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Calculus Examples
f(x)=√xx-4√x+4f(x)=√xx−4√x+4
Step 1
Find where the expression √xx-4√x+4 is undefined.
x<0,x=4
Step 2
Since √xx-4√x+4→∞ as x→4 from the left and √xx-4√x+4→∞ as x→4 from the right, then x=4 is a vertical asymptote.
x=4
Step 3
Step 3.1
Divide the numerator and denominator by the highest power of x in the denominator, which is √x2=x.
limx→∞√xx2xx+-4√xx+4x
Step 3.2
Evaluate the limit.
Step 3.2.1
Simplify each term.
limx→∞√xx21-4√xx+4x
Step 3.2.2
Cancel the common factor of x and x2.
Step 3.2.2.1
Raise x to the power of 1.
limx→∞√x1x21-4√xx+4x
Step 3.2.2.2
Factor x out of x1.
limx→∞√x⋅1x21-4√xx+4x
Step 3.2.2.3
Cancel the common factors.
Step 3.2.2.3.1
Factor x out of x2.
limx→∞√x⋅1x⋅x1-4√xx+4x
Step 3.2.2.3.2
Cancel the common factor.
limx→∞√x⋅1x⋅x1-4√xx+4x
Step 3.2.2.3.3
Rewrite the expression.
limx→∞√1x1-4√xx+4x
limx→∞√1x1-4√xx+4x
limx→∞√1x1-4√xx+4x
Step 3.2.3
Split the limit using the Limits Quotient Rule on the limit as x approaches ∞.
limx→∞√1xlimx→∞1-4√xx+4x
Step 3.2.4
Move the limit under the radical sign.
√limx→∞1xlimx→∞1-4√xx+4x
√limx→∞1xlimx→∞1-4√xx+4x
Step 3.3
Since its numerator approaches a real number while its denominator is unbounded, the fraction 1x approaches 0.
√0limx→∞1-4√xx+4x
Step 3.4
Evaluate the limit.
Step 3.4.1
Split the limit using the Sum of Limits Rule on the limit as x approaches ∞.
√0limx→∞1-limx→∞4√xx+limx→∞4x
Step 3.4.2
Evaluate the limit of 1 which is constant as x approaches ∞.
√01-limx→∞4√xx+limx→∞4x
Step 3.4.3
Move the term 4 outside of the limit because it is constant with respect to x.
√01-4limx→∞√xx+limx→∞4x
√01-4limx→∞√xx+limx→∞4x
Step 3.5
Apply L'Hospital's rule.
Step 3.5.1
Evaluate the limit of the numerator and the limit of the denominator.
Step 3.5.1.1
Take the limit of the numerator and the limit of the denominator.
√01-4limx→∞√xlimx→∞x+limx→∞4x
Step 3.5.1.2
As x approaches ∞ for radicals, the value goes to ∞.
√01-4∞limx→∞x+limx→∞4x
Step 3.5.1.3
The limit at infinity of a polynomial whose leading coefficient is positive is infinity.
√01-4∞∞+limx→∞4x
Step 3.5.1.4
Infinity divided by infinity is undefined.
Undefined
√01-4∞∞+limx→∞4x
Step 3.5.2
Since ∞∞ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.
limx→∞√xx=limx→∞ddx[√x]ddx[x]
Step 3.5.3
Find the derivative of the numerator and denominator.
Step 3.5.3.1
Differentiate the numerator and denominator.
√01-4limx→∞ddx[√x]ddx[x]+limx→∞4x
Step 3.5.3.2
Use n√ax=axn to rewrite √x as x12.
√01-4limx→∞ddx[x12]ddx[x]+limx→∞4x
Step 3.5.3.3
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=12.
√01-4limx→∞12x12-1ddx[x]+limx→∞4x
Step 3.5.3.4
To write -1 as a fraction with a common denominator, multiply by 22.
√01-4limx→∞12x12-1⋅22ddx[x]+limx→∞4x
Step 3.5.3.5
Combine -1 and 22.
