Calculus Examples

$y = \frac{\sec (2 x)}{1 + \tan (2 x)}$

Step 1

Since $\frac{\sec (2 x)}{1 + \tan (2 x)}$ is constant with respect to $z$ , the derivative of $\frac{\sec (2 x)}{1 + \tan (2 x)}$ with respect to $z$ is $0$ .

$0$