Calculus Examples

Find dy/dx y=sec(tan(x))
y=sec(tan(x))y=sec(tan(x))
Step 1
Differentiate both sides of the equation.
ddx(y)=ddx(sec(tan(x)))ddx(y)=ddx(sec(tan(x)))
Step 2
The derivative of yy with respect to xx is y.
y
Step 3
Differentiate the right side of the equation.
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Step 3.1
Differentiate using the chain rule, which states that ddx[f(g(x))] is f(g(x))g(x) where f(x)=sec(x) and g(x)=tan(x).
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Step 3.1.1
To apply the Chain Rule, set u as tan(x).
ddu[sec(u)]ddx[tan(x)]
Step 3.1.2
The derivative of sec(u) with respect to u is sec(u)tan(u).
sec(u)tan(u)ddx[tan(x)]
Step 3.1.3
Replace all occurrences of u with tan(x).
sec(tan(x))tan(tan(x))ddx[tan(x)]
sec(tan(x))tan(tan(x))ddx[tan(x)]
Step 3.2
The derivative of tan(x) with respect to x is sec2(x).
sec(tan(x))tan(tan(x))sec2(x)
Step 3.3
Reorder the factors of sec(tan(x))tan(tan(x))sec2(x).
sec2(x)sec(tan(x))tan(tan(x))
sec2(x)sec(tan(x))tan(tan(x))
Step 4
Reform the equation by setting the left side equal to the right side.
y=sec2(x)sec(tan(x))tan(tan(x))
Step 5
Replace y with dydx.
dydx=sec2(x)sec(tan(x))tan(tan(x))
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