Calculus Examples

$x^{9} (x + y) = y^{2} (4 x - y)$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (x^{9} (x + y)) = \frac{d}{d x} (y^{2} (4 x - y))$

Step 2

Differentiate the left side of the equation.

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Step 2.1

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{9}$ and $g (x) = x + y$ .

$x^{9} \frac{d}{d x} [x + y] + (x + y) \frac{d}{d x} [x^{9}]$

Step 2.2

Differentiate.

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Step 2.2.1

By the Sum Rule, the derivative of $x + y$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [y]$ .

$x^{9} (\frac{d}{d x} [x] + \frac{d}{d x} [y]) + (x + y) \frac{d}{d x} [x^{9}]$

Step 2.2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$x^{9} (1 + \frac{d}{d x} [y]) + (x + y) \frac{d}{d x} [x^{9}]$

Step 2.3

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$x^{9} (1 + y') + (x + y) \frac{d}{d x} [x^{9}]$

Step 2.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 9$ .

$x^{9} (1 + y') + (x + y) (9 x^{8})$

Step 2.5

Move $9$ to the left of $x + y$ .

$x^{9} (1 + y') + 9 \cdot (x + y) x^{8}$

Step 2.6

Simplify.

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Step 2.6.1

Apply the distributive property.

$x^{9} \cdot 1 + x^{9} y' + 9 (x + y) x^{8}$

Step 2.6.2

Apply the distributive property.

$x^{9} \cdot 1 + x^{9} y' + (9 x + 9 y) x^{8}$

Step 2.6.3

Apply the distributive property.

$x^{9} \cdot 1 + x^{9} y' + 9 x \cdot x^{8} + 9 y x^{8}$

Step 2.6.4

Combine terms.

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Step 2.6.4.1

Multiply $x^{9}$ by $1$ .

$x^{9} + x^{9} y' + 9 x \cdot x^{8} + 9 y x^{8}$

Step 2.6.4.2

Multiply $x$ by $x^{8}$ by adding the exponents.

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Step 2.6.4.2.1

Move $x^{8}$ .

$x^{9} + x^{9} y' + 9 (x^{8} x) + 9 y x^{8}$

Step 2.6.4.2.2

Multiply $x^{8}$ by $x$ .

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Step 2.6.4.2.2.1

Raise $x$ to the power of $1$ .

$x^{9} + x^{9} y' + 9 (x^{8} x^{1}) + 9 y x^{8}$

Step 2.6.4.2.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x^{9} + x^{9} y' + 9 x^{8 + 1} + 9 y x^{8}$

Step 2.6.4.2.3

Add $8$ and $1$ .

$x^{9} + x^{9} y' + 9 x^{9} + 9 y x^{8}$

Step 2.6.4.3

Add $x^{9}$ and $9 x^{9}$ .

$10 x^{9} + x^{9} y' + 9 y x^{8}$

Step 2.6.5

Reorder terms.

$10 x^{9} + x^{9} y' + 9 x^{8} y$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = y^{2}$ and $g (x) = 4 x - y$ .

$y^{2} \frac{d}{d x} [4 x - y] + (4 x - y) \frac{d}{d x} [y^{2}]$

Step 3.2

Differentiate.

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Step 3.2.1

By the Sum Rule, the derivative of $4 x - y$ with respect to $x$ is $\frac{d}{d x} [4 x] + \frac{d}{d x} [- y]$ .

$y^{2} (\frac{d}{d x} [4 x] + \frac{d}{d x} [- y]) + (4 x - y) \frac{d}{d x} [y^{2}]$

Step 3.2.2

Since $4$ is constant with respect to $x$ , the derivative of $4 x$ with respect to $x$ is $4 \frac{d}{d x} [x]$ .

$y^{2} (4 \frac{d}{d x} [x] + \frac{d}{d x} [- y]) + (4 x - y) \frac{d}{d x} [y^{2}]$

Step 3.2.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$y^{2} (4 \cdot 1 + \frac{d}{d x} [- y]) + (4 x - y) \frac{d}{d x} [y^{2}]$

Step 3.2.4

Multiply $4$ by $1$ .

$y^{2} (4 + \frac{d}{d x} [- y]) + (4 x - y) \frac{d}{d x} [y^{2}]$

Step 3.2.5

Since $- 1$ is constant with respect to $x$ , the derivative of $- y$ with respect to $x$ is $- \frac{d}{d x} [y]$ .

$y^{2} (4 - \frac{d}{d x} [y]) + (4 x - y) \frac{d}{d x} [y^{2}]$

Step 3.3

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$y^{2} (4 - y') + (4 x - y) \frac{d}{d x} [y^{2}]$

Step 3.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = y$ .

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Step 3.4.1

To apply the Chain Rule, set $u$ as $y$ .

