Calculus Examples

$y = (\frac{x}{3.8} + \frac{3.8}{x}) (x^{2} + 1)$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (y) = \frac{d}{d x} ((\frac{x}{3.8} + \frac{3.8}{x}) (x^{2} + 1))$

Step 2

The derivative of $y$ with respect to $x$ is $y'$ .

$y'$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = \frac{x}{3.8} + \frac{3.8}{x}$ and $g (x) = x^{2} + 1$ .

$(\frac{x}{3.8} + \frac{3.8}{x}) \frac{d}{d x} [x^{2} + 1] + (x^{2} + 1) \frac{d}{d x} [\frac{x}{3.8} + \frac{3.8}{x}]$

Step 3.2

Differentiate.

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Step 3.2.1

By the Sum Rule, the derivative of $x^{2} + 1$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [1]$ .

$(\frac{x}{3.8} + \frac{3.8}{x}) (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [1]) + (x^{2} + 1) \frac{d}{d x} [\frac{x}{3.8} + \frac{3.8}{x}]$

Step 3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$(\frac{x}{3.8} + \frac{3.8}{x}) (2 x + \frac{d}{d x} [1]) + (x^{2} + 1) \frac{d}{d x} [\frac{x}{3.8} + \frac{3.8}{x}]$

Step 3.2.3

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$(\frac{x}{3.8} + \frac{3.8}{x}) (2 x + 0) + (x^{2} + 1) \frac{d}{d x} [\frac{x}{3.8} + \frac{3.8}{x}]$

Step 3.2.4

Simplify the expression.

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Step 3.2.4.1

Add $2 x$ and $0$ .

$(\frac{x}{3.8} + \frac{3.8}{x}) (2 x) + (x^{2} + 1) \frac{d}{d x} [\frac{x}{3.8} + \frac{3.8}{x}]$

Step 3.2.4.2

Move $2$ to the left of $\frac{x}{3.8} + \frac{3.8}{x}$ .

$2 \cdot (\frac{x}{3.8} + \frac{3.8}{x}) x + (x^{2} + 1) \frac{d}{d x} [\frac{x}{3.8} + \frac{3.8}{x}]$

Step 3.2.5

By the Sum Rule, the derivative of $\frac{x}{3.8} + \frac{3.8}{x}$ with respect to $x$ is $\frac{d}{d x} [\frac{x}{3.8}] + \frac{d}{d x} [\frac{3.8}{x}]$ .

$2 (\frac{x}{3.8} + \frac{3.8}{x}) x + (x^{2} + 1) (\frac{d}{d x} [\frac{x}{3.8}] + \frac{d}{d x} [\frac{3.8}{x}])$

Step 3.2.6

Since $\frac{1}{3.8}$ is constant with respect to $x$ , the derivative of $\frac{x}{3.8}$ with respect to $x$ is $\frac{1}{3.8} \frac{d}{d x} [x]$ .

$2 (\frac{x}{3.8} + \frac{3.8}{x}) x + (x^{2} + 1) (\frac{1}{3.8} \frac{d}{d x} [x] + \frac{d}{d x} [\frac{3.8}{x}])$

Step 3.2.7

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 (\frac{x}{3.8} + \frac{3.8}{x}) x + (x^{2} + 1) (\frac{1}{3.8} \cdot 1 + \frac{d}{d x} [\frac{3.8}{x}])$

Step 3.2.8

Multiply $\frac{1}{3.8}$ by $1$ .

$2 (\frac{x}{3.8} + \frac{3.8}{x}) x + (x^{2} + 1) (\frac{1}{3.8} + \frac{d}{d x} [\frac{3.8}{x}])$

Step 3.2.9

Since $3.8$ is constant with respect to $x$ , the derivative of $\frac{3.8}{x}$ with respect to $x$ is $3.8 \frac{d}{d x} [\frac{1}{x}]$ .

$2 (\frac{x}{3.8} + \frac{3.8}{x}) x + (x^{2} + 1) (\frac{1}{3.8} + 3.8 \frac{d}{d x} [\frac{1}{x}])$

Step 3.2.10

Rewrite $\frac{1}{x}$ as $x^{- 1}$ .

