ is $- 4 \frac{d}{d x} [x]$ .

$\frac{2 (3 - 4 x) - (1 + 2 x) (- 4 \frac{d}{d x} [x])}{{(3 - 4 x)}^{2}}$

Step 2.12

Multiply $- 4$ by $- 1$ .

$\frac{2 (3 - 4 x) + 4 (1 + 2 x) \frac{d}{d x} [x]}{{(3 - 4 x)}^{2}}$

Step 2.13

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{2 (3 - 4 x) + 4 (1 + 2 x) \cdot 1}{{(3 - 4 x)}^{2}}$

Step 2.14

Multiply $4$ by $1$ .

$\frac{2 (3 - 4 x) + 4 (1 + 2 x)}{{(3 - 4 x)}^{2}}$

Step 3

Simplify.

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Step 3.1

Apply the distributive property.

$\frac{2 \cdot 3 + 2 (- 4 x) + 4 (1 + 2 x)}{{(3 - 4 x)}^{2}}$

Step 3.2

Apply the distributive property.

$\frac{2 \cdot 3 + 2 (- 4 x) + 4 \cdot 1 + 4 (2 x)}{{(3 - 4 x)}^{2}}$

Step 3.3

Simplify the numerator.

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Step 3.3.1

Simplify each term.

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Step 3.3.1.1

Multiply $2$ by $3$ .

$\frac{6 + 2 (- 4 x) + 4 \cdot 1 + 4 (2 x)}{{(3 - 4 x)}^{2}}$

Step 3.3.1.2

Multiply $- 4$ by $2$ .

$\frac{6 - 8 x + 4 \cdot 1 + 4 (2 x)}{{(3 - 4 x)}^{2}}$

Step 3.3.1.3

Multiply $4$ by $1$ .

$\frac{6 - 8 x + 4 + 4 (2 x)}{{(3 - 4 x)}^{2}}$

Step 3.3.1.4

Multiply $2$ by $4$ .

$\frac{6 - 8 x + 4 + 8 x}{{(3 - 4 x)}^{2}}$

Step 3.3.2

Combine the opposite terms in $6 - 8 x + 4 + 8 x$ .

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Step 3.3.2.1

Add $- 8 x$ and $8 x$ .

$\frac{6 + 0 + 4}{{(3 - 4 x)}^{2}}$

Step 3.3.2.2

Add $6$ and $0$ .

$\frac{6 + 4}{{(3 - 4 x)}^{2}}$

Step 3.3.3

Add $6$ and $4$ .

$\frac{10}{{(3 - 4 x)}^{2}}$

Step 3.4

Reorder terms.

$\frac{10}{{(- 4 x + 3)}^{2}}$