$y^{2} (4 - y') + (4 x - y) (\frac{d}{d u} [u^{2}] \frac{d}{d x} [y])$

Step 3.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$y^{2} (4 - y') + (4 x - y) (2 u \frac{d}{d x} [y])$

Step 3.4.3

Replace all occurrences of $u$ with $y$ .

$y^{2} (4 - y') + (4 x - y) (2 y \frac{d}{d x} [y])$

Step 3.5

Move $2$ to the left of $4 x - y$ .

$y^{2} (4 - y') + 2 \cdot (4 x - y) y \frac{d}{d x} [y]$

Step 3.6

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$y^{2} (4 - y') + 2 (4 x - y) y y'$

Step 3.7

Simplify.

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Step 3.7.1

Apply the distributive property.

$y^{2} \cdot 4 + y^{2} (- y') + 2 (4 x - y) y y'$

Step 3.7.2

Apply the distributive property.

$y^{2} \cdot 4 + y^{2} (- y') + (2 (4 x) + 2 (- y)) y y'$

Step 3.7.3

Apply the distributive property.

$y^{2} \cdot 4 + y^{2} (- y') + (2 (4 x) y + 2 (- y) y) y'$

Step 3.7.4

Apply the distributive property.

$y^{2} \cdot 4 + y^{2} (- y') + 2 (4 x) y y' + 2 (- y) y y'$

Step 3.7.5

Combine terms.

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Step 3.7.5.1

Move $4$ to the left of $y^{2}$ .

$4 \cdot y^{2} + y^{2} (- y') + 2 (4 x) y y' + 2 (- y) y y'$

Step 3.7.5.2

Multiply $4$ by $2$ .

$4 y^{2} + y^{2} (- y') + 8 x y y' + 2 (- y) y y'$

Step 3.7.5.3

Multiply $- 1$ by $2$ .

$4 y^{2} + y^{2} (- y') + 8 x y y' - 2 y \cdot y y'$

Step 3.7.5.4

Raise $y$ to the power of $1$ .

$4 y^{2} + y^{2} (- y') + 8 x y y' - 2 (y^{1} y) y'$

Step 3.7.5.5

Raise $y$ to the power of $1$ .

$4 y^{2} + y^{2} (- y') + 8 x y y' - 2 (y^{1} y^{1}) y'$

Step 3.7.5.6

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$4 y^{2} + y^{2} (- y') + 8 x y y' - 2 y^{1 + 1} y'$

Step 3.7.5.7

Add $1$ and $1$ .

$4 y^{2} + y^{2} (- y') + 8 x y y' - 2 y^{2} y'$

Step 3.7.5.8

Subtract $2 y^{2} y'$ from $y^{2} (- y')$ .

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Step 3.7.5.8.1

Reorder $y^{2}$ and $- 1$ .

$4 y^{2} - 1 \cdot y^{2} y' - 2 y^{2} y' + 8 x y y'$

Step 3.7.5.8.2

Subtract $2 y^{2} y'$ from $- 1 \cdot y^{2} y'$ .

$4 y^{2} - 3 y^{2} y' + 8 x y y'$

Step 4

Reform the equation by setting the left side equal to the right side.

$10 x^{9} + x^{9} y' + 9 x^{8} y = 4 y^{2} - 3 y^{2} y' + 8 x y y'$

Step 5

Solve for $y'$ .

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Step 5.1

Since $y'$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$4 y^{2} - 3 y^{2} y' + 8 x y y' = 10 x^{9} + x^{9} y' + 9 x^{8} y$

Step 5.2

Subtract $x^{9} y'$ from both sides of the equation.

$4 y^{2} - 3 y^{2} y' + 8 x y y' - x^{9} y' = 10 x^{9} + 9 x^{8} y$

Step 5.3

Subtract $4 y^{2}$ from both sides of the equation.

$- 3 y^{2} y' + 8 x y y' - x^{9} y' = 10 x^{9} + 9 x^{8} y - 4 y^{2}$

Step 5.4

Factor $y'$ out of $- 3 y^{2} y' + 8 x y y' - x^{9} y'$ .

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Step 5.4.1

Factor $y'$ out of $- 3 y^{2} y'$ .

$y' (- 3 y^{2}) + 8 x y y' - x^{9} y' = 10 x^{9} + 9 x^{8} y - 4 y^{2}$

Step 5.4.2

Factor $y'$ out of $8 x y y'$ .

$y' (- 3 y^{2}) + y' (8 x y) - x^{9} y' = 10 x^{9} + 9 x^{8} y - 4 y^{2}$

Step 5.4.3

Factor $y'$ out of $- x^{9} y'$ .

$y' (- 3 y^{2}) + y' (8 x y) + y' (- x^{9}) = 10 x^{9} + 9 x^{8} y - 4 y^{2}$

Step 5.4.4

Factor $y'$ out of $y' (- 3 y^{2}) + y' (8 x y)$ .

