Calculus Examples

$y = {(x^{2} + 2 x)}^{\frac{1}{3}}$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (y) = \frac{d}{d x} ({(x^{2} + 2 x)}^{\frac{1}{3}})$

Step 2

The derivative of $y$ with respect to $x$ is $y'$ .

$y'$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{3}}$ and $g (x) = x^{2} + 2 x$ .

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Step 3.1.1

To apply the Chain Rule, set $u$ as $x^{2} + 2 x$ .

$\frac{d}{d u} [u^{\frac{1}{3}}] \frac{d}{d x} [x^{2} + 2 x]$

Step 3.1.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{3}$ .

$\frac{1}{3} u^{\frac{1}{3} - 1} \frac{d}{d x} [x^{2} + 2 x]$

Step 3.1.3

Replace all occurrences of $u$ with $x^{2} + 2 x$ .

$\frac{1}{3} {(x^{2} + 2 x)}^{\frac{1}{3} - 1} \frac{d}{d x} [x^{2} + 2 x]$

Step 3.2

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{1}{3} {(x^{2} + 2 x)}^{\frac{1}{3} - 1 \cdot \frac{3}{3}} \frac{d}{d x} [x^{2} + 2 x]$

Step 3.3

Combine $- 1$ and $\frac{3}{3}$ .

$\frac{1}{3} {(x^{2} + 2 x)}^{\frac{1}{3} + \frac{- 1 \cdot 3}{3}} \frac{d}{d x} [x^{2} + 2 x]$

Step 3.4

Combine the numerators over the common denominator.

$\frac{1}{3} {(x^{2} + 2 x)}^{\frac{1 - 1 \cdot 3}{3}} \frac{d}{d x} [x^{2} + 2 x]$

Step 3.5

Simplify the numerator.

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Step 3.5.1

Multiply $- 1$ by $3$ .

$\frac{1}{3} {(x^{2} + 2 x)}^{\frac{1 - 3}{3}} \frac{d}{d x} [x^{2} + 2 x]$

Step 3.5.2

Subtract $3$ from $1$ .

$\frac{1}{3} {(x^{2} + 2 x)}^{\frac{- 2}{3}} \frac{d}{d x} [x^{2} + 2 x]$

Step 3.6

Combine fractions.

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Step 3.6.1

Move the negative in front of the fraction.

$\frac{1}{3} {(x^{2} + 2 x)}^{- \frac{2}{3}} \frac{d}{d x} [x^{2} + 2 x]$

Step 3.6.2

Combine $\frac{1}{3}$ and ${(x^{2} + 2 x)}^{- \frac{2}{3}}$ .

$\frac{{(x^{2} + 2 x)}^{- \frac{2}{3}}}{3} \frac{d}{d x} [x^{2} + 2 x]$

Step 3.6.3

Move ${(x^{2} + 2 x)}^{- \frac{2}{3}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}} \frac{d}{d x} [x^{2} + 2 x]$

Step 3.7

By the Sum Rule, the derivative of $x^{2} + 2 x$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [2 x]$ .

$\frac{1}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [2 x])$

Step 3.8

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{1}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}} (2 x + \frac{d}{d x} [2 x])$

Step 3.9

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$\frac{1}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}} (2 x + 2 \frac{d}{d x} [x])$

Step 3.10

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{1}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}} (2 x + 2 \cdot 1)$

Step 3.11

Multiply $2$ by $1$ .

$\frac{1}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}} (2 x + 2)$

Step 3.12

Simplify.

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Step 3.12.1

Reorder the factors of $\frac{1}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}} (2 x + 2)$ .

$(2 x + 2) \frac{1}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}}$

Step 3.12.2

Multiply $2 x + 2$ by $\frac{1}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}}$ .

$\frac{2 x + 2}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}}$

Step 3.12.3

Factor $2$ out of $2 x + 2$ .

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Step 3.12.3.1

Factor $2$ out of $2 x$ .

$\frac{2 (x) + 2}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}}$

Step 3.12.3.2

Factor $2$ out of $2$ .

$\frac{2 (x) + 2 (1)}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}}$

Step 3.12.3.3

Factor $2$ out of $2 (x) + 2 (1)$ .

$\frac{2 (x + 1)}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}}$

Step 4

Reform the equation by setting the left side equal to the right side.

$y' = \frac{2 (x + 1)}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}}$

Step 5

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = \frac{2 (x + 1)}{3 {(x^{2} + 2 x)}^{\frac{2}{3}}}$