Calculus Examples

Evaluate the Integral integral of t^2cos(t) with respect to t
t2cos(t)dt
Step 1
Integrate by parts using the formula udv=uv-vdu, where u=t2 and dv=cos(t).
t2sin(t)-sin(t)(2t)dt
Step 2
Since 2 is constant with respect to t, move 2 out of the integral.
t2sin(t)-(2sin(t)(t)dt)
Step 3
Multiply 2 by -1.
t2sin(t)-2sin(t)(t)dt
Step 4
Integrate by parts using the formula udv=uv-vdu, where u=t and dv=sin(t).
t2sin(t)-2(t(-cos(t))--cos(t)dt)
Step 5
Since -1 is constant with respect to t, move -1 out of the integral.
t2sin(t)-2(t(-cos(t))--cos(t)dt)
Step 6
Simplify.
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Step 6.1
Multiply -1 by -1.
t2sin(t)-2(t(-cos(t))+1cos(t)dt)
Step 6.2
Multiply cos(t)dt by 1.
t2sin(t)-2(t(-cos(t))+cos(t)dt)
t2sin(t)-2(t(-cos(t))+cos(t)dt)
Step 7
The integral of cos(t) with respect to t is sin(t).
t2sin(t)-2(t(-cos(t))+sin(t)+C)
Step 8
Rewrite t2sin(t)-2(t(-cos(t))+sin(t)+C) as t2sin(t)-2(-tcos(t)+sin(t))+C.
t2sin(t)-2(-tcos(t)+sin(t))+C
t2cos(t)dt
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