Calculus Examples

$x \sqrt{y + 1} = x y + 1$

Step 1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{y + 1}$ as ${(y + 1)}^{\frac{1}{2}}$ .

$x {(y + 1)}^{\frac{1}{2}} = x y + 1$

Step 2

Differentiate both sides of the equation.

$\frac{d}{d x} (x {(y + 1)}^{\frac{1}{2}}) = \frac{d}{d x} (x y + 1)$

Step 3

Differentiate the left side of the equation.

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Step 3.1

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = {(y + 1)}^{\frac{1}{2}}$ .

$x \frac{d}{d x} [{(y + 1)}^{\frac{1}{2}}] + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = y + 1$ .

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Step 3.2.1

To apply the Chain Rule, set $u$ as $y + 1$ .

$x (\frac{d}{d u} [u^{\frac{1}{2}}] \frac{d}{d x} [y + 1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{2}$ .

$x (\frac{1}{2} u^{\frac{1}{2} - 1} \frac{d}{d x} [y + 1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.2.3

Replace all occurrences of $u$ with $y + 1$ .

$x (\frac{1}{2} {(y + 1)}^{\frac{1}{2} - 1} \frac{d}{d x} [y + 1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$x (\frac{1}{2} {(y + 1)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [y + 1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.4

Combine $- 1$ and $\frac{2}{2}$ .

$x (\frac{1}{2} {(y + 1)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [y + 1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.5

Combine the numerators over the common denominator.

$x (\frac{1}{2} {(y + 1)}^{\frac{1 - 1 \cdot 2}{2}} \frac{d}{d x} [y + 1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.6

Simplify the numerator.

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Step 3.6.1

Multiply $- 1$ by $2$ .

$x (\frac{1}{2} {(y + 1)}^{\frac{1 - 2}{2}} \frac{d}{d x} [y + 1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.6.2

Subtract $2$ from $1$ .

$x (\frac{1}{2} {(y + 1)}^{\frac{- 1}{2}} \frac{d}{d x} [y + 1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.7

Combine fractions.

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Step 3.7.1

Move the negative in front of the fraction.

$x (\frac{1}{2} {(y + 1)}^{- \frac{1}{2}} \frac{d}{d x} [y + 1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.7.2

Combine $\frac{1}{2}$ and ${(y + 1)}^{- \frac{1}{2}}$ .

$x (\frac{{(y + 1)}^{- \frac{1}{2}}}{2} \frac{d}{d x} [y + 1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.7.3

Move ${(y + 1)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$x (\frac{1}{2 {(y + 1)}^{\frac{1}{2}}} \frac{d}{d x} [y + 1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.7.4

Combine $\frac{1}{2 {(y + 1)}^{\frac{1}{2}}}$ and $x$ .

$\frac{x}{2 {(y + 1)}^{\frac{1}{2}}} \frac{d}{d x} [y + 1] + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.8

By the Sum Rule, the derivative of $y + 1$ with respect to $x$ is $\frac{d}{d x} [y] + \frac{d}{d x} [1]$ .

$\frac{x}{2 {(y + 1)}^{\frac{1}{2}}} (\frac{d}{d x} [y] + \frac{d}{d x} [1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.9

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$\frac{x}{2 {(y + 1)}^{\frac{1}{2}}} (y' + \frac{d}{d x} [1]) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.10

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$\frac{x}{2 {(y + 1)}^{\frac{1}{2}}} (y' + 0) + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.11

Combine fractions.

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Step 3.11.1

Add $y'$ and $0$ .

$\frac{x}{2 {(y + 1)}^{\frac{1}{2}}} y' + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.11.2

Combine $\frac{x}{2 {(y + 1)}^{\frac{1}{2}}}$ and $y'$ .