$2 (\frac{x}{3.8} + \frac{3.8}{x}) x + (x^{2} + 1) (\frac{1}{3.8} + 3.8 \frac{d}{d x} [x^{- 1}])$

Step 3.2.11

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = - 1$ .

$2 (\frac{x}{3.8} + \frac{3.8}{x}) x + (x^{2} + 1) (\frac{1}{3.8} + 3.8 (- x^{- 2}))$

Step 3.2.12

Multiply $- 1$ by $3.8$ .

$2 (\frac{x}{3.8} + \frac{3.8}{x}) x + (x^{2} + 1) (\frac{1}{3.8} - 3.8 x^{- 2})$

Step 3.3

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$2 (\frac{x}{3.8} + \frac{3.8}{x}) x + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4

Simplify.

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Step 3.4.1

Apply the distributive property.

$(2 \frac{x}{3.8} + 2 \frac{3.8}{x}) x + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.2

Apply the distributive property.

$2 \frac{x}{3.8} x + 2 \frac{3.8}{x} x + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.3

Combine terms.

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Step 3.4.3.1

Combine $2$ and $\frac{x}{3.8}$ .

$\frac{2 x}{3.8} x + 2 \frac{3.8}{x} x + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.3.2

Combine $\frac{2 x}{3.8}$ and $x$ .

$\frac{2 x \cdot x}{3.8} + 2 \frac{3.8}{x} x + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.3.3

Raise $x$ to the power of $1$ .

$\frac{2 (x^{1} x)}{3.8} + 2 \frac{3.8}{x} x + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.3.4

Raise $x$ to the power of $1$ .

$\frac{2 (x^{1} x^{1})}{3.8} + 2 \frac{3.8}{x} x + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.3.5

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 x^{1 + 1}}{3.8} + 2 \frac{3.8}{x} x + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.3.6

Add $1$ and $1$ .

$\frac{2 x^{2}}{3.8} + 2 \frac{3.8}{x} x + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.3.7

Combine $2$ and $\frac{3.8}{x}$ .

$\frac{2 x^{2}}{3.8} + \frac{2 \cdot 3.8}{x} x + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.3.8

Multiply $2$ by $3.8$ .

$\frac{2 x^{2}}{3.8} + \frac{7.6}{x} x + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.3.9

Combine $\frac{7.6}{x}$ and $x$ .

$\frac{2 x^{2}}{3.8} + \frac{7.6 x}{x} + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.3.10

Cancel the common factor of $x$ .

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Step 3.4.3.10.1

Cancel the common factor.

$\frac{2 x^{2}}{3.8} + \frac{7.6 x}{x} + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.3.10.2

Divide $7.6$ by $1$ .

$\frac{2 x^{2}}{3.8} + 7.6 + (x^{2} + 1) (\frac{1}{3.8} - 3.8 \frac{1}{x^{2}})$

Step 3.4.3.11

Combine $- 3.8$ and $\frac{1}{x^{2}}$ .

$\frac{2 x^{2}}{3.8} + 7.6 + (x^{2} + 1) (\frac{1}{3.8} + \frac{- 3.8}{x^{2}})$

Step 3.4.3.12

Move the negative in front of the fraction.

$\frac{2 x^{2}}{3.8} + 7.6 + (x^{2} + 1) (\frac{1}{3.8} - \frac{3.8}{x^{2}})$

Step 3.4.4

Reorder terms.

$\frac{2 x^{2}}{3.8} + (x^{2} + 1) (\frac{1}{3.8} - \frac{3.8}{x^{2}}) + 7.6$

Step 4

Reform the equation by setting the left side equal to the right side.

$y' = \frac{2 x^{2}}{3.8} + (x^{2} + 1) (\frac{1}{3.8} - \frac{3.8}{x^{2}}) + 7.6$

Step 5

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = \frac{2 x^{2}}{3.8} + (x^{2} + 1) (\frac{1}{3.8} - \frac{3.8}{x^{2}}) + 7.6$