Calculus Examples

$y = 9 e^{x} + \frac{4}{\sqrt[3]{x}}$

Step 1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{x}$ as $x^{\frac{1}{3}}$ .

$y = 9 e^{x} + \frac{4}{x^{\frac{1}{3}}}$

Step 2

Differentiate both sides of the equation.

$\frac{d}{d x} (y) = \frac{d}{d x} (9 e^{x} + \frac{4}{x^{\frac{1}{3}}})$

Step 3

The derivative of $y$ with respect to $x$ is $y'$ .

$y'$

Step 4

Differentiate the right side of the equation.

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Step 4.1

By the Sum Rule, the derivative of $9 e^{x} + \frac{4}{x^{\frac{1}{3}}}$ with respect to $x$ is $\frac{d}{d x} [9 e^{x}] + \frac{d}{d x} [\frac{4}{x^{\frac{1}{3}}}]$ .

$\frac{d}{d x} [9 e^{x}] + \frac{d}{d x} [\frac{4}{x^{\frac{1}{3}}}]$

Step 4.2

Evaluate $\frac{d}{d x} [9 e^{x}]$ .

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Step 4.2.1

Since $9$ is constant with respect to $x$ , the derivative of $9 e^{x}$ with respect to $x$ is $9 \frac{d}{d x} [e^{x}]$ .

$9 \frac{d}{d x} [e^{x}] + \frac{d}{d x} [\frac{4}{x^{\frac{1}{3}}}]$

Step 4.2.2

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$9 e^{x} + \frac{d}{d x} [\frac{4}{x^{\frac{1}{3}}}]$

Step 4.3

Evaluate $\frac{d}{d x} [\frac{4}{x^{\frac{1}{3}}}]$ .

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Step 4.3.1

Since $4$ is constant with respect to $x$ , the derivative of $\frac{4}{x^{\frac{1}{3}}}$ with respect to $x$ is $4 \frac{d}{d x} [\frac{1}{x^{\frac{1}{3}}}]$ .

$9 e^{x} + 4 \frac{d}{d x} [\frac{1}{x^{\frac{1}{3}}}]$

Step 4.3.2

Rewrite $\frac{1}{x^{\frac{1}{3}}}$ as ${(x^{\frac{1}{3}})}^{- 1}$ .

$9 e^{x} + 4 \frac{d}{d x} [{(x^{\frac{1}{3}})}^{- 1}]$

Step 4.3.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{- 1}$ and $g (x) = x^{\frac{1}{3}}$ .

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Step 4.3.3.1

To apply the Chain Rule, set $u$ as $x^{\frac{1}{3}}$ .

$9 e^{x} + 4 (\frac{d}{d u} [u^{- 1}] \frac{d}{d x} [x^{\frac{1}{3}}])$

Step 4.3.3.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = - 1$ .

$9 e^{x} + 4 (- u^{- 2} \frac{d}{d x} [x^{\frac{1}{3}}])$

Step 4.3.3.3

Replace all occurrences of $u$ with $x^{\frac{1}{3}}$ .

$9 e^{x} + 4 (- {(x^{\frac{1}{3}})}^{- 2} \frac{d}{d x} [x^{\frac{1}{3}}])$

Step 4.3.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = \frac{1}{3}$ .

$9 e^{x} + 4 (- {(x^{\frac{1}{3}})}^{- 2} (\frac{1}{3} x^{\frac{1}{3} - 1}))$

Step 4.3.5

Multiply the exponents in ${(x^{\frac{1}{3}})}^{- 2}$ .

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Step 4.3.5.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$9 e^{x} + 4 (- x^{\frac{1}{3} \cdot - 2} (\frac{1}{3} x^{\frac{1}{3} - 1}))$

Step 4.3.5.2

Combine $\frac{1}{3}$ and $- 2$ .

