Calculus Examples

$y = \frac{(x - 3) (x^{2} + 3 x + 9)}{x^{3}}$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (y) = \frac{d}{d x} (\frac{(x - 3) (x^{2} + 3 x + 9)}{x^{3}})$

Step 2

The derivative of $y$ with respect to $x$ is $y'$ .

$y'$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = (x - 3) (x^{2} + 3 x + 9)$ and $g (x) = x^{3}$ .

$\frac{x^{3} \frac{d}{d x} [(x - 3) (x^{2} + 3 x + 9)] - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{{(x^{3})}^{2}}$

Step 3.2

Multiply the exponents in ${(x^{3})}^{2}$ .

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Step 3.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{x^{3} \frac{d}{d x} [(x - 3) (x^{2} + 3 x + 9)] - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{3 \cdot 2}}$

Step 3.2.2

Multiply $3$ by $2$ .

$\frac{x^{3} \frac{d}{d x} [(x - 3) (x^{2} + 3 x + 9)] - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.3

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x - 3$ and $g (x) = x^{2} + 3 x + 9$ .

$\frac{x^{3} ((x - 3) \frac{d}{d x} [x^{2} + 3 x + 9] + (x^{2} + 3 x + 9) \frac{d}{d x} [x - 3]) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4

Differentiate.

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Step 3.4.1

By the Sum Rule, the derivative of $x^{2} + 3 x + 9$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [3 x] + \frac{d}{d x} [9]$ .

$\frac{x^{3} ((x - 3) (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [3 x] + \frac{d}{d x} [9]) + (x^{2} + 3 x + 9) \frac{d}{d x} [x - 3]) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{x^{3} ((x - 3) (2 x + \frac{d}{d x} [3 x] + \frac{d}{d x} [9]) + (x^{2} + 3 x + 9) \frac{d}{d x} [x - 3]) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4.3

Since $3$ is constant with respect to $x$ , the derivative of $3 x$ with respect to $x$ is $3 \frac{d}{d x} [x]$ .

$\frac{x^{3} ((x - 3) (2 x + 3 \frac{d}{d x} [x] + \frac{d}{d x} [9]) + (x^{2} + 3 x + 9) \frac{d}{d x} [x - 3]) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{x^{3} ((x - 3) (2 x + 3 \cdot 1 + \frac{d}{d x} [9]) + (x^{2} + 3 x + 9) \frac{d}{d x} [x - 3]) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4.5

Multiply $3$ by $1$ .

$\frac{x^{3} ((x - 3) (2 x + 3 + \frac{d}{d x} [9]) + (x^{2} + 3 x + 9) \frac{d}{d x} [x - 3]) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4.6

Since $9$ is constant with respect to $x$ , the derivative of $9$ with respect to $x$ is $0$ .

$\frac{x^{3} ((x - 3) (2 x + 3 + 0) + (x^{2} + 3 x + 9) \frac{d}{d x} [x - 3]) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4.7

Add $2 x + 3$ and $0$ .

$\frac{x^{3} ((x - 3) (2 x + 3) + (x^{2} + 3 x + 9) \frac{d}{d x} [x - 3]) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4.8

By the Sum Rule, the derivative of $x - 3$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [- 3]$ .

$\frac{x^{3} ((x - 3) (2 x + 3) + (x^{2} + 3 x + 9) (\frac{d}{d x} [x] + \frac{d}{d x} [- 3])) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4.9

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{x^{3} ((x - 3) (2 x + 3) + (x^{2} + 3 x + 9) (1 + \frac{d}{d x} [- 3])) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4.10

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3$ with respect to $x$ is $0$ .

$\frac{x^{3} ((x - 3) (2 x + 3) + (x^{2} + 3 x + 9) (1 + 0)) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4.11

Simplify the expression.

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Step 3.4.11.1

Add $1$ and $0$ .

$\frac{x^{3} ((x - 3) (2 x + 3) + (x^{2} + 3 x + 9) \cdot 1) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4.11.2

Multiply $x^{2} + 3 x + 9$ by $1$ .

$\frac{x^{3} ((x - 3) (2 x + 3) + x^{2} + 3 x + 9) - (x - 3) (x^{2} + 3 x + 9) \frac{d}{d x} [x^{3}]}{x^{6}}$

Step 3.4.12

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$\frac{x^{3} ((x - 3) (2 x + 3) + x^{2} + 3 x + 9) - (x - 3) (x^{2} + 3 x + 9) (3 x^{2})}{x^{6}}$

Step 3.4.13

Simplify with factoring out.

