Calculus Examples

$f (x) = arcsec (8 x)$

Step 1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = arcsec (x)$ and $g (x) = 8 x$ .

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Step 1.1

To apply the Chain Rule, set $u$ as $8 x$ .

$\frac{d}{d u} [arcsec (u)] \frac{d}{d x} [8 x]$

Step 1.2

The derivative of $arcsec (u)$ with respect to $u$ is $\frac{1}{u \sqrt{u^{2} - 1}}$ .

$\frac{1}{u \sqrt{u^{2} - 1}} \frac{d}{d x} [8 x]$

Step 1.3

Replace all occurrences of $u$ with $8 x$ .

$\frac{1}{8 x \sqrt{{(8 x)}^{2} - 1}} \frac{d}{d x} [8 x]$

Step 2

Differentiate.

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Step 2.1

Factor $8$ out of $8 x$ .

$\frac{1}{8 x \sqrt{{(8 (x))}^{2} - 1}} \frac{d}{d x} [8 x]$

Step 2.2

Simplify the expression.

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Step 2.2.1

Apply the product rule to $8 (x)$ .

$\frac{1}{8 x \sqrt{8^{2} x^{2} - 1}} \frac{d}{d x} [8 x]$

Step 2.2.2

Raise $8$ to the power of $2$ .

$\frac{1}{8 x \sqrt{64 x^{2} - 1}} \frac{d}{d x} [8 x]$

Step 2.3

Since $8$ is constant with respect to $x$ , the derivative of $8 x$ with respect to $x$ is $8 \frac{d}{d x} [x]$ .

$\frac{1}{8 x \sqrt{64 x^{2} - 1}} (8 \frac{d}{d x} [x])$

Step 2.4

Simplify terms.

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Step 2.4.1

Combine $8$ and $\frac{1}{8 x \sqrt{64 x^{2} - 1}}$ .

$\frac{8}{8 x \sqrt{64 x^{2} - 1}} \frac{d}{d x} [x]$

Step 2.4.2

Cancel the common factor of $8$ .

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Step 2.4.2.1

Cancel the common factor.

$\frac{8}{8 x \sqrt{64 x^{2} - 1}} \frac{d}{d x} [x]$

Step 2.4.2.2

Rewrite the expression.

$\frac{1}{x \sqrt{64 x^{2} - 1}} \frac{d}{d x} [x]$

Step 2.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{1}{x \sqrt{64 x^{2} - 1}} \cdot 1$

Step 2.6

Multiply $\frac{1}{x \sqrt{64 x^{2} - 1}}$ by $1$ .

$\frac{1}{x \sqrt{64 x^{2} - 1}}$