√01-4limx→∞12x12+-1⋅22ddx[x]+limx→∞4x
Step 3.5.3.6
Combine the numerators over the common denominator.
√01-4limx→∞12x1-1⋅22ddx[x]+limx→∞4x
Step 3.5.3.7
Simplify the numerator.
Step 3.5.3.7.1
Multiply -1 by 2.
√01-4limx→∞12x1-22ddx[x]+limx→∞4x
Step 3.5.3.7.2
Subtract 2 from 1.
√01-4limx→∞12x-12ddx[x]+limx→∞4x
√01-4limx→∞12x-12ddx[x]+limx→∞4x
Step 3.5.3.8
Move the negative in front of the fraction.
√01-4limx→∞12x-12ddx[x]+limx→∞4x
Step 3.5.3.9
Simplify.
Step 3.5.3.9.1
Rewrite the expression using the negative exponent rule b-n=1bn.
√01-4limx→∞12⋅1x12ddx[x]+limx→∞4x
Step 3.5.3.9.2
Multiply 12 by 1x12.
√01-4limx→∞12x12ddx[x]+limx→∞4x
√01-4limx→∞12x12ddx[x]+limx→∞4x
Step 3.5.3.10
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.
√01-4limx→∞12x121+limx→∞4x
√01-4limx→∞12x121+limx→∞4x
Step 3.5.4
Multiply the numerator by the reciprocal of the denominator.
√01-4limx→∞12x12⋅1+limx→∞4x
Step 3.5.5
Rewrite x12 as √x.
√01-4limx→∞12√x⋅1+limx→∞4x
Step 3.5.6
Multiply 12√x by 1.
√01-4limx→∞12√x+limx→∞4x
√01-4limx→∞12√x+limx→∞4x
Step 3.6
Move the term 12 outside of the limit because it is constant with respect to x.
√01-4(12)limx→∞1√x+limx→∞4x
Step 3.7
Since its numerator approaches a real number while its denominator is unbounded, the fraction 1√x approaches 0.
√01-4(12)⋅0+limx→∞4x
Step 3.8
Move the term 4 outside of the limit because it is constant with respect to x.
√01-4(12)⋅0+4limx→∞1x
Step 3.9
Since its numerator approaches a real number while its denominator is unbounded, the fraction 1x approaches 0.
√01-4(12)⋅0+4⋅0
Step 3.10
Simplify the answer.
Step 3.10.1
Simplify the numerator.
Step 3.10.1.1
Rewrite 0 as 02.
√021-4(12)⋅0+4⋅0
Step 3.10.1.2
Pull terms out from under the radical, assuming positive real numbers.
01-4(12)⋅0+4⋅0
01-4(12)⋅0+4⋅0
Step 3.10.2
Simplify the denominator.
Step 3.10.2.1
Cancel the common factor of 2.
Step 3.10.2.1.1
Factor 2 out of -4.
01+2(-2)12⋅0+4⋅0
Step 3.10.2.1.2
Cancel the common factor.
01+2⋅-212⋅0+4⋅0
Step 3.10.2.1.3
Rewrite the expression.
01-2⋅0+4⋅0
01-2⋅0+4⋅0
Step 3.10.2.2
Multiply -2 by 0.
01+0+4⋅0
Step 3.10.2.3
Multiply 4 by 0.
01+0+0
Step 3.10.2.4
Add 1+0 and 0.
01+0
Step 3.10.2.5
Add 1 and 0.
01
01
Step 3.10.3
Divide 0 by 1.
0
0
0
Step 4
List the horizontal asymptotes:
y=0
Step 5
Use polynomial division to find the oblique asymptotes. Because this expression contains a radical, polynomial division cannot be performed.
Cannot Find Oblique Asymptotes
Step 6
This is the set of all asymptotes.
Vertical Asymptotes: x=4
Horizontal Asymptotes: y=0
Cannot Find Oblique Asymptotes
Step 7