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Step 3.4.13.1

Multiply $3$ by $- 1$ .

$\frac{x^{3} ((x - 3) (2 x + 3) + x^{2} + 3 x + 9) - 3 (x - 3) (x^{2} + 3 x + 9) x^{2}}{x^{6}}$

Step 3.4.13.2

Factor $x^{2}$ out of $x^{3} ((x - 3) (2 x + 3) + x^{2} + 3 x + 9) - 3 (x - 3) (x^{2} + 3 x + 9) x^{2}$ .

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Step 3.4.13.2.1

Factor $x^{2}$ out of $x^{3} ((x - 3) (2 x + 3) + x^{2} + 3 x + 9)$ .

$\frac{x^{2} (x ((x - 3) (2 x + 3) + x^{2} + 3 x + 9)) - 3 (x - 3) (x^{2} + 3 x + 9) x^{2}}{x^{6}}$

Step 3.4.13.2.2

Factor $x^{2}$ out of $- 3 (x - 3) (x^{2} + 3 x + 9) x^{2}$ .

$\frac{x^{2} (x ((x - 3) (2 x + 3) + x^{2} + 3 x + 9)) + x^{2} (- 3 (x - 3) (x^{2} + 3 x + 9))}{x^{6}}$

Step 3.4.13.2.3

Factor $x^{2}$ out of $x^{2} (x ((x - 3) (2 x + 3) + x^{2} + 3 x + 9)) + x^{2} (- 3 (x - 3) (x^{2} + 3 x + 9))$ .

$\frac{x^{2} (x ((x - 3) (2 x + 3) + x^{2} + 3 x + 9) - 3 (x - 3) (x^{2} + 3 x + 9))}{x^{6}}$

Step 3.5

Cancel the common factors.

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Step 3.5.1

Factor $x^{2}$ out of $x^{6}$ .

$\frac{x^{2} (x ((x - 3) (2 x + 3) + x^{2} + 3 x + 9) - 3 (x - 3) (x^{2} + 3 x + 9))}{x^{2} x^{4}}$

Step 3.5.2

Cancel the common factor.

$\frac{x^{2} (x ((x - 3) (2 x + 3) + x^{2} + 3 x + 9) - 3 (x - 3) (x^{2} + 3 x + 9))}{x^{2} x^{4}}$

Step 3.5.3

Rewrite the expression.

$\frac{x ((x - 3) (2 x + 3) + x^{2} + 3 x + 9) - 3 (x - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6

Simplify.

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Step 3.6.1

Apply the distributive property.

$\frac{x ((x - 3) (2 x + 3)) + x \cdot x^{2} + x (3 x) + x \cdot 9 - 3 (x - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.2

Apply the distributive property.

$\frac{x ((x - 3) (2 x + 3)) + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3

Simplify the numerator.

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Step 3.6.3.1

Simplify each term.

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Step 3.6.3.1.1

Expand $(x - 3) (2 x + 3)$ using the FOIL Method.

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Step 3.6.3.1.1.1

Apply the distributive property.

$\frac{x (x (2 x + 3) - 3 (2 x + 3)) + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.1.2

Apply the distributive property.

$\frac{x (x (2 x) + x \cdot 3 - 3 (2 x + 3)) + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.1.3

Apply the distributive property.

$\frac{x (x (2 x) + x \cdot 3 - 3 (2 x) - 3 \cdot 3) + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.2

Simplify and combine like terms.

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Step 3.6.3.1.2.1

Simplify each term.

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Step 3.6.3.1.2.1.1

Rewrite using the commutative property of multiplication.

$\frac{x (2 x \cdot x + x \cdot 3 - 3 (2 x) - 3 \cdot 3) + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.2.1.2

Multiply $x$ by $x$ by adding the exponents.

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Step 3.6.3.1.2.1.2.1

Move $x$ .

$\frac{x (2 (x \cdot x) + x \cdot 3 - 3 (2 x) - 3 \cdot 3) + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.2.1.2.2

Multiply $x$ by $x$ .

$\frac{x (2 x^{2} + x \cdot 3 - 3 (2 x) - 3 \cdot 3) + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.2.1.3

Move $3$ to the left of $x$ .