$\frac{x y'}{2 {(y + 1)}^{\frac{1}{2}}} + {(y + 1)}^{\frac{1}{2}} \frac{d}{d x} [x]$

Step 3.12

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{x y'}{2 {(y + 1)}^{\frac{1}{2}}} + {(y + 1)}^{\frac{1}{2}} \cdot 1$

Step 3.13

Multiply ${(y + 1)}^{\frac{1}{2}}$ by $1$ .

$\frac{x y'}{2 {(y + 1)}^{\frac{1}{2}}} + {(y + 1)}^{\frac{1}{2}}$

Step 3.14

To write ${(y + 1)}^{\frac{1}{2}}$ as a fraction with a common denominator, multiply by $\frac{2 {(y + 1)}^{\frac{1}{2}}}{2 {(y + 1)}^{\frac{1}{2}}}$ .

$\frac{x y'}{2 {(y + 1)}^{\frac{1}{2}}} + {(y + 1)}^{\frac{1}{2}} \cdot \frac{2 {(y + 1)}^{\frac{1}{2}}}{2 {(y + 1)}^{\frac{1}{2}}}$

Step 3.15

Combine ${(y + 1)}^{\frac{1}{2}}$ and $\frac{2 {(y + 1)}^{\frac{1}{2}}}{2 {(y + 1)}^{\frac{1}{2}}}$ .

$\frac{x y'}{2 {(y + 1)}^{\frac{1}{2}}} + \frac{{(y + 1)}^{\frac{1}{2}} (2 {(y + 1)}^{\frac{1}{2}})}{2 {(y + 1)}^{\frac{1}{2}}}$

Step 3.16

Combine the numerators over the common denominator.

$\frac{x y' + {(y + 1)}^{\frac{1}{2}} (2 {(y + 1)}^{\frac{1}{2}})}{2 {(y + 1)}^{\frac{1}{2}}}$

Step 3.17

Multiply ${(y + 1)}^{\frac{1}{2}}$ by ${(y + 1)}^{\frac{1}{2}}$ by adding the exponents.

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Step 3.17.1

Move ${(y + 1)}^{\frac{1}{2}}$ .

$\frac{x y' + {(y + 1)}^{\frac{1}{2}} {(y + 1)}^{\frac{1}{2}} \cdot 2}{2 {(y + 1)}^{\frac{1}{2}}}$

Step 3.17.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{x y' + {(y + 1)}^{\frac{1}{2} + \frac{1}{2}} \cdot 2}{2 {(y + 1)}^{\frac{1}{2}}}$

Step 3.17.3

Combine the numerators over the common denominator.

$\frac{x y' + {(y + 1)}^{\frac{1 + 1}{2}} \cdot 2}{2 {(y + 1)}^{\frac{1}{2}}}$

Step 3.17.4

Add $1$ and $1$ .

$\frac{x y' + {(y + 1)}^{\frac{2}{2}} \cdot 2}{2 {(y + 1)}^{\frac{1}{2}}}$

Step 3.17.5

Divide $2$ by $2$ .

$\frac{x y' + {(y + 1)}^{1} \cdot 2}{2 {(y + 1)}^{\frac{1}{2}}}$

Step 3.18

Simplify ${(y + 1)}^{1} \cdot 2$ .

$\frac{x y' + (y + 1) \cdot 2}{2 {(y + 1)}^{\frac{1}{2}}}$

Step 3.19

Move $2$ to the left of $y + 1$ .

$\frac{x y' + 2 \cdot (y + 1)}{2 {(y + 1)}^{\frac{1}{2}}}$

Step 3.20

Simplify.

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Step 3.20.1

Apply the distributive property.

$\frac{x y' + 2 y + 2 \cdot 1}{2 {(y + 1)}^{\frac{1}{2}}}$

Step 3.20.2

Multiply $2$ by $1$ .

$\frac{x y' + 2 y + 2}{2 {(y + 1)}^{\frac{1}{2}}}$

Step 4

Differentiate the right side of the equation.

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Step 4.1

By the Sum Rule, the derivative of $x y + 1$ with respect to $x$ is $\frac{d}{d x} [x y] + \frac{d}{d x} [1]$ .