$9 e^{x} + 4 (- x^{\frac{- 2}{3}} (\frac{1}{3} x^{\frac{1}{3} - 1}))$

Step 4.3.5.3

Move the negative in front of the fraction.

$9 e^{x} + 4 (- x^{- \frac{2}{3}} (\frac{1}{3} x^{\frac{1}{3} - 1}))$

Step 4.3.6

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$9 e^{x} + 4 (- x^{- \frac{2}{3}} (\frac{1}{3} x^{\frac{1}{3} - 1 \cdot \frac{3}{3}}))$

Step 4.3.7

Combine $- 1$ and $\frac{3}{3}$ .

$9 e^{x} + 4 (- x^{- \frac{2}{3}} (\frac{1}{3} x^{\frac{1}{3} + \frac{- 1 \cdot 3}{3}}))$

Step 4.3.8

Combine the numerators over the common denominator.

$9 e^{x} + 4 (- x^{- \frac{2}{3}} (\frac{1}{3} x^{\frac{1 - 1 \cdot 3}{3}}))$

Step 4.3.9

Simplify the numerator.

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Step 4.3.9.1

Multiply $- 1$ by $3$ .

$9 e^{x} + 4 (- x^{- \frac{2}{3}} (\frac{1}{3} x^{\frac{1 - 3}{3}}))$

Step 4.3.9.2

Subtract $3$ from $1$ .

$9 e^{x} + 4 (- x^{- \frac{2}{3}} (\frac{1}{3} x^{\frac{- 2}{3}}))$

Step 4.3.10

Move the negative in front of the fraction.

$9 e^{x} + 4 (- x^{- \frac{2}{3}} (\frac{1}{3} x^{- \frac{2}{3}}))$

Step 4.3.11

Combine $\frac{1}{3}$ and $x^{- \frac{2}{3}}$ .

$9 e^{x} + 4 (- x^{- \frac{2}{3}} \frac{x^{- \frac{2}{3}}}{3})$

Step 4.3.12

Combine $\frac{x^{- \frac{2}{3}}}{3}$ and $x^{- \frac{2}{3}}$ .

$9 e^{x} + 4 (- \frac{x^{- \frac{2}{3}} x^{- \frac{2}{3}}}{3})$

Step 4.3.13

Multiply $x^{- \frac{2}{3}}$ by $x^{- \frac{2}{3}}$ by adding the exponents.

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Step 4.3.13.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$9 e^{x} + 4 (- \frac{x^{- \frac{2}{3} - \frac{2}{3}}}{3})$

Step 4.3.13.2

Combine the numerators over the common denominator.

$9 e^{x} + 4 (- \frac{x^{\frac{- 2 - 2}{3}}}{3})$

Step 4.3.13.3

Subtract $2$ from $- 2$ .

$9 e^{x} + 4 (- \frac{x^{\frac{- 4}{3}}}{3})$

Step 4.3.13.4

Move the negative in front of the fraction.

$9 e^{x} + 4 (- \frac{x^{- \frac{4}{3}}}{3})$

Step 4.3.14

Move $x^{- \frac{4}{3}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$9 e^{x} + 4 (- \frac{1}{3 x^{\frac{4}{3}}})$

Step 4.3.15

Multiply $- 1$ by $4$ .

$9 e^{x} - 4 \frac{1}{3 x^{\frac{4}{3}}}$

Step 4.3.16

Combine $- 4$ and $\frac{1}{3 x^{\frac{4}{3}}}$ .

$9 e^{x} + \frac{- 4}{3 x^{\frac{4}{3}}}$

Step 4.3.17

Move the negative in front of the fraction.

$9 e^{x} - \frac{4}{3 x^{\frac{4}{3}}}$

Step 5

Reform the equation by setting the left side equal to the right side.

$y' = 9 e^{x} - \frac{4}{3 x^{\frac{4}{3}}}$

Step 6

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = 9 e^{x} - \frac{4}{3 x^{\frac{4}{3}}}$