Calculus Examples

$25 (x^{2} - y^{2}) = 2 {(x^{2} + y^{2})}^{2}$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (25 (x^{2} - y^{2})) = \frac{d}{d x} (2 {(x^{2} + y^{2})}^{2})$

Step 2

Differentiate the left side of the equation.

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Step 2.1

Differentiate.

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Step 2.1.1

Since $25$ is constant with respect to $x$ , the derivative of $25 (x^{2} - y^{2})$ with respect to $x$ is $25 \frac{d}{d x} [x^{2} - y^{2}]$ .

$25 \frac{d}{d x} [x^{2} - y^{2}]$

Step 2.1.2

By the Sum Rule, the derivative of $x^{2} - y^{2}$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- y^{2}]$ .

$25 (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- y^{2}])$

Step 2.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$25 (2 x + \frac{d}{d x} [- y^{2}])$

Step 2.1.4

Since $- 1$ is constant with respect to $x$ , the derivative of $- y^{2}$ with respect to $x$ is $- \frac{d}{d x} [y^{2}]$ .

$25 (2 x - \frac{d}{d x} [y^{2}])$

Step 2.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = y$ .

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Step 2.2.1

To apply the Chain Rule, set $u$ as $y$ .

$25 (2 x - (\frac{d}{d u} [u^{2}] \frac{d}{d x} [y]))$

Step 2.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$25 (2 x - (2 u \frac{d}{d x} [y]))$

Step 2.2.3

Replace all occurrences of $u$ with $y$ .

$25 (2 x - (2 y \frac{d}{d x} [y]))$

Step 2.3

Multiply $2$ by $- 1$ .

$25 (2 x - 2 (y \frac{d}{d x} [y]))$

Step 2.4

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$25 (2 x - 2 y y')$

Step 2.5

Simplify.

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Step 2.5.1

Apply the distributive property.

$25 (2 x) + 25 (- 2 y y')$

Step 2.5.2

Combine terms.

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Step 2.5.2.1

Multiply $2$ by $25$ .

$50 x + 25 (- 2 y y')$

Step 2.5.2.2

Multiply $- 2$ by $25$ .

$50 x - 50 y y'$

Step 2.5.3

Reorder terms.

$- 50 y y' + 50 x$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Since $2$ is constant with respect to $x$ , the derivative of $2 {(x^{2} + y^{2})}^{2}$ with respect to $x$ is $2 \frac{d}{d x} [{(x^{2} + y^{2})}^{2}]$ .

$2 \frac{d}{d x} [{(x^{2} + y^{2})}^{2}]$

Step 3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = x^{2} + y^{2}$ .

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Step 3.2.1

To apply the Chain Rule, set $u_{1}$ as $x^{2} + y^{2}$ .

$2 (\frac{d}{d u_{1}} [{u_{1}}^{2}] \frac{d}{d x} [x^{2} + y^{2}])$

Step 3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 2$ .

$2 (2 u_{1} \frac{d}{d x} [x^{2} + y^{2}])$

Step 3.2.3

Replace all occurrences of $u_{1}$ with $x^{2} + y^{2}$ .

$2 (2 (x^{2} + y^{2}) \frac{d}{d x} [x^{2} + y^{2}])$

Step 3.3

Differentiate.

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Step 3.3.1

Multiply $2$ by $2$ .

$4 ((x^{2} + y^{2}) \frac{d}{d x} [x^{2} + y^{2}])$

Step 3.3.2

By the Sum Rule, the derivative of $x^{2} + y^{2}$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [y^{2}]$ .

$4 (x^{2} + y^{2}) (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [y^{2}])$

Step 3.3.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$4 (x^{2} + y^{2}) (2 x + \frac{d}{d x} [y^{2}])$

Step 3.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = y$ .

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Step 3.4.1

To apply the Chain Rule, set $u_{2}$ as $y$ .

$4 (x^{2} + y^{2}) (2 x + \frac{d}{d u_{2}} [{u_{2}}^{2}] \frac{d}{d x} [y])$

Step 3.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = 2$ .

$4 (x^{2} + y^{2}) (2 x + 2 u_{2} \frac{d}{d x} [y])$

Step 3.4.3

Replace all occurrences of $u_{2}$ with $y$ .

$4 (x^{2} + y^{2}) (2 x + 2 y \frac{d}{d x} [y])$

Step 3.5

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$4 (x^{2} + y^{2}) (2 x + 2 y y')$

Step 3.6

Simplify.

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Step 3.6.1

Apply the distributive property.

$(4 x^{2} + 4 y^{2}) (2 x + 2 y y')$

Step 3.6.2

Reorder the factors of $(4 x^{2} + 4 y^{2}) (2 x + 2 y y')$ .

