Calculus Examples

$\arctan (x^{2} y) = x y^{2}$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (\arctan (x^{2} y)) = \frac{d}{d x} (x y^{2})$

Step 2

Differentiate the left side of the equation.

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Step 2.1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \arctan (x)$ and $g (x) = x^{2} y$ .

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Step 2.1.1

To apply the Chain Rule, set $u$ as $x^{2} y$ .

$\frac{d}{d u} [\arctan (u)] \frac{d}{d x} [x^{2} y]$

Step 2.1.2

The derivative of $\arctan (u)$ with respect to $u$ is $\frac{1}{1 + u^{2}}$ .

$\frac{1}{1 + u^{2}} \frac{d}{d x} [x^{2} y]$

Step 2.1.3

Replace all occurrences of $u$ with $x^{2} y$ .

$\frac{1}{1 + {(x^{2} y)}^{2}} \frac{d}{d x} [x^{2} y]$

Step 2.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{2}$ and $g (x) = y$ .

$\frac{1}{1 + {(x^{2} y)}^{2}} (x^{2} \frac{d}{d x} [y] + y \frac{d}{d x} [x^{2}])$

Step 2.3

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$\frac{1}{1 + {(x^{2} y)}^{2}} (x^{2} y' + y \frac{d}{d x} [x^{2}])$

Step 2.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{1}{1 + {(x^{2} y)}^{2}} (x^{2} y' + y (2 x))$

Step 2.5

Move $2$ to the left of $y$ .

$\frac{1}{1 + {(x^{2} y)}^{2}} (x^{2} y' + 2 \cdot y x)$

Step 2.6

Simplify.

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Step 2.6.1

Apply the product rule to $x^{2} y$ .

$\frac{1}{1 + {(x^{2})}^{2} y^{2}} (x^{2} y' + 2 y x)$

Step 2.6.2

Multiply the exponents in ${(x^{2})}^{2}$ .

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Step 2.6.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{1}{1 + x^{2 \cdot 2} y^{2}} (x^{2} y' + 2 y x)$

Step 2.6.2.2

Multiply $2$ by $2$ .

$\frac{1}{1 + x^{4} y^{2}} (x^{2} y' + 2 y x)$

Step 2.6.3

Reorder the factors of $\frac{1}{1 + x^{4} y^{2}} (x^{2} y' + 2 y x)$ .

$(x^{2} y' + 2 y x) \frac{1}{1 + x^{4} y^{2}}$

Step 2.6.4

Multiply $x^{2} y' + 2 y x$ by $\frac{1}{1 + x^{4} y^{2}}$ .

$\frac{x^{2} y' + 2 y x}{1 + x^{4} y^{2}}$

Step 2.6.5

Factor $x$ out of $x^{2} y' + 2 y x$ .

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Step 2.6.5.1

Factor $x$ out of $x^{2} y'$ .

$\frac{x (x y') + 2 y x}{1 + x^{4} y^{2}}$

Step 2.6.5.2

Factor $x$ out of $2 y x$ .

$\frac{x (x y') + x (2 y)}{1 + x^{4} y^{2}}$

Step 2.6.5.3

Factor $x$ out of $x (x y') + x (2 y)$ .

$\frac{x (x y' + 2 y)}{1 + x^{4} y^{2}}$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = y^{2}$ .

$x \frac{d}{d x} [y^{2}] + y^{2} \frac{d}{d x} [x]$

Step 3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = y$ .

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Step 3.2.1

To apply the Chain Rule, set $u$ as $y$ .

$x (\frac{d}{d u} [u^{2}] \frac{d}{d x} [y]) + y^{2} \frac{d}{d x} [x]$

Step 3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$x (2 u \frac{d}{d x} [y]) + y^{2} \frac{d}{d x} [x]$

Step 3.2.3

Replace all occurrences of $u$ with $y$ .

$x (2 y \frac{d}{d x} [y]) + y^{2} \frac{d}{d x} [x]$

Step 3.3

Move $2$ to the left of $x$ .