$y' (- 3 y^{2} + 8 x y) + y' (- x^{9}) = 10 x^{9} + 9 x^{8} y - 4 y^{2}$

Step 5.4.5

Factor $y'$ out of $y' (- 3 y^{2} + 8 x y) + y' (- x^{9})$ .

$y' (- 3 y^{2} + 8 x y - x^{9}) = 10 x^{9} + 9 x^{8} y - 4 y^{2}$

Step 5.5

Divide each term in $y' (- 3 y^{2} + 8 x y - x^{9}) = 10 x^{9} + 9 x^{8} y - 4 y^{2}$ by $- 3 y^{2} + 8 x y - x^{9}$ and simplify.

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Step 5.5.1

Divide each term in $y' (- 3 y^{2} + 8 x y - x^{9}) = 10 x^{9} + 9 x^{8} y - 4 y^{2}$ by $- 3 y^{2} + 8 x y - x^{9}$ .

$\frac{y' (- 3 y^{2} + 8 x y - x^{9})}{- 3 y^{2} + 8 x y - x^{9}} = \frac{10 x^{9}}{- 3 y^{2} + 8 x y - x^{9}} + \frac{9 x^{8} y}{- 3 y^{2} + 8 x y - x^{9}} + \frac{- 4 y^{2}}{- 3 y^{2} + 8 x y - x^{9}}$

Step 5.5.2

Simplify the left side.

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Step 5.5.2.1

Cancel the common factor of $- 3 y^{2} + 8 x y - x^{9}$ .

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Step 5.5.2.1.1

Cancel the common factor.

Step 5.5.2.1.2

Divide $y'$ by $1$ .

$y' = \frac{10 x^{9}}{- 3 y^{2} + 8 x y - x^{9}} + \frac{9 x^{8} y}{- 3 y^{2} + 8 x y - x^{9}} + \frac{- 4 y^{2}}{- 3 y^{2} + 8 x y - x^{9}}$

Step 5.5.3

Simplify the right side.

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Step 5.5.3.1

Move the negative in front of the fraction.

$y' = \frac{10 x^{9}}{- 3 y^{2} + 8 x y - x^{9}} + \frac{9 x^{8} y}{- 3 y^{2} + 8 x y - x^{9}} - \frac{4 y^{2}}{- 3 y^{2} + 8 x y - x^{9}}$

Step 5.5.3.2

Combine the numerators over the common denominator.

$y' = \frac{10 x^{9} + 9 x^{8} y}{- 3 y^{2} + 8 x y - x^{9}} - \frac{4 y^{2}}{- 3 y^{2} + 8 x y - x^{9}}$

Step 5.5.3.3

Combine the numerators over the common denominator.

$y' = \frac{10 x^{9} + 9 x^{8} y - 4 y^{2}}{- 3 y^{2} + 8 x y - x^{9}}$

Step 5.5.3.4

Factor $- 1$ out of $- 3 y^{2}$ .

$y' = \frac{10 x^{9} + 9 x^{8} y - 4 y^{2}}{- (3 y^{2}) + 8 x y - x^{9}}$

Step 5.5.3.5

Factor $- 1$ out of $8 x y$ .

$y' = \frac{10 x^{9} + 9 x^{8} y - 4 y^{2}}{- (3 y^{2}) - (- 8 x y) - x^{9}}$

Step 5.5.3.6

Factor $- 1$ out of $- (3 y^{2}) - (- 8 x y)$ .

$y' = \frac{10 x^{9} + 9 x^{8} y - 4 y^{2}}{- (3 y^{2} - 8 x y) - x^{9}}$

Step 5.5.3.7

Factor $- 1$ out of $- x^{9}$ .

$y' = \frac{10 x^{9} + 9 x^{8} y - 4 y^{2}}{- (3 y^{2} - 8 x y) - (x^{9})}$

Step 5.5.3.8

Factor $- 1$ out of $- (3 y^{2} - 8 x y) - (x^{9})$ .

$y' = \frac{10 x^{9} + 9 x^{8} y - 4 y^{2}}{- (3 y^{2} - 8 x y + x^{9})}$

Step 5.5.3.9

Rewrite negatives.

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Step 5.5.3.9.1

Rewrite $- (3 y^{2} - 8 x y + x^{9})$ as $- 1 (3 y^{2} - 8 x y + x^{9})$ .

$y' = \frac{10 x^{9} + 9 x^{8} y - 4 y^{2}}{- 1 (3 y^{2} - 8 x y + x^{9})}$

Step 5.5.3.9.2

Move the negative in front of the fraction.

$y' = - \frac{10 x^{9} + 9 x^{8} y - 4 y^{2}}{3 y^{2} - 8 x y + x^{9}}$

Step 6

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = - \frac{10 x^{9} + 9 x^{8} y - 4 y^{2}}{3 y^{2} - 8 x y + x^{9}}$