$\frac{x (2 x^{2} + 3 \cdot x - 3 (2 x) - 3 \cdot 3) + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.2.1.4

Multiply $2$ by $- 3$ .

$\frac{x (2 x^{2} + 3 x - 6 x - 3 \cdot 3) + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.2.1.5

Multiply $- 3$ by $3$ .

$\frac{x (2 x^{2} + 3 x - 6 x - 9) + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.2.2

Subtract $6 x$ from $3 x$ .

$\frac{x (2 x^{2} - 3 x - 9) + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.3

Apply the distributive property.

$\frac{x (2 x^{2}) + x (- 3 x) + x \cdot - 9 + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.4

Simplify.

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Step 3.6.3.1.4.1

Rewrite using the commutative property of multiplication.

$\frac{2 x \cdot x^{2} + x (- 3 x) + x \cdot - 9 + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.4.2

Rewrite using the commutative property of multiplication.

$\frac{2 x \cdot x^{2} - 3 x \cdot x + x \cdot - 9 + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.4.3

Move $- 9$ to the left of $x$ .

$\frac{2 x \cdot x^{2} - 3 x \cdot x - 9 \cdot x + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.5

Simplify each term.

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Step 3.6.3.1.5.1

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 3.6.3.1.5.1.1

Move $x^{2}$ .

$\frac{2 (x^{2} x) - 3 x \cdot x - 9 \cdot x + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.5.1.2

Multiply $x^{2}$ by $x$ .

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Step 3.6.3.1.5.1.2.1

Raise $x$ to the power of $1$ .

$\frac{2 (x^{2} x^{1}) - 3 x \cdot x - 9 \cdot x + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.5.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 x^{2 + 1} - 3 x \cdot x - 9 \cdot x + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.5.1.3

Add $2$ and $1$ .

$\frac{2 x^{3} - 3 x \cdot x - 9 \cdot x + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.5.2

Multiply $x$ by $x$ by adding the exponents.

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Step 3.6.3.1.5.2.1

Move $x$ .

$\frac{2 x^{3} - 3 (x \cdot x) - 9 \cdot x + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.5.2.2

Multiply $x$ by $x$ .

$\frac{2 x^{3} - 3 x^{2} - 9 \cdot x + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

$\frac{2 x^{3} - 3 x^{2} - 9 x + x \cdot x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.6

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 3.6.3.1.6.1

Multiply $x$ by $x^{2}$ .

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Step 3.6.3.1.6.1.1

Raise $x$ to the power of $1$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{1} x^{2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.6.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{1 + 2} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.6.2

Add $1$ and $2$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + x (3 x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.7

Rewrite using the commutative property of multiplication.

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x \cdot x + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.8

Multiply $x$ by $x$ by adding the exponents.

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Step 3.6.3.1.8.1

Move $x$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 (x \cdot x) + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.8.2

Multiply $x$ by $x$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + x \cdot 9 + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.9

Move $9$ to the left of $x$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 \cdot x + (- 3 x - 3 \cdot - 3) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.10

Multiply $- 3$ by $- 3$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x + (- 3 x + 9) (x^{2} + 3 x + 9)}{x^{4}}$

Step 3.6.3.1.11

Expand $(- 3 x + 9) (x^{2} + 3 x + 9)$ by multiplying each term in the first expression by each term in the second expression.

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x \cdot x^{2} - 3 x (3 x) - 3 x \cdot 9 + 9 x^{2} + 9 (3 x) + 9 \cdot 9}{x^{4}}$

Step 3.6.3.1.12

Combine the opposite terms in $- 3 x \cdot x^{2} - 3 x (3 x) - 3 x \cdot 9 + 9 x^{2} + 9 (3 x) + 9 \cdot 9$ .

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Step 3.6.3.1.12.1

Reorder the factors in the terms $- 3 x \cdot 9$ and $9 (3 x)$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x \cdot x^{2} - 3 x (3 x) - 3 \cdot 9 x + 9 x^{2} + 3 \cdot 9 x + 9 \cdot 9}{x^{4}}$

Step 3.6.3.1.12.2

Add $- 3 \cdot 9 x$ and $3 \cdot 9 x$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x \cdot x^{2} - 3 x (3 x) + 9 x^{2} + 0 + 9 \cdot 9}{x^{4}}$

Step 3.6.3.1.12.3

Add $- 3 x \cdot x^{2} - 3 x (3 x) + 9 x^{2}$ and $0$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x \cdot x^{2} - 3 x (3 x) + 9 x^{2} + 9 \cdot 9}{x^{4}}$

Step 3.6.3.1.13

Simplify each term.