$2 \cdot x y \frac{d}{d x} [y] + y^{2} \frac{d}{d x} [x]$

Step 3.4

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$2 x y y' + y^{2} \frac{d}{d x} [x]$

Step 3.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 x y y' + y^{2} \cdot 1$

Step 3.6

Simplify the expression.

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Step 3.6.1

Multiply $y^{2}$ by $1$ .

$2 x y y' + y^{2}$

Step 3.6.2

Reorder terms.

$y^{2} + 2 x y y'$

Step 4

Reform the equation by setting the left side equal to the right side.

$\frac{x (x y' + 2 y)}{1 + x^{4} y^{2}} = y^{2} + 2 x y y'$

Step 5

Solve for $y'$ .

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Step 5.1

Multiply both sides by $1 + x^{4} y^{2}$ .

$\frac{x (x y' + 2 y)}{1 + x^{4} y^{2}} (1 + x^{4} y^{2}) = (y^{2} + 2 x y y') (1 + x^{4} y^{2})$

Step 5.2

Simplify.

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Step 5.2.1

Simplify the left side.

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Step 5.2.1.1

Simplify $\frac{x (x y' + 2 y)}{1 + x^{4} y^{2}} (1 + x^{4} y^{2})$ .

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Step 5.2.1.1.1

Cancel the common factor of $1 + x^{4} y^{2}$ .

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Step 5.2.1.1.1.1

Cancel the common factor.

$\frac{x (x y' + 2 y)}{1 + x^{4} y^{2}} (1 + x^{4} y^{2}) = (y^{2} + 2 x y y') (1 + x^{4} y^{2})$

Step 5.2.1.1.1.2

Rewrite the expression.

$x (x y' + 2 y) = (y^{2} + 2 x y y') (1 + x^{4} y^{2})$

Step 5.2.1.1.2

Apply the distributive property.

$x (x y') + x (2 y) = (y^{2} + 2 x y y') (1 + x^{4} y^{2})$

Step 5.2.1.1.3

Multiply $x$ by $x$ by adding the exponents.

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Step 5.2.1.1.3.1

Move $x$ .

$x \cdot x y' + x (2 y) = (y^{2} + 2 x y y') (1 + x^{4} y^{2})$

Step 5.2.1.1.3.2

Multiply $x$ by $x$ .

$x^{2} y' + x (2 y) = (y^{2} + 2 x y y') (1 + x^{4} y^{2})$

Step 5.2.1.1.4

Rewrite using the commutative property of multiplication.

$x^{2} y' + 2 x y = (y^{2} + 2 x y y') (1 + x^{4} y^{2})$

Step 5.2.1.1.5

Reorder $x^{2}$ and $y'$ .

$y' x^{2} + 2 x y = (y^{2} + 2 x y y') (1 + x^{4} y^{2})$

Step 5.2.2

Simplify the right side.

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Step 5.2.2.1

Simplify $(y^{2} + 2 x y y') (1 + x^{4} y^{2})$ .

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Step 5.2.2.1.1

Expand $(y^{2} + 2 x y y') (1 + x^{4} y^{2})$ using the FOIL Method.

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Step 5.2.2.1.1.1

Apply the distributive property.

$y' x^{2} + 2 x y = y^{2} (1 + x^{4} y^{2}) + 2 x y y' (1 + x^{4} y^{2})$

Step 5.2.2.1.1.2

Apply the distributive property.

$y' x^{2} + 2 x y = y^{2} \cdot 1 + y^{2} (x^{4} y^{2}) + 2 x y y' (1 + x^{4} y^{2})$

Step 5.2.2.1.1.3

Apply the distributive property.

$y' x^{2} + 2 x y = y^{2} \cdot 1 + y^{2} (x^{4} y^{2}) + 2 x y y' \cdot 1 + 2 x y y' (x^{4} y^{2})$

Step 5.2.2.1.2

Simplify terms.

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Step 5.2.2.1.2.1

Simplify each term.

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Step 5.2.2.1.2.1.1

Multiply $y^{2}$ by $1$ .