$(2 x + 2 y y') (4 x^{2} + 4 y^{2})$

Step 4

Reform the equation by setting the left side equal to the right side.

$- 50 y y' + 50 x = (2 x + 2 y y') (4 x^{2} + 4 y^{2})$

Step 5

Solve for $y'$ .

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Step 5.1

Simplify $(2 x + 2 y y') (4 x^{2} + 4 y^{2})$ .

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Step 5.1.1

Rewrite.

$- 50 y y' + 50 x = 0 + 0 + (2 x + 2 y y') (4 x^{2} + 4 y^{2})$

Step 5.1.2

Simplify by adding zeros.

$- 50 y y' + 50 x = (2 x + 2 y y') (4 x^{2} + 4 y^{2})$

Step 5.1.3

Expand $(2 x + 2 y y') (4 x^{2} + 4 y^{2})$ using the FOIL Method.

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Step 5.1.3.1

Apply the distributive property.

$- 50 y y' + 50 x = 2 x (4 x^{2} + 4 y^{2}) + 2 y y' (4 x^{2} + 4 y^{2})$

Step 5.1.3.2

Apply the distributive property.

$- 50 y y' + 50 x = 2 x (4 x^{2}) + 2 x (4 y^{2}) + 2 y y' (4 x^{2} + 4 y^{2})$

Step 5.1.3.3

Apply the distributive property.

$- 50 y y' + 50 x = 2 x (4 x^{2}) + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2})$

Step 5.1.4

Simplify each term.

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Step 5.1.4.1

Rewrite using the commutative property of multiplication.

$- 50 y y' + 50 x = 2 \cdot 4 x \cdot x^{2} + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2})$

Step 5.1.4.2

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 5.1.4.2.1

Move $x^{2}$ .

$- 50 y y' + 50 x = 2 \cdot 4 (x^{2} x) + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2})$

Step 5.1.4.2.2

Multiply $x^{2}$ by $x$ .

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Step 5.1.4.2.2.1

Raise $x$ to the power of $1$ .

$- 50 y y' + 50 x = 2 \cdot 4 (x^{2} x^{1}) + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2})$

Step 5.1.4.2.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$- 50 y y' + 50 x = 2 \cdot 4 x^{2 + 1} + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2})$

Step 5.1.4.2.3

Add $2$ and $1$ .

$- 50 y y' + 50 x = 2 \cdot 4 x^{3} + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2})$

Step 5.1.4.3

Multiply $2$ by $4$ .

$- 50 y y' + 50 x = 8 x^{3} + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2})$

Step 5.1.4.4

Rewrite using the commutative property of multiplication.

$- 50 y y' + 50 x = 8 x^{3} + 2 \cdot 4 x y^{2} + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2})$

Step 5.1.4.5

Multiply $2$ by $4$ .

$- 50 y y' + 50 x = 8 x^{3} + 8 x y^{2} + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2})$

Step 5.1.4.6

Multiply $4$ by $2$ .

$- 50 y y' + 50 x = 8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 2 y y' (4 y^{2})$

Step 5.1.4.7

Multiply $y$ by $y^{2}$ by adding the exponents.

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Step 5.1.4.7.1

Move $y^{2}$ .

$- 50 y y' + 50 x = 8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 2 (y^{2} y) y' \cdot 4$

Step 5.1.4.7.2

Multiply $y^{2}$ by $y$ .

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Step 5.1.4.7.2.1

Raise $y$ to the power of $1$ .

$- 50 y y' + 50 x = 8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 2 (y^{2} y^{1}) y' \cdot 4$

Step 5.1.4.7.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$- 50 y y' + 50 x = 8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 2 y^{2 + 1} y' \cdot 4$

Step 5.1.4.7.3

Add $2$ and $1$ .

$- 50 y y' + 50 x = 8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 2 y^{3} y' \cdot 4$

Step 5.1.4.8

Multiply $4$ by $2$ .

$- 50 y y' + 50 x = 8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 8 y^{3} y'$

Step 5.2

Since $y'$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 8 y^{3} y' = - 50 y y' + 50 x$

Step 5.3

Add $50 y y'$ to both sides of the equation.

$8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 8 y^{3} y' + 50 y y' = 50 x$

Step 5.4

Move all terms not containing $y'$ to the right side of the equation.

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Step 5.4.1

Subtract $8 x^{3}$ from both sides of the equation.

$8 x y^{2} + 8 y y' x^{2} + 8 y^{3} y' + 50 y y' = 50 x - 8 x^{3}$

Step 5.4.2

Subtract $8 x y^{2}$ from both sides of the equation.

$8 y y' x^{2} + 8 y^{3} y' + 50 y y' = 50 x - 8 x^{3} - 8 x y^{2}$

Step 5.5

Factor $2 y y'$ out of $8 y y' x^{2} + 8 y^{3} y' + 50 y y'$ .

