Calculus Examples

Find the Average Value of the Derivative y=x^3 , [0,5]
y=x3 , [0,5]
Step 1
Write y=x3 as a function.
f(x)=x3
Step 2
Find the derivative of f(x)=x3.
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Step 2.1
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=3.
f(x)=3x2
Step 2.2
The first derivative of f(x) with respect to x is 3x2.
3x2
3x2
Step 3
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
Interval Notation:
(-,)
Set-Builder Notation:
{x|x}
Step 4
f(x) is continuous on [0,5].
f(x) is continuous
Step 5
The average value of function f over the interval [a,b] is defined as A(x)=1b-abaf(x)dx.
A(x)=1b-abaf(x)dx
Step 6
Substitute the actual values into the formula for the average value of a function.
A(x)=15-0(503x2dx)
Step 7
Since 3 is constant with respect to x, move 3 out of the integral.
A(x)=15-0(350x2dx)
Step 8
By the Power Rule, the integral of x2 with respect to x is 13x3.
A(x)=15-0(3(13x3]50))
Step 9
Simplify the answer.
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Step 9.1
Combine 13 and x3.
A(x)=15-0(3(x33]50))
Step 9.2
Substitute and simplify.
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Step 9.2.1
Evaluate x33 at 5 and at 0.
A(x)=15-0(3((533)-033))
Step 9.2.2
Simplify.
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Step 9.2.2.1
Raise 5 to the power of 3.
A(x)=15-0(3(1253-033))
Step 9.2.2.2
Raising 0 to any positive power yields 0.
A(x)=15-0(3(1253-03))
Step 9.2.2.3
Cancel the common factor of 0 and 3.
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Step 9.2.2.3.1
Factor 3 out of 0.
A(x)=15-0(3(1253-3(0)3))
Step 9.2.2.3.2
Cancel the common factors.
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Step 9.2.2.3.2.1
Factor 3 out of 3.
A(x)=15-0(3(1253-3031))
Step 9.2.2.3.2.2
Cancel the common factor.
A(x)=15-0(3(1253-3031))
Step 9.2.2.3.2.3
Rewrite the expression.
A(x)=15-0(3(1253-01))
Step 9.2.2.3.2.4
Divide 0 by 1.
A(x)=15-0(3(1253-0))
A(x)=15-0(3(1253-0))
A(x)=15-0(3(1253-0))
Step 9.2.2.4
Multiply -1 by 0.
A(x)=15-0(3(1253+0))
Step 9.2.2.5
Add 1253 and 0.
A(x)=15-0(3(1253))
Step 9.2.2.6
Combine 3 and 1253.
A(x)=15-0(31253)
Step 9.2.2.7
Multiply 3 by 125.
A(x)=15-0(3753)
Step 9.2.2.8
Cancel the common factor of 375 and 3.
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Step 9.2.2.8.1
Factor 3 out of 375.
A(x)=15-0(31253)
Step 9.2.2.8.2
Cancel the common factors.
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Step 9.2.2.8.2.1
Factor 3 out of 3.
A(x)=15-0(31253(1))
Step 9.2.2.8.2.2
Cancel the common factor.
A(x)=15-0(312531)
Step 9.2.2.8.2.3
Rewrite the expression.
A(x)=15-0(1251)
Step 9.2.2.8.2.4
Divide 125 by 1.
A(x)=15-0(125)
A(x)=15-0(125)
A(x)=15-0(125)
A(x)=15-0(125)
A(x)=15-0(125)
A(x)=15-0(125)
Step 10
Simplify the denominator.
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Step 10.1
Multiply -1 by 0.
A(x)=15+0125
Step 10.2
Add 5 and 0.
A(x)=15125
A(x)=15125
Step 11
Cancel the common factor of 5.
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Step 11.1
Factor 5 out of 125.
A(x)=15(5(25))
Step 11.2
Cancel the common factor.
A(x)=15(525)
Step 11.3
Rewrite the expression.
A(x)=25
A(x)=25
Step 12
 [x2  12  π  xdx ]