$y' x^{2} + 2 x y = y^{2} + y^{2} (x^{4} y^{2}) + 2 x y y' \cdot 1 + 2 x y y' (x^{4} y^{2})$

Step 5.2.2.1.2.1.2

Multiply $y^{2}$ by $y^{2}$ by adding the exponents.

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Step 5.2.2.1.2.1.2.1

Move $y^{2}$ .

$y' x^{2} + 2 x y = y^{2} + y^{2} y^{2} x^{4} + 2 x y y' \cdot 1 + 2 x y y' (x^{4} y^{2})$

Step 5.2.2.1.2.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y' x^{2} + 2 x y = y^{2} + y^{2 + 2} x^{4} + 2 x y y' \cdot 1 + 2 x y y' (x^{4} y^{2})$

Step 5.2.2.1.2.1.2.3

Add $2$ and $2$ .

$y' x^{2} + 2 x y = y^{2} + y^{4} x^{4} + 2 x y y' \cdot 1 + 2 x y y' (x^{4} y^{2})$

Step 5.2.2.1.2.1.3

Multiply $2$ by $1$ .

$y' x^{2} + 2 x y = y^{2} + y^{4} x^{4} + 2 x y y' + 2 x y y' (x^{4} y^{2})$

Step 5.2.2.1.2.1.4

Multiply $x$ by $x^{4}$ by adding the exponents.

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Step 5.2.2.1.2.1.4.1

Move $x^{4}$ .

$y' x^{2} + 2 x y = y^{2} + y^{4} x^{4} + 2 x y y' + 2 (x^{4} x) y y' y^{2}$

Step 5.2.2.1.2.1.4.2

Multiply $x^{4}$ by $x$ .

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Step 5.2.2.1.2.1.4.2.1

Raise $x$ to the power of $1$ .

$y' x^{2} + 2 x y = y^{2} + y^{4} x^{4} + 2 x y y' + 2 (x^{4} x^{1}) y y' y^{2}$

Step 5.2.2.1.2.1.4.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y' x^{2} + 2 x y = y^{2} + y^{4} x^{4} + 2 x y y' + 2 x^{4 + 1} y y' y^{2}$

Step 5.2.2.1.2.1.4.3

Add $4$ and $1$ .

$y' x^{2} + 2 x y = y^{2} + y^{4} x^{4} + 2 x y y' + 2 x^{5} y y' y^{2}$

Step 5.2.2.1.2.1.5

Multiply $y$ by $y^{2}$ by adding the exponents.

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Step 5.2.2.1.2.1.5.1

Move $y^{2}$ .

$y' x^{2} + 2 x y = y^{2} + y^{4} x^{4} + 2 x y y' + 2 x^{5} (y^{2} y) y'$

Step 5.2.2.1.2.1.5.2

Multiply $y^{2}$ by $y$ .

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Step 5.2.2.1.2.1.5.2.1

Raise $y$ to the power of $1$ .

$y' x^{2} + 2 x y = y^{2} + y^{4} x^{4} + 2 x y y' + 2 x^{5} (y^{2} y^{1}) y'$

Step 5.2.2.1.2.1.5.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y' x^{2} + 2 x y = y^{2} + y^{4} x^{4} + 2 x y y' + 2 x^{5} y^{2 + 1} y'$

Step 5.2.2.1.2.1.5.3

Add $2$ and $1$ .

$y' x^{2} + 2 x y = y^{2} + y^{4} x^{4} + 2 x y y' + 2 x^{5} y^{3} y'$

Step 5.2.2.1.2.2

Simplify the expression.

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Step 5.2.2.1.2.2.1

Reorder $y^{4}$ and $x^{4}$ .

$y' x^{2} + 2 x y = y^{2} + x^{4} y^{4} + 2 x y y' + 2 x^{5} y^{3} y'$

Step 5.2.2.1.2.2.2

Move $y$ .

$y' x^{2} + 2 x y = y^{2} + x^{4} y^{4} + 2 x y' y + 2 x^{5} y^{3} y'$

Step 5.2.2.1.2.2.3

Move $x$ .

