Calculus Examples

$\sin (\arccos (3 x))$

Step 1

Simplify with factoring out.

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Step 1.1

Draw a triangle in the plane with vertices $(3 x, \sqrt{1^{2} - {(3 x)}^{2}})$ , $(3 x, 0)$ , and the origin. Then $\arccos (3 x)$ is the angle between the positive x-axis and the ray beginning at the origin and passing through $(3 x, \sqrt{1^{2} - {(3 x)}^{2}})$ . Therefore, $\sin (\arccos (3 x))$ is $\sqrt{1 - {(3 x)}^{2}}$ .

$\frac{d}{d x} [\sqrt{1 - {(3 x)}^{2}}]$

Step 1.2

Factor $3$ out of $3 x$ .

$\frac{d}{d x} [\sqrt{1 - {(3 (x))}^{2}}]$

Step 1.3

Simplify the expression.

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Step 1.3.1

Apply the product rule to $3 (x)$ .

$\frac{d}{d x} [\sqrt{1 - (3^{2} x^{2})}]$

Step 1.3.2

Raise $3$ to the power of $2$ .

$\frac{d}{d x} [\sqrt{1 - (9 x^{2})}]$

Step 1.3.3

Multiply $9$ by $- 1$ .

$\frac{d}{d x} [\sqrt{1 - 9 x^{2}}]$

Step 1.3.4

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{1 - 9 x^{2}}$ as ${(1 - 9 x^{2})}^{\frac{1}{2}}$ .

$\frac{d}{d x} [{(1 - 9 x^{2})}^{\frac{1}{2}}]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = 1 - 9 x^{2}$ .

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Step 2.1

To apply the Chain Rule, set $u$ as $1 - 9 x^{2}$ .

$\frac{d}{d u} [u^{\frac{1}{2}}] \frac{d}{d x} [1 - 9 x^{2}]$

Step 2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{2}$ .

$\frac{1}{2} u^{\frac{1}{2} - 1} \frac{d}{d x} [1 - 9 x^{2}]$

Step 2.3

Replace all occurrences of $u$ with $1 - 9 x^{2}$ .

$\frac{1}{2} {(1 - 9 x^{2})}^{\frac{1}{2} - 1} \frac{d}{d x} [1 - 9 x^{2}]$

Step 3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{1}{2} {(1 - 9 x^{2})}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [1 - 9 x^{2}]$

Step 4

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{1}{2} {(1 - 9 x^{2})}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [1 - 9 x^{2}]$

Step 5

Combine the numerators over the common denominator.

$\frac{1}{2} {(1 - 9 x^{2})}^{\frac{1 - 1 \cdot 2}{2}} \frac{d}{d x} [1 - 9 x^{2}]$

Step 6

Simplify the numerator.

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Step 6.1

Multiply $- 1$ by $2$ .

$\frac{1}{2} {(1 - 9 x^{2})}^{\frac{1 - 2}{2}} \frac{d}{d x} [1 - 9 x^{2}]$

Step 6.2

Subtract $2$ from $1$ .

$\frac{1}{2} {(1 - 9 x^{2})}^{\frac{- 1}{2}} \frac{d}{d x} [1 - 9 x^{2}]$

Step 7

Combine fractions.

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Step 7.1

Move the negative in front of the fraction.

$\frac{1}{2} {(1 - 9 x^{2})}^{- \frac{1}{2}} \frac{d}{d x} [1 - 9 x^{2}]$

Step 7.2

Combine $\frac{1}{2}$ and ${(1 - 9 x^{2})}^{- \frac{1}{2}}$ .

$\frac{{(1 - 9 x^{2})}^{- \frac{1}{2}}}{2} \frac{d}{d x} [1 - 9 x^{2}]$

Step 7.3

Move ${(1 - 9 x^{2})}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}} \frac{d}{d x} [1 - 9 x^{2}]$

Step 8

By the Sum Rule, the derivative of $1 - 9 x^{2}$ with respect to $x$ is $\frac{d}{d x} [1] + \frac{d}{d x} [- 9 x^{2}]$ .

$\frac{1}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}} (\frac{d}{d x} [1] + \frac{d}{d x} [- 9 x^{2}])$

Step 9

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$\frac{1}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}} (0 + \frac{d}{d x} [- 9 x^{2}])$

Step 10

Add $0$ and $\frac{d}{d x} [- 9 x^{2}]$ .

$\frac{1}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}} \frac{d}{d x} [- 9 x^{2}]$

Step 11

Since $- 9$ is constant with respect to $x$ , the derivative of $- 9 x^{2}$ with respect to $x$ is $- 9 \frac{d}{d x} [x^{2}]$ .

$\frac{1}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}} (- 9 \frac{d}{d x} [x^{2}])$

Step 12

Combine fractions.

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Step 12.1

Combine $- 9$ and $\frac{1}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}}$ .

$\frac{- 9}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}} \frac{d}{d x} [x^{2}]$

Step 12.2

Move the negative in front of the fraction.

$- \frac{9}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}} \frac{d}{d x} [x^{2}]$

Step 13

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$- \frac{9}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}} (2 x)$

Step 14

Simplify terms.

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Step 14.1

Multiply $2$ by $- 1$ .

$- 2 \frac{9}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}} x$

Step 14.2

Combine $- 2$ and $\frac{9}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}}$ .

$\frac{- 2 \cdot 9}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}} x$

Step 14.3

Multiply $- 2$ by $9$ .

$\frac{- 18}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}} x$

Step 14.4

Combine $\frac{- 18}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}}$ and $x$ .

$\frac{- 18 x}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}}$

Step 14.5

Factor $2$ out of $- 18 x$ .

$\frac{2 (- 9 x)}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}}$

Step 15

Cancel the common factors.

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Step 15.1

Factor $2$ out of $2 {(1 - 9 x^{2})}^{\frac{1}{2}}$ .

$\frac{2 (- 9 x)}{2 ({(1 - 9 x^{2})}^{\frac{1}{2}})}$

Step 15.2

Cancel the common factor.

$\frac{2 (- 9 x)}{2 {(1 - 9 x^{2})}^{\frac{1}{2}}}$

Step 15.3

Rewrite the expression.

$\frac{- 9 x}{{(1 - 9 x^{2})}^{\frac{1}{2}}}$

Step 16

Move the negative in front of the fraction.

$- \frac{9 x}{{(1 - 9 x^{2})}^{\frac{1}{2}}}$