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Step 5.5.1

Factor $2 y y'$ out of $8 y y' x^{2}$ .

$2 y y' (4 x^{2}) + 8 y^{3} y' + 50 y y' = 50 x - 8 x^{3} - 8 x y^{2}$

Step 5.5.2

Factor $2 y y'$ out of $8 y^{3} y'$ .

$2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) + 50 y y' = 50 x - 8 x^{3} - 8 x y^{2}$

Step 5.5.3

Factor $2 y y'$ out of $50 y y'$ .

$2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) + 2 y y' \cdot 25 = 50 x - 8 x^{3} - 8 x y^{2}$

Step 5.5.4

Factor $2 y y'$ out of $2 y y' (4 x^{2}) + 2 y y' (4 y^{2})$ .

$2 y y' (4 x^{2} + 4 y^{2}) + 2 y y' \cdot 25 = 50 x - 8 x^{3} - 8 x y^{2}$

Step 5.5.5

Factor $2 y y'$ out of $2 y y' (4 x^{2} + 4 y^{2}) + 2 y y' \cdot 25$ .

$2 y y' (4 x^{2} + 4 y^{2} + 25) = 50 x - 8 x^{3} - 8 x y^{2}$

Step 5.6

Divide each term in $2 y y' (4 x^{2} + 4 y^{2} + 25) = 50 x - 8 x^{3} - 8 x y^{2}$ by $2 y (4 x^{2} + 4 y^{2} + 25)$ and simplify.

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Step 5.6.1

Divide each term in $2 y y' (4 x^{2} + 4 y^{2} + 25) = 50 x - 8 x^{3} - 8 x y^{2}$ by $2 y (4 x^{2} + 4 y^{2} + 25)$ .

$\frac{2 y y' (4 x^{2} + 4 y^{2} + 25)}{2 y (4 x^{2} + 4 y^{2} + 25)} = \frac{50 x}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.2

Simplify the left side.

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Step 5.6.2.1

Cancel the common factor of $2$ .

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Step 5.6.2.1.1

Cancel the common factor.

Step 5.6.2.1.2

Rewrite the expression.

$\frac{y y' (4 x^{2} + 4 y^{2} + 25)}{y (4 x^{2} + 4 y^{2} + 25)} = \frac{50 x}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.2.2

Cancel the common factor of $y$ .

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Step 5.6.2.2.1

Cancel the common factor.

Step 5.6.2.2.2

Rewrite the expression.

$\frac{y' (4 x^{2} + 4 y^{2} + 25)}{4 x^{2} + 4 y^{2} + 25} = \frac{50 x}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.2.3

Cancel the common factor of $4 x^{2} + 4 y^{2} + 25$ .

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Step 5.6.2.3.1

Cancel the common factor.

Step 5.6.2.3.2

Divide $y'$ by $1$ .

$y' = \frac{50 x}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3

Simplify the right side.

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Step 5.6.3.1

Simplify each term.

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Step 5.6.3.1.1

Cancel the common factor of $50$ and $2$ .

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Step 5.6.3.1.1.1

Factor $2$ out of $50 x$ .

$y' = \frac{2 (25 x)}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.1.2

Cancel the common factors.

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Step 5.6.3.1.1.2.1

Factor $2$ out of $2 y (4 x^{2} + 4 y^{2} + 25)$ .

$y' = \frac{2 (25 x)}{2 (y (4 x^{2} + 4 y^{2} + 25))} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.1.2.2

Cancel the common factor.

$y' = \frac{2 (25 x)}{2 (y (4 x^{2} + 4 y^{2} + 25))} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.1.2.3

Rewrite the expression.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.2

Cancel the common factor of $- 8$ and $2$ .

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Step 5.6.3.1.2.1

Factor $2$ out of $- 8 x^{3}$ .

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{2 (- 4 x^{3})}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.2.2

Cancel the common factors.

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Step 5.6.3.1.2.2.1

Factor $2$ out of $2 y (4 x^{2} + 4 y^{2} + 25)$ .

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{2 (- 4 x^{3})}{2 (y (4 x^{2} + 4 y^{2} + 25))} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.2.2.2

Cancel the common factor.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{2 (- 4 x^{3})}{2 (y (4 x^{2} + 4 y^{2} + 25))} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.2.2.3

Rewrite the expression.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.3

Move the negative in front of the fraction.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.4

Cancel the common factor of $- 8$ and $2$ .

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Step 5.6.3.1.4.1

Factor $2$ out of $- 8 x y^{2}$ .

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{2 (- 4 x y^{2})}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.4.2

Cancel the common factors.

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Step 5.6.3.1.4.2.1

Factor $2$ out of $2 y (4 x^{2} + 4 y^{2} + 25)$ .

