Calculus Examples

$\int 2^{- x} d x$

Step 1

Let $u = - x$ . Then $d u = - d x$ , so $- d u = d x$ . Rewrite using $u$ and $d$ $u$ .

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Step 1.1

Let $u = - x$ . Find $\frac{d u}{d x}$ .

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Step 1.1.1

Differentiate $- x$ .

$\frac{d}{d x} [- x]$

Step 1.1.2

Since $- 1$ is constant with respect to $x$ , the derivative of $- x$ with respect to $x$ is $- \frac{d}{d x} [x]$ .

$- \frac{d}{d x} [x]$

Step 1.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- 1 \cdot 1$

Step 1.1.4

Multiply $- 1$ by $1$ .

$- 1$

Step 1.2

Rewrite the problem using $u$ and $d u$ .

$\int - 2^{u} d u$

Step 2

Since $- 1$ is constant with respect to $u$ , move $- 1$ out of the integral.

$- \int 2^{u} d u$

Step 3

The integral of $2^{u}$ with respect to $u$ is $\frac{2^{u}}{\ln (2)}$ .

$- (\frac{2^{u}}{\ln (2)} + C)$

Step 4

Rewrite $- (\frac{2^{u}}{\ln (2)} + C)$ as $- \frac{1}{\ln (2)} \cdot 2^{u} + C$ .

$- \frac{1}{\ln (2)} \cdot 2^{u} + C$

Step 5

Replace all occurrences of $u$ with $- x$ .

$- \frac{1}{\ln (2)} \cdot 2^{- x} + C$