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Step 3.6.3.1.13.1

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 3.6.3.1.13.1.1

Move $x^{2}$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 (x^{2} x) - 3 x (3 x) + 9 x^{2} + 9 \cdot 9}{x^{4}}$

Step 3.6.3.1.13.1.2

Multiply $x^{2}$ by $x$ .

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Step 3.6.3.1.13.1.2.1

Raise $x$ to the power of $1$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 (x^{2} x^{1}) - 3 x (3 x) + 9 x^{2} + 9 \cdot 9}{x^{4}}$

Step 3.6.3.1.13.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x^{2 + 1} - 3 x (3 x) + 9 x^{2} + 9 \cdot 9}{x^{4}}$

Step 3.6.3.1.13.1.3

Add $2$ and $1$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x^{3} - 3 x (3 x) + 9 x^{2} + 9 \cdot 9}{x^{4}}$

Step 3.6.3.1.13.2

Rewrite using the commutative property of multiplication.

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x^{3} - 3 \cdot 3 x \cdot x + 9 x^{2} + 9 \cdot 9}{x^{4}}$

Step 3.6.3.1.13.3

Multiply $x$ by $x$ by adding the exponents.

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Step 3.6.3.1.13.3.1

Move $x$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x^{3} - 3 \cdot 3 (x \cdot x) + 9 x^{2} + 9 \cdot 9}{x^{4}}$

Step 3.6.3.1.13.3.2

Multiply $x$ by $x$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x^{3} - 3 \cdot 3 x^{2} + 9 x^{2} + 9 \cdot 9}{x^{4}}$

Step 3.6.3.1.13.4

Multiply $- 3$ by $3$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x^{3} - 9 x^{2} + 9 x^{2} + 9 \cdot 9}{x^{4}}$

Step 3.6.3.1.13.5

Multiply $9$ by $9$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x^{3} - 9 x^{2} + 9 x^{2} + 81}{x^{4}}$

Step 3.6.3.1.14

Combine the opposite terms in $- 3 x^{3} - 9 x^{2} + 9 x^{2} + 81$ .

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Step 3.6.3.1.14.1

Add $- 9 x^{2}$ and $9 x^{2}$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x^{3} + 0 + 81}{x^{4}}$

Step 3.6.3.1.14.2

Add $- 3 x^{3}$ and $0$ .

$\frac{2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x^{3} + 81}{x^{4}}$

Step 3.6.3.2

Combine the opposite terms in $2 x^{3} - 3 x^{2} - 9 x + x^{3} + 3 x^{2} + 9 x - 3 x^{3} + 81$ .

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Step 3.6.3.2.1

Add $- 3 x^{2}$ and $3 x^{2}$ .

$\frac{2 x^{3} - 9 x + x^{3} + 0 + 9 x - 3 x^{3} + 81}{x^{4}}$

Step 3.6.3.2.2

Add $2 x^{3} - 9 x + x^{3}$ and $0$ .

$\frac{2 x^{3} - 9 x + x^{3} + 9 x - 3 x^{3} + 81}{x^{4}}$

Step 3.6.3.2.3

Add $- 9 x$ and $9 x$ .

$\frac{2 x^{3} + x^{3} + 0 - 3 x^{3} + 81}{x^{4}}$

Step 3.6.3.2.4

Add $2 x^{3} + x^{3}$ and $0$ .

$\frac{2 x^{3} + x^{3} - 3 x^{3} + 81}{x^{4}}$

Step 3.6.3.3

Add $2 x^{3}$ and $x^{3}$ .

$\frac{3 x^{3} - 3 x^{3} + 81}{x^{4}}$

Step 3.6.3.4

Subtract $3 x^{3}$ from $3 x^{3}$ .

$\frac{0 + 81}{x^{4}}$

Step 3.6.3.5

Add $0$ and $81$ .

$\frac{81}{x^{4}}$

Step 4

Reform the equation by setting the left side equal to the right side.

$y' = \frac{81}{x^{4}}$

Step 5

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = \frac{81}{x^{4}}$