$\frac{d}{d x} [x y] + \frac{d}{d x} [1]$

Step 4.2

Evaluate $\frac{d}{d x} [x y]$ .

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Step 4.2.1

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = y$ .

$x \frac{d}{d x} [y] + y \frac{d}{d x} [x] + \frac{d}{d x} [1]$

Step 4.2.2

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$x y' + y \frac{d}{d x} [x] + \frac{d}{d x} [1]$

Step 4.2.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$x y' + y \cdot 1 + \frac{d}{d x} [1]$

Step 4.2.4

Multiply $y$ by $1$ .

$x y' + y + \frac{d}{d x} [1]$

Step 4.3

Differentiate using the Constant Rule.

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Step 4.3.1

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$x y' + y + 0$

Step 4.3.2

Add $x y' + y$ and $0$ .

$x y' + y$

Step 5

Reform the equation by setting the left side equal to the right side.

$\frac{x y' + 2 y + 2}{2 {(y + 1)}^{\frac{1}{2}}} = x y' + y$

Step 6

Solve for $y'$ .

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Step 6.1

Multiply both sides by $2 {(y + 1)}^{\frac{1}{2}}$ .

$\frac{x y' + 2 y + 2}{2 {(y + 1)}^{\frac{1}{2}}} (2 {(y + 1)}^{\frac{1}{2}}) = (x y' + y) (2 {(y + 1)}^{\frac{1}{2}})$

Step 6.2

Simplify.

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Step 6.2.1

Simplify the left side.

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Step 6.2.1.1

Simplify $\frac{x y' + 2 y + 2}{2 {(y + 1)}^{\frac{1}{2}}} (2 {(y + 1)}^{\frac{1}{2}})$ .

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Step 6.2.1.1.1

Rewrite using the commutative property of multiplication.

$2 \frac{x y' + 2 y + 2}{2 {(y + 1)}^{\frac{1}{2}}} {(y + 1)}^{\frac{1}{2}} = (x y' + y) (2 {(y + 1)}^{\frac{1}{2}})$

Step 6.2.1.1.2

Cancel the common factor of $2$ .

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Step 6.2.1.1.2.1

Cancel the common factor.

$2 \frac{x y' + 2 y + 2}{2 {(y + 1)}^{\frac{1}{2}}} {(y + 1)}^{\frac{1}{2}} = (x y' + y) (2 {(y + 1)}^{\frac{1}{2}})$

Step 6.2.1.1.2.2

Rewrite the expression.

$\frac{x y' + 2 y + 2}{{(y + 1)}^{\frac{1}{2}}} {(y + 1)}^{\frac{1}{2}} = (x y' + y) (2 {(y + 1)}^{\frac{1}{2}})$

Step 6.2.1.1.3

Cancel the common factor of ${(y + 1)}^{\frac{1}{2}}$ .

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Step 6.2.1.1.3.1

Cancel the common factor.

$\frac{x y' + 2 y + 2}{{(y + 1)}^{\frac{1}{2}}} {(y + 1)}^{\frac{1}{2}} = (x y' + y) (2 {(y + 1)}^{\frac{1}{2}})$

Step 6.2.1.1.3.2

Rewrite the expression.

$x y' + 2 y + 2 = (x y' + y) (2 {(y + 1)}^{\frac{1}{2}})$

Step 6.2.1.1.4

Reorder $x$ and $y'$ .

$y' x + 2 y + 2 = (x y' + y) (2 {(y + 1)}^{\frac{1}{2}})$

Step 6.2.2

Simplify the right side.

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Step 6.2.2.1

Simplify $(x y' + y) (2 {(y + 1)}^{\frac{1}{2}})$ .

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Step 6.2.2.1.1

Apply the distributive property.