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{2 (- 4 x y^{2})}{2 (y (4 x^{2} + 4 y^{2} + 25))}$

Step 5.6.3.1.4.2.2

Cancel the common factor.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{2 (- 4 x y^{2})}{2 (y (4 x^{2} + 4 y^{2} + 25))}$

Step 5.6.3.1.4.2.3

Rewrite the expression.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 4 x y^{2}}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.5

Cancel the common factor of $y^{2}$ and $y$ .

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Step 5.6.3.1.5.1

Factor $y$ out of $- 4 x y^{2}$ .

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{y (- 4 x y)}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.5.2

Cancel the common factors.

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Step 5.6.3.1.5.2.1

Cancel the common factor.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{y (- 4 x y)}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.1.5.2.2

Rewrite the expression.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 4 x y}{4 x^{2} + 4 y^{2} + 25}$

Step 5.6.3.1.6

Move the negative in front of the fraction.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x y}{4 x^{2} + 4 y^{2} + 25}$

Step 5.6.3.2

To write $- \frac{4 x y}{4 x^{2} + 4 y^{2} + 25}$ as a fraction with a common denominator, multiply by $\frac{y}{y}$ .

$y' = - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x y}{4 x^{2} + 4 y^{2} + 25} \cdot \frac{y}{y}$

Step 5.6.3.3

Write each expression with a common denominator of $y (4 x^{2} + 4 y^{2} + 25)$ , by multiplying each by an appropriate factor of $1$ .

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Step 5.6.3.3.1

Multiply $\frac{4 x y}{4 x^{2} + 4 y^{2} + 25}$ by $\frac{y}{y}$ .

$y' = - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x y \cdot y}{(4 x^{2} + 4 y^{2} + 25) y}$

Step 5.6.3.3.2

Reorder the factors of $(4 x^{2} + 4 y^{2} + 25) y$ .

$y' = - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x y \cdot y}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.4

Combine the numerators over the common denominator.

$y' = - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{25 x - 4 x y \cdot y}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.5

Combine the numerators over the common denominator.

$y' = \frac{- 4 x^{3} + 25 x - 4 x y \cdot y}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.6

Multiply $y$ by $y$ by adding the exponents.

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Step 5.6.3.6.1

Move $y$ .

$y' = \frac{- 4 x^{3} + 25 x - 4 x (y \cdot y)}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.6.2

Multiply $y$ by $y$ .

$y' = \frac{- 4 x^{3} + 25 x - 4 x y^{2}}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.7

Factor $x$ out of $- 4 x^{3} + 25 x - 4 x y^{2}$ .

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Step 5.6.3.7.1

Factor $x$ out of $- 4 x^{3}$ .

$y' = \frac{x (- 4 x^{2}) + 25 x - 4 x y^{2}}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.7.2

Factor $x$ out of $25 x$ .

$y' = \frac{x (- 4 x^{2}) + x \cdot 25 - 4 x y^{2}}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.7.3

Factor $x$ out of $- 4 x y^{2}$ .

$y' = \frac{x (- 4 x^{2}) + x \cdot 25 + x (- 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.7.4

Factor $x$ out of $x (- 4 x^{2}) + x \cdot 25$ .

$y' = \frac{x (- 4 x^{2} + 25) + x (- 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.7.5

Factor $x$ out of $x (- 4 x^{2} + 25) + x (- 4 y^{2})$ .

$y' = \frac{x (- 4 x^{2} + 25 - 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.8

Factor $- 1$ out of $- 4 x^{2}$ .

$y' = \frac{x (- (4 x^{2}) + 25 - 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.9

Rewrite $25$ as $- 1 (- 25)$ .

$y' = \frac{x (- (4 x^{2}) - 1 (- 25) - 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.10

Factor $- 1$ out of $- (4 x^{2}) - 1 (- 25)$ .

$y' = \frac{x (- (4 x^{2} - 25) - 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.11

Factor $- 1$ out of $- 4 y^{2}$ .

$y' = \frac{x (- (4 x^{2} - 25) - (4 y^{2}))}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.12

Factor $- 1$ out of $- (4 x^{2} - 25) - (4 y^{2})$ .

$y' = \frac{x (- (4 x^{2} - 25 + 4 y^{2}))}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.13

Simplify the expression.

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Step 5.6.3.13.1

Rewrite $- (4 x^{2} - 25 + 4 y^{2})$ as $- 1 (4 x^{2} - 25 + 4 y^{2})$ .

$y' = \frac{x (- 1 (4 x^{2} - 25 + 4 y^{2}))}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 5.6.3.13.2

Move the negative in front of the fraction.

$y' = - \frac{x (4 x^{2} - 25 + 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 6

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = - \frac{x (4 x^{2} - 25 + 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$