$y' x^{2} + 2 x y = y^{2} + x^{4} y^{4} + 2 y' x y + 2 x^{5} y^{3} y'$

Step 5.2.2.1.2.2.4

Move $y^{3}$ .

$y' x^{2} + 2 x y = y^{2} + x^{4} y^{4} + 2 y' x y + 2 x^{5} y' y^{3}$

Step 5.2.2.1.2.2.5

Move $x^{5}$ .

$y' x^{2} + 2 x y = y^{2} + x^{4} y^{4} + 2 y' x y + 2 y' x^{5} y^{3}$

Step 5.2.2.1.2.2.6

Move $y^{2}$ .

$y' x^{2} + 2 x y = x^{4} y^{4} + 2 y' x y + 2 y' x^{5} y^{3} + y^{2}$

Step 5.2.2.1.2.2.7

Move $2 y' x y$ .

$y' x^{2} + 2 x y = x^{4} y^{4} + 2 y' x^{5} y^{3} + 2 y' x y + y^{2}$

Step 5.2.2.1.2.2.8

Reorder $x^{4} y^{4}$ and $2 y' x^{5} y^{3}$ .

$y' x^{2} + 2 x y = 2 y' x^{5} y^{3} + x^{4} y^{4} + 2 y' x y + y^{2}$

Step 5.3

Solve for $y'$ .

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Step 5.3.1

Since $y'$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$2 y' x^{5} y^{3} + x^{4} y^{4} + 2 y' x y + y^{2} = y' x^{2} + 2 x y$

Step 5.3.2

Subtract $y' x^{2}$ from both sides of the equation.

$2 y' x^{5} y^{3} + x^{4} y^{4} + 2 y' x y + y^{2} - y' x^{2} = 2 x y$

Step 5.3.3

Move all terms not containing $y'$ to the right side of the equation.

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Step 5.3.3.1

Subtract $x^{4} y^{4}$ from both sides of the equation.

$2 y' x^{5} y^{3} + 2 y' x y + y^{2} - y' x^{2} = 2 x y - x^{4} y^{4}$

Step 5.3.3.2

Subtract $y^{2}$ from both sides of the equation.

$2 y' x^{5} y^{3} + 2 y' x y - y' x^{2} = 2 x y - x^{4} y^{4} - y^{2}$

Step 5.3.4

Factor $y' x$ out of $2 y' x^{5} y^{3} + 2 y' x y - y' x^{2}$ .

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Step 5.3.4.1

Factor $y' x$ out of $2 y' x^{5} y^{3}$ .

$y' x (2 x^{4} y^{3}) + 2 y' x y - y' x^{2} = 2 x y - x^{4} y^{4} - y^{2}$

Step 5.3.4.2

Factor $y' x$ out of $2 y' x y$ .

$y' x (2 x^{4} y^{3}) + y' x (2 y) - y' x^{2} = 2 x y - x^{4} y^{4} - y^{2}$

Step 5.3.4.3

Factor $y' x$ out of $- y' x^{2}$ .

$y' x (2 x^{4} y^{3}) + y' x (2 y) + y' x (- 1 x) = 2 x y - x^{4} y^{4} - y^{2}$

Step 5.3.4.4

Factor $y' x$ out of $y' x (2 x^{4} y^{3}) + y' x (2 y)$ .

$y' x (2 x^{4} y^{3} + 2 y) + y' x (- 1 x) = 2 x y - x^{4} y^{4} - y^{2}$

Step 5.3.4.5

Factor $y' x$ out of $y' x (2 x^{4} y^{3} + 2 y) + y' x (- 1 x)$ .

$y' x (2 x^{4} y^{3} + 2 y - 1 x) = 2 x y - x^{4} y^{4} - y^{2}$

Step 5.3.5

Rewrite $- 1 x$ as $- x$ .

