Calculus Examples

$y = {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{4}$

Step 1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{4}$ and $g (x) = \frac{1}{x} - \arcsin (\frac{1}{x})$ .

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Step 1.1

To apply the Chain Rule, set $u_{1}$ as $\frac{1}{x} - \arcsin (\frac{1}{x})$ .

$\frac{d}{d u_{1}} [{u_{1}}^{4}] \frac{d}{d x} [\frac{1}{x} - \arcsin (\frac{1}{x})]$

Step 1.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 4$ .

$4 {u_{1}}^{3} \frac{d}{d x} [\frac{1}{x} - \arcsin (\frac{1}{x})]$

Step 1.3

Replace all occurrences of $u_{1}$ with $\frac{1}{x} - \arcsin (\frac{1}{x})$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} \frac{d}{d x} [\frac{1}{x} - \arcsin (\frac{1}{x})]$

Step 2

Differentiate.

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Step 2.1

By the Sum Rule, the derivative of $\frac{1}{x} - \arcsin (\frac{1}{x})$ with respect to $x$ is $\frac{d}{d x} [\frac{1}{x}] + \frac{d}{d x} [- \arcsin (\frac{1}{x})]$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (\frac{d}{d x} [\frac{1}{x}] + \frac{d}{d x} [- \arcsin (\frac{1}{x})])$

Step 2.2

Rewrite $\frac{1}{x}$ as $x^{- 1}$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (\frac{d}{d x} [x^{- 1}] + \frac{d}{d x} [- \arcsin (\frac{1}{x})])$

Step 2.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = - 1$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- x^{- 2} + \frac{d}{d x} [- \arcsin (\frac{1}{x})])$

Step 2.4

Since $- 1$ is constant with respect to $x$ , the derivative of $- \arcsin (\frac{1}{x})$ with respect to $x$ is $- \frac{d}{d x} [\arcsin (\frac{1}{x})]$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- x^{- 2} - \frac{d}{d x} [\arcsin (\frac{1}{x})])$

Step 3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \arcsin (x)$ and $g (x) = \frac{1}{x}$ .

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Step 3.1

To apply the Chain Rule, set $u_{2}$ as $\frac{1}{x}$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- x^{- 2} - (\frac{d}{d u_{2}} [\arcsin (u_{2})] \frac{d}{d x} [\frac{1}{x}]))$

Step 3.2

The derivative of $\arcsin (u_{2})$ with respect to $u_{2}$ is $\frac{1}{\sqrt{1 - {u_{2}}^{2}}}$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- x^{- 2} - (\frac{1}{\sqrt{1 - {u_{2}}^{2}}} \frac{d}{d x} [\frac{1}{x}]))$

Step 3.3

Replace all occurrences of $u_{2}$ with $\frac{1}{x}$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- x^{- 2} - (\frac{1}{\sqrt{1 - {(\frac{1}{x})}^{2}}} \frac{d}{d x} [\frac{1}{x}]))$

Step 4

Differentiate using the Power Rule.

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Step 4.1

Rewrite $\frac{1}{x}$ as $x^{- 1}$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- x^{- 2} - \frac{1}{\sqrt{1 - {(\frac{1}{x})}^{2}}} \frac{d}{d x} [x^{- 1}])$

Step 4.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = - 1$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- x^{- 2} - \frac{1}{\sqrt{1 - {(\frac{1}{x})}^{2}}} (- x^{- 2}))$

Step 4.3

Combine fractions.

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Step 4.3.1

Multiply $- 1$ by $- 1$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- x^{- 2} + 1 \frac{1}{\sqrt{1 - {(\frac{1}{x})}^{2}}} x^{- 2})$

Step 4.3.2

Multiply $\frac{1}{\sqrt{1 - {(\frac{1}{x})}^{2}}}$ by $1$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- x^{- 2} + \frac{1}{\sqrt{1 - {(\frac{1}{x})}^{2}}} x^{- 2})$

Step 4.3.3

Combine $\frac{1}{\sqrt{1 - {(\frac{1}{x})}^{2}}}$ and $x^{- 2}$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- x^{- 2} + \frac{x^{- 2}}{\sqrt{1 - {(\frac{1}{x})}^{2}}})$

Step 4.3.4

Move $x^{- 2}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- x^{- 2} + \frac{1}{\sqrt{1 - {(\frac{1}{x})}^{2}} x^{2}})$

Step 5

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- \frac{1}{x^{2}} + \frac{1}{\sqrt{1 - {(\frac{1}{x})}^{2}} x^{2}})$

Step 6

Simplify.

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Step 6.1

Apply the product rule to $\frac{1}{x}$ .

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- \frac{1}{x^{2}} + \frac{1}{\sqrt{1 - \frac{1^{2}}{x^{2}}} x^{2}})$

Step 6.2

One to any power is one.

$4 {(\frac{1}{x} - \arcsin (\frac{1}{x}))}^{3} (- \frac{1}{x^{2}} + \frac{1}{\sqrt{1 - \frac{1}{x^{2}}} x^{2}})$