$y' x + 2 y + 2 = x y' (2 {(y + 1)}^{\frac{1}{2}}) + y (2 {(y + 1)}^{\frac{1}{2}})$

Step 6.2.2.1.2

Reorder.

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Step 6.2.2.1.2.1

Rewrite using the commutative property of multiplication.

$y' x + 2 y + 2 = 2 x y' {(y + 1)}^{\frac{1}{2}} + y (2 {(y + 1)}^{\frac{1}{2}})$

Step 6.2.2.1.2.2

Rewrite using the commutative property of multiplication.

$y' x + 2 y + 2 = 2 x y' {(y + 1)}^{\frac{1}{2}} + 2 y {(y + 1)}^{\frac{1}{2}}$

Step 6.2.2.1.2.3

Move $x$ .

$y' x + 2 y + 2 = 2 y' x {(y + 1)}^{\frac{1}{2}} + 2 y {(y + 1)}^{\frac{1}{2}}$

Step 6.3

Solve for $y'$ .

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Step 6.3.1

Subtract $2 y' x {(y + 1)}^{\frac{1}{2}}$ from both sides of the equation.

$y' x + 2 y + 2 - 2 y' x {(y + 1)}^{\frac{1}{2}} = 2 y {(y + 1)}^{\frac{1}{2}}$

Step 6.3.2

Move all terms not containing $y'$ to the right side of the equation.

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Step 6.3.2.1

Subtract $2 y$ from both sides of the equation.

$y' x + 2 - 2 y' x {(y + 1)}^{\frac{1}{2}} = 2 y {(y + 1)}^{\frac{1}{2}} - 2 y$

Step 6.3.2.2

Subtract $2$ from both sides of the equation.

$y' x - 2 y' x {(y + 1)}^{\frac{1}{2}} = 2 y {(y + 1)}^{\frac{1}{2}} - 2 y - 2$

Step 6.3.3

Factor $y' x$ out of $y' x - 2 y' x {(y + 1)}^{\frac{1}{2}}$ .

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Step 6.3.3.1

Factor $y' x$ out of $y' x$ .

$y' x \cdot 1 - 2 y' x {(y + 1)}^{\frac{1}{2}} = 2 y {(y + 1)}^{\frac{1}{2}} - 2 y - 2$

Step 6.3.3.2

Factor $y' x$ out of $- 2 y' x {(y + 1)}^{\frac{1}{2}}$ .

$y' x \cdot 1 + y' x (- 2 {(y + 1)}^{\frac{1}{2}}) = 2 y {(y + 1)}^{\frac{1}{2}} - 2 y - 2$

Step 6.3.3.3

Factor $y' x$ out of $y' x \cdot 1 + y' x (- 2 {(y + 1)}^{\frac{1}{2}})$ .

$y' x (1 - 2 {(y + 1)}^{\frac{1}{2}}) = 2 y {(y + 1)}^{\frac{1}{2}} - 2 y - 2$

Step 6.3.4

Divide each term in $y' x (1 - 2 {(y + 1)}^{\frac{1}{2}}) = 2 y {(y + 1)}^{\frac{1}{2}} - 2 y - 2$ by $x (1 - 2 {(y + 1)}^{\frac{1}{2}})$ and simplify.

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Step 6.3.4.1

Divide each term in $y' x (1 - 2 {(y + 1)}^{\frac{1}{2}}) = 2 y {(y + 1)}^{\frac{1}{2}} - 2 y - 2$ by $x (1 - 2 {(y + 1)}^{\frac{1}{2}})$ .

$\frac{y' x (1 - 2 {(y + 1)}^{\frac{1}{2}})}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} = \frac{2 y {(y + 1)}^{\frac{1}{2}}}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} + \frac{- 2 y}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} + \frac{- 2}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.2

Simplify the left side.

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Step 6.3.4.2.1

Cancel the common factor.

Step 6.3.4.2.2

Rewrite the expression.