$y' x (2 x^{4} y^{3} + 2 y - x) = 2 x y - x^{4} y^{4} - y^{2}$

Step 5.3.6

Divide each term in $y' x (2 x^{4} y^{3} + 2 y - x) = 2 x y - x^{4} y^{4} - y^{2}$ by $x (2 x^{4} y^{3} + 2 y - x)$ and simplify.

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Step 5.3.6.1

Divide each term in $y' x (2 x^{4} y^{3} + 2 y - x) = 2 x y - x^{4} y^{4} - y^{2}$ by $x (2 x^{4} y^{3} + 2 y - x)$ .

$\frac{y' x (2 x^{4} y^{3} + 2 y - x)}{x (2 x^{4} y^{3} + 2 y - x)} = \frac{2 x y}{x (2 x^{4} y^{3} + 2 y - x)} + \frac{- x^{4} y^{4}}{x (2 x^{4} y^{3} + 2 y - x)} + \frac{- y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.2

Simplify the left side.

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Step 5.3.6.2.1

Cancel the common factor of $x$ .

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Step 5.3.6.2.1.1

Cancel the common factor.

Step 5.3.6.2.1.2

Rewrite the expression.

$\frac{y' (2 x^{4} y^{3} + 2 y - x)}{2 x^{4} y^{3} + 2 y - x} = \frac{2 x y}{x (2 x^{4} y^{3} + 2 y - x)} + \frac{- x^{4} y^{4}}{x (2 x^{4} y^{3} + 2 y - x)} + \frac{- y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.2.2

Cancel the common factor of $2 x^{4} y^{3} + 2 y - x$ .

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Step 5.3.6.2.2.1

Cancel the common factor.

Step 5.3.6.2.2.2

Divide $y'$ by $1$ .

$y' = \frac{2 x y}{x (2 x^{4} y^{3} + 2 y - x)} + \frac{- x^{4} y^{4}}{x (2 x^{4} y^{3} + 2 y - x)} + \frac{- y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3

Simplify the right side.

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Step 5.3.6.3.1

Simplify each term.

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Step 5.3.6.3.1.1

Cancel the common factor of $x$ .

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Step 5.3.6.3.1.1.1

Cancel the common factor.

$y' = \frac{2 x y}{x (2 x^{4} y^{3} + 2 y - x)} + \frac{- x^{4} y^{4}}{x (2 x^{4} y^{3} + 2 y - x)} + \frac{- y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.1.1.2

Rewrite the expression.

$y' = \frac{2 y}{2 x^{4} y^{3} + 2 y - x} + \frac{- x^{4} y^{4}}{x (2 x^{4} y^{3} + 2 y - x)} + \frac{- y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.1.2

Cancel the common factor of $x^{4}$ and $x$ .

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Step 5.3.6.3.1.2.1

Factor $x$ out of $- x^{4} y^{4}$ .

$y' = \frac{2 y}{2 x^{4} y^{3} + 2 y - x} + \frac{x (- x^{3} y^{4})}{x (2 x^{4} y^{3} + 2 y - x)} + \frac{- y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.1.2.2

Cancel the common factors.

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Step 5.3.6.3.1.2.2.1

Cancel the common factor.

$y' = \frac{2 y}{2 x^{4} y^{3} + 2 y - x} + \frac{x (- x^{3} y^{4})}{x (2 x^{4} y^{3} + 2 y - x)} + \frac{- y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.1.2.2.2

Rewrite the expression.

$y' = \frac{2 y}{2 x^{4} y^{3} + 2 y - x} + \frac{- x^{3} y^{4}}{2 x^{4} y^{3} + 2 y - x} + \frac{- y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.1.3

Move the negative in front of the fraction.

$y' = \frac{2 y}{2 x^{4} y^{3} + 2 y - x} - \frac{x^{3} y^{4}}{2 x^{4} y^{3} + 2 y - x} + \frac{- y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.1.4

Move the negative in front of the fraction.

$y' = \frac{2 y}{2 x^{4} y^{3} + 2 y - x} - \frac{x^{3} y^{4}}{2 x^{4} y^{3} + 2 y - x} - \frac{y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.2

Simplify terms.

