Calculus Examples

$π \int_{0}^{π} \sin^{2} (x) d x$

Step 1

Use the half-angle formula to rewrite $\sin^{2} (x)$ as $\frac{1 - \cos (2 x)}{2}$ .

$π \int_{0}^{π} \frac{1 - \cos (2 x)}{2} d x$

Step 2

Since $\frac{1}{2}$ is constant with respect to $x$ , move $\frac{1}{2}$ out of the integral.

$π (\frac{1}{2} \int_{0}^{π} 1 - \cos (2 x) d x)$

Step 3

Combine $\frac{1}{2}$ and $π$ .

$\frac{π}{2} \int_{0}^{π} 1 - \cos (2 x) d x$

Step 4

Split the single integral into multiple integrals.

$\frac{π}{2} (\int_{0}^{π} d x + \int_{0}^{π} - \cos (2 x) d x)$

Step 5

Apply the constant rule.

$\frac{π}{2} (x]_{0}^{π} + \int_{0}^{π} - \cos (2 x) d x)$

Step 6

Since $- 1$ is constant with respect to $x$ , move $- 1$ out of the integral.

$\frac{π}{2} (x]_{0}^{π} - \int_{0}^{π} \cos (2 x) d x)$

Step 7

Let $u = 2 x$ . Then $d u = 2 d x$ , so $\frac{1}{2} d u = d x$ . Rewrite using $u$ and $d$ $u$ .

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Step 7.1

Let $u = 2 x$ . Find $\frac{d u}{d x}$ .

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Step 7.1.1

Differentiate $2 x$ .

$\frac{d}{d x} [2 x]$

Step 7.1.2

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$2 \frac{d}{d x} [x]$

Step 7.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 \cdot 1$

Step 7.1.4

Multiply $2$ by $1$ .

$2$

Step 7.2

Substitute the lower limit in for $x$ in $u = 2 x$ .

$u_{lower} = 2 \cdot 0$

Step 7.3

Multiply $2$ by $0$ .

$u_{lower} = 0$

Step 7.4

Substitute the upper limit in for $x$ in $u = 2 x$ .

$u_{upper} = 2 π$

Step 7.5

The values found for $u_{lower}$ and $u_{upper}$ will be used to evaluate the definite integral.

$u_{lower} = 0$

$u_{upper} = 2 π$

Step 7.6

Rewrite the problem using $u$ , $d u$ , and the new limits of integration.

$\frac{π}{2} (x]_{0}^{π} - \int_{0}^{2 π} \cos (u) \frac{1}{2} d u)$

Step 8

Combine $\cos (u)$ and $\frac{1}{2}$ .

$\frac{π}{2} (x]_{0}^{π} - \int_{0}^{2 π} \frac{\cos (u)}{2} d u)$

Step 9

Since $\frac{1}{2}$ is constant with respect to $u$ , move $\frac{1}{2}$ out of the integral.

$\frac{π}{2} (x]_{0}^{π} - (\frac{1}{2} \int_{0}^{2 π} \cos (u) d u))$

Step 10

The integral of $\cos (u)$ with respect to $u$ is $\sin (u)$ .

$\frac{π}{2} (x]_{0}^{π} - \frac{1}{2} \sin (u)]_{0}^{2 π})$

Step 11

Substitute and simplify.

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Step 11.1

Evaluate $x$ at $π$ and at $0$ .

$\frac{π}{2} ((π) + 0 - \frac{1}{2} \sin (u)]_{0}^{2 π})$

Step 11.2

Evaluate $\sin (u)$ at $2 π$ and at $0$ .

$\frac{π}{2} ((π) + 0 - \frac{1}{2} ((\sin (2 π)) - \sin (0)))$

Step 11.3

Add $π$ and $0$ .

$\frac{π}{2} (π - \frac{1}{2} (\sin (2 π) - \sin (0)))$

Step 12

Simplify.

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Step 12.1

The exact value of $\sin (0)$ is $0$ .

$\frac{π}{2} (π - \frac{1}{2} (\sin (2 π) - 0))$

Step 12.2

Multiply $- 1$ by $0$ .

$\frac{π}{2} (π - \frac{1}{2} (\sin (2 π) + 0))$

Step 12.3

Add $\sin (2 π)$ and $0$ .

$\frac{π}{2} (π - \frac{1}{2} \sin (2 π))$

Step 12.4

Combine $\sin (2 π)$ and $\frac{1}{2}$ .

$\frac{π}{2} (π - \frac{\sin (2 π)}{2})$

Step 13

Simplify.

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Step 13.1

Simplify the numerator.

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Step 13.1.1

Subtract full rotations of $2 π$ until the angle is greater than or equal to $0$ and less than $2 π$ .

$\frac{π}{2} (π - \frac{\sin (0)}{2})$

Step 13.1.2

The exact value of $\sin (0)$ is $0$ .

$\frac{π}{2} (π - \frac{0}{2})$

Step 13.2

Divide $0$ by $2$ .

$\frac{π}{2} (π - 0)$

Step 13.3

Multiply $- 1$ by $0$ .

$\frac{π}{2} (π + 0)$

Step 13.4

Add $π$ and $0$ .

$\frac{π}{2} π$

Step 13.5

Multiply $\frac{π}{2} π$ .

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Step 13.5.1

Combine $\frac{π}{2}$ and $π$ .

$\frac{π π}{2}$

Step 13.5.2

Raise $π$ to the power of $1$ .

$\frac{π^{1} π}{2}$

Step 13.5.3

Raise $π$ to the power of $1$ .

$\frac{π^{1} π^{1}}{2}$

Step 13.5.4

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{π^{1 + 1}}{2}$

Step 13.5.5

Add $1$ and $1$ .

$\frac{π^{2}}{2}$

Step 14

The result can be shown in multiple forms.

Exact Form:

$\frac{π^{2}}{2}$

Decimal Form:

$4.93480220 \dots$