$\frac{y' (1 - 2 {(y + 1)}^{\frac{1}{2}})}{1 - 2 {(y + 1)}^{\frac{1}{2}}} = \frac{2 y {(y + 1)}^{\frac{1}{2}}}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} + \frac{- 2 y}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} + \frac{- 2}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.2.3

Cancel the common factor.

Step 6.3.4.2.4

Divide $y'$ by $1$ .

$y' = \frac{2 y {(y + 1)}^{\frac{1}{2}}}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} + \frac{- 2 y}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} + \frac{- 2}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3

Simplify the right side.

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Step 6.3.4.3.1

Simplify terms.

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Step 6.3.4.3.1.1

Simplify each term.

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Step 6.3.4.3.1.1.1

Move the negative in front of the fraction.

$y' = \frac{2 y {(y + 1)}^{\frac{1}{2}}}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} - \frac{2 y}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} + \frac{- 2}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3.1.1.2

Move the negative in front of the fraction.

$y' = \frac{2 y {(y + 1)}^{\frac{1}{2}}}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} - \frac{2 y}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} - \frac{2}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3.1.2

Simplify terms.

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Step 6.3.4.3.1.2.1

Combine the numerators over the common denominator.

$y' = \frac{2 y {(y + 1)}^{\frac{1}{2}} - 2 y}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} - \frac{2}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3.1.2.2

Factor $2 y$ out of $2 y {(y + 1)}^{\frac{1}{2}} - 2 y$ .

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Step 6.3.4.3.1.2.2.1

Factor $2 y$ out of $2 y {(y + 1)}^{\frac{1}{2}}$ .

$y' = \frac{2 y ({(y + 1)}^{\frac{1}{2}}) - 2 y}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} - \frac{2}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3.1.2.2.2

Factor $2 y$ out of $- 2 y$ .

$y' = \frac{2 y ({(y + 1)}^{\frac{1}{2}}) + 2 y (- 1)}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} - \frac{2}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3.1.2.2.3

Factor $2 y$ out of $2 y ({(y + 1)}^{\frac{1}{2}}) + 2 y (- 1)$ .

$y' = \frac{2 y ({(y + 1)}^{\frac{1}{2}} - 1)}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})} - \frac{2}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3.1.2.3

Combine the numerators over the common denominator.

$y' = \frac{2 y ({(y + 1)}^{\frac{1}{2}} - 1) - 2}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3.2

Simplify the numerator.

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Step 6.3.4.3.2.1

Factor $2$ out of $2 y ({(y + 1)}^{\frac{1}{2}} - 1) - 2$ .

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Step 6.3.4.3.2.1.1

Factor $2$ out of $2 y ({(y + 1)}^{\frac{1}{2}} - 1)$ .

$y' = \frac{2 (y ({(y + 1)}^{\frac{1}{2}} - 1)) - 2}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3.2.1.2

Factor $2$ out of $- 2$ .

$y' = \frac{2 (y ({(y + 1)}^{\frac{1}{2}} - 1)) + 2 (- 1)}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3.2.1.3

Factor $2$ out of $2 (y ({(y + 1)}^{\frac{1}{2}} - 1)) + 2 (- 1)$ .

$y' = \frac{2 (y ({(y + 1)}^{\frac{1}{2}} - 1) - 1)}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3.2.2

Apply the distributive property.

$y' = \frac{2 (y {(y + 1)}^{\frac{1}{2}} + y \cdot - 1 - 1)}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3.2.3

Move $- 1$ to the left of $y$ .

$y' = \frac{2 (y {(y + 1)}^{\frac{1}{2}} - 1 \cdot y - 1)}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 6.3.4.3.2.4

Rewrite $- 1 y$ as $- y$ .

$y' = \frac{2 (y {(y + 1)}^{\frac{1}{2}} - y - 1)}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$

Step 7

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = \frac{2 (y {(y + 1)}^{\frac{1}{2}} - y - 1)}{x (1 - 2 {(y + 1)}^{\frac{1}{2}})}$