Calculus Examples

$y = \frac{x + 1}{5 x - 1}$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (y) = \frac{d}{d x} (\frac{x + 1}{5 x - 1})$

Step 2

The derivative of $y$ with respect to $x$ is $y'$ .

$y'$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = x + 1$ and $g (x) = 5 x - 1$ .

$\frac{(5 x - 1) \frac{d}{d x} [x + 1] - (x + 1) \frac{d}{d x} [5 x - 1]}{{(5 x - 1)}^{2}}$

Step 3.2

Differentiate.

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Step 3.2.1

By the Sum Rule, the derivative of $x + 1$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [1]$ .

$\frac{(5 x - 1) (\frac{d}{d x} [x] + \frac{d}{d x} [1]) - (x + 1) \frac{d}{d x} [5 x - 1]}{{(5 x - 1)}^{2}}$

Step 3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{(5 x - 1) (1 + \frac{d}{d x} [1]) - (x + 1) \frac{d}{d x} [5 x - 1]}{{(5 x - 1)}^{2}}$

Step 3.2.3

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$\frac{(5 x - 1) (1 + 0) - (x + 1) \frac{d}{d x} [5 x - 1]}{{(5 x - 1)}^{2}}$

Step 3.2.4

Simplify the expression.

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Step 3.2.4.1

Add $1$ and $0$ .

$\frac{(5 x - 1) \cdot 1 - (x + 1) \frac{d}{d x} [5 x - 1]}{{(5 x - 1)}^{2}}$

Step 3.2.4.2

Multiply $5 x - 1$ by $1$ .

$\frac{5 x - 1 - (x + 1) \frac{d}{d x} [5 x - 1]}{{(5 x - 1)}^{2}}$

Step 3.2.5

By the Sum Rule, the derivative of $5 x - 1$ with respect to $x$ is $\frac{d}{d x} [5 x] + \frac{d}{d x} [- 1]$ .

$\frac{5 x - 1 - (x + 1) (\frac{d}{d x} [5 x] + \frac{d}{d x} [- 1])}{{(5 x - 1)}^{2}}$

Step 3.2.6

Since $5$ is constant with respect to $x$ , the derivative of $5 x$ with respect to $x$ is $5 \frac{d}{d x} [x]$ .

$\frac{5 x - 1 - (x + 1) (5 \frac{d}{d x} [x] + \frac{d}{d x} [- 1])}{{(5 x - 1)}^{2}}$

Step 3.2.7

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{5 x - 1 - (x + 1) (5 \cdot 1 + \frac{d}{d x} [- 1])}{{(5 x - 1)}^{2}}$

Step 3.2.8

Multiply $5$ by $1$ .

$\frac{5 x - 1 - (x + 1) (5 + \frac{d}{d x} [- 1])}{{(5 x - 1)}^{2}}$

Step 3.2.9

Since $- 1$ is constant with respect to $x$ , the derivative of $- 1$ with respect to $x$ is $0$ .

$\frac{5 x - 1 - (x + 1) (5 + 0)}{{(5 x - 1)}^{2}}$

Step 3.2.10

Simplify the expression.

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Step 3.2.10.1

Add $5$ and $0$ .

$\frac{5 x - 1 - (x + 1) \cdot 5}{{(5 x - 1)}^{2}}$

Step 3.2.10.2

Multiply $5$ by $- 1$ .

$\frac{5 x - 1 - 5 (x + 1)}{{(5 x - 1)}^{2}}$

Step 3.3

Simplify.

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Step 3.3.1

Apply the distributive property.

$\frac{5 x - 1 - 5 x - 5 \cdot 1}{{(5 x - 1)}^{2}}$

Step 3.3.2

Simplify the numerator.

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Step 3.3.2.1

Combine the opposite terms in $5 x - 1 - 5 x - 5 \cdot 1$ .

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Step 3.3.2.1.1

Subtract $5 x$ from $5 x$ .

$\frac{0 - 1 - 5 \cdot 1}{{(5 x - 1)}^{2}}$

Step 3.3.2.1.2

Subtract $1$ from $0$ .

$\frac{- 1 - 5 \cdot 1}{{(5 x - 1)}^{2}}$

Step 3.3.2.2

Multiply $- 5$ by $1$ .

$\frac{- 1 - 5}{{(5 x - 1)}^{2}}$

Step 3.3.2.3

Subtract $5$ from $- 1$ .

$\frac{- 6}{{(5 x - 1)}^{2}}$

Step 3.3.3

Move the negative in front of the fraction.

$- \frac{6}{{(5 x - 1)}^{2}}$

Step 4

Reform the equation by setting the left side equal to the right side.

$y' = - \frac{6}{{(5 x - 1)}^{2}}$

Step 5

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = - \frac{6}{{(5 x - 1)}^{2}}$