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Step 5.3.6.3.2.1

Combine the numerators over the common denominator.

$y' = \frac{2 y - x^{3} y^{4}}{2 x^{4} y^{3} + 2 y - x} - \frac{y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.2.2

Factor $y$ out of $2 y - x^{3} y^{4}$ .

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Step 5.3.6.3.2.2.1

Factor $y$ out of $2 y$ .

$y' = \frac{y \cdot 2 - x^{3} y^{4}}{2 x^{4} y^{3} + 2 y - x} - \frac{y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.2.2.2

Factor $y$ out of $- x^{3} y^{4}$ .

$y' = \frac{y \cdot 2 + y (- x^{3} y^{3})}{2 x^{4} y^{3} + 2 y - x} - \frac{y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.2.2.3

Factor $y$ out of $y \cdot 2 + y (- x^{3} y^{3})$ .

$y' = \frac{y (2 - x^{3} y^{3})}{2 x^{4} y^{3} + 2 y - x} - \frac{y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.3

To write $\frac{y (2 - x^{3} y^{3})}{2 x^{4} y^{3} + 2 y - x}$ as a fraction with a common denominator, multiply by $\frac{x}{x}$ .

$y' = \frac{y (2 - x^{3} y^{3})}{2 x^{4} y^{3} + 2 y - x} \cdot \frac{x}{x} - \frac{y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.4

Write each expression with a common denominator of $(2 x^{4} y^{3} + 2 y - x) x$ , by multiplying each by an appropriate factor of $1$ .

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Step 5.3.6.3.4.1

Multiply $\frac{y (2 - x^{3} y^{3})}{2 x^{4} y^{3} + 2 y - x}$ by $\frac{x}{x}$ .

$y' = \frac{y (2 - x^{3} y^{3}) x}{(2 x^{4} y^{3} + 2 y - x) x} - \frac{y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.4.2

Reorder the factors of $(2 x^{4} y^{3} + 2 y - x) x$ .

$y' = \frac{y (2 - x^{3} y^{3}) x}{x (2 x^{4} y^{3} + 2 y - x)} - \frac{y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.5

Combine the numerators over the common denominator.

$y' = \frac{y (2 - x^{3} y^{3}) x - y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.6

Simplify the numerator.

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Step 5.3.6.3.6.1

Factor $y$ out of $y (2 - x^{3} y^{3}) x - y^{2}$ .

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Step 5.3.6.3.6.1.1

Factor $y$ out of $y (2 - x^{3} y^{3}) x$ .

$y' = \frac{y ((2 - x^{3} y^{3}) x) - y^{2}}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.6.1.2

Factor $y$ out of $- y^{2}$ .

$y' = \frac{y ((2 - x^{3} y^{3}) x) + y (- y)}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.6.1.3

Factor $y$ out of $y ((2 - x^{3} y^{3}) x) + y (- y)$ .

$y' = \frac{y ((2 - x^{3} y^{3}) x - y)}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.6.2

Apply the distributive property.

$y' = \frac{y (2 x - x^{3} y^{3} x - y)}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.6.3

Multiply $x^{3}$ by $x$ by adding the exponents.

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Step 5.3.6.3.6.3.1

Move $x$ .

$y' = \frac{y (2 x - (x \cdot x^{3}) y^{3} - y)}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.6.3.2

Multiply $x$ by $x^{3}$ .

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Step 5.3.6.3.6.3.2.1

Raise $x$ to the power of $1$ .

$y' = \frac{y (2 x - (x^{1} x^{3}) y^{3} - y)}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.6.3.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y' = \frac{y (2 x - x^{1 + 3} y^{3} - y)}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 5.3.6.3.6.3.3

Add $1$ and $3$ .

$y' = \frac{y (2 x - x^{4} y^{3} - y)}{x (2 x^{4} y^{3} + 2 y - x)}$

Step 6

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = \frac{y (2 x - x^{4} y^{3} - y)}{x (2 x^{4} y^{3} + 2 y - x)}$