Calculus Examples

$27 m^{6} + 64 n^{9}$

Step 1

Rewrite $27 m^{6}$ as ${(3 m^{2})}^{3}$ .

${(3 m^{2})}^{3} + 64 n^{9}$

Step 2

Rewrite $64 n^{9}$ as ${(4 n^{3})}^{3}$ .

${(3 m^{2})}^{3} + {(4 n^{3})}^{3}$

Step 3

Since both terms are perfect cubes, factor using the sum of cubes formula, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ where $a = 3 m^{2}$ and $b = 4 n^{3}$ .

$(3 m^{2} + 4 n^{3}) ({(3 m^{2})}^{2} - (3 m^{2}) (4 n^{3}) + {(4 n^{3})}^{2})$

Step 4

Simplify.

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Step 4.1

Apply the product rule to $3 m^{2}$ .

$(3 m^{2} + 4 n^{3}) (3^{2} {(m^{2})}^{2} - (3 m^{2}) (4 n^{3}) + {(4 n^{3})}^{2})$

Step 4.2

Raise $3$ to the power of $2$ .

$(3 m^{2} + 4 n^{3}) (9 {(m^{2})}^{2} - (3 m^{2}) (4 n^{3}) + {(4 n^{3})}^{2})$

Step 4.3

Multiply the exponents in ${(m^{2})}^{2}$ .

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Step 4.3.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$(3 m^{2} + 4 n^{3}) (9 m^{2 \cdot 2} - (3 m^{2}) (4 n^{3}) + {(4 n^{3})}^{2})$

Step 4.3.2

Multiply $2$ by $2$ .

$(3 m^{2} + 4 n^{3}) (9 m^{4} - (3 m^{2}) (4 n^{3}) + {(4 n^{3})}^{2})$

Step 4.4

Multiply $3$ by $- 1$ .

$(3 m^{2} + 4 n^{3}) (9 m^{4} - 3 m^{2} (4 n^{3}) + {(4 n^{3})}^{2})$

Step 4.5

Rewrite using the commutative property of multiplication.

$(3 m^{2} + 4 n^{3}) (9 m^{4} - 3 \cdot 4 m^{2} n^{3} + {(4 n^{3})}^{2})$

Step 4.6

Multiply $- 3$ by $4$ .

$(3 m^{2} + 4 n^{3}) (9 m^{4} - 12 m^{2} n^{3} + {(4 n^{3})}^{2})$

Step 4.7

Apply the product rule to $4 n^{3}$ .

$(3 m^{2} + 4 n^{3}) (9 m^{4} - 12 m^{2} n^{3} + 4^{2} {(n^{3})}^{2})$

Step 4.8

Raise $4$ to the power of $2$ .

$(3 m^{2} + 4 n^{3}) (9 m^{4} - 12 m^{2} n^{3} + 16 {(n^{3})}^{2})$

Step 4.9

Multiply the exponents in ${(n^{3})}^{2}$ .

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Step 4.9.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$(3 m^{2} + 4 n^{3}) (9 m^{4} - 12 m^{2} n^{3} + 16 n^{3 \cdot 2})$

Step 4.9.2

Multiply $3$ by $2$ .

$(3 m^{2} + 4 n^{3}) (9 m^{4} - 12 m^{2} n^{3} + 16 n^{6})$