Calculus Examples

$\int \frac{2 x + 1}{x^{2} + x + 1} d x$

Step 1

Let $u = x^{2} + x + 1$ . Then $d u = (2 x + 1) d x$ , so $\frac{1}{2 x + 1} d u = d x$ . Rewrite using $u$ and $d$ $u$ .

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Step 1.1

Let $u = x^{2} + x + 1$ . Find $\frac{d u}{d x}$ .

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Step 1.1.1

Differentiate $x^{2} + x + 1$ .

$\frac{d}{d x} [x^{2} + x + 1]$

Step 1.1.2

By the Sum Rule, the derivative of $x^{2} + x + 1$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [x] + \frac{d}{d x} [1]$ .

$\frac{d}{d x} [x^{2}] + \frac{d}{d x} [x] + \frac{d}{d x} [1]$

Step 1.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$2 x + \frac{d}{d x} [x] + \frac{d}{d x} [1]$

Step 1.1.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 x + 1 + \frac{d}{d x} [1]$

Step 1.1.5

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$2 x + 1 + 0$

Step 1.1.6

Add $2 x + 1$ and $0$ .

$2 x + 1$

Step 1.2

Rewrite the problem using $u$ and $d u$ .

$\int \frac{1}{u} d u$

Step 2

The integral of $\frac{1}{u}$ with respect to $u$ is $\ln (| u |)$ .

$\ln (| u |) + C$

Step 3

Replace all occurrences of $u$ with $x^{2} + x + 1$ .

$\ln (| x^{2} + x + 1 |) + C$