Calculus Examples

$f (x) = \sqrt[15]{7 x + 5}$

Step 1

Find the first derivative.

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Step 1.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[15]{7 x + 5}$ as ${(7 x + 5)}^{\frac{1}{15}}$ .

$f' (x) = \frac{d}{d x} ({(7 x + 5)}^{\frac{1}{15}})$

Step 1.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{15}}$ and $g (x) = 7 x + 5$ .

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Step 1.2.1

To apply the Chain Rule, set $u$ as $7 x + 5$ .

$f' (x) = \frac{d}{d u} (u^{\frac{1}{15}}) \frac{d}{d x} (7 x + 5)$

Step 1.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{15}$ .

$f' (x) = \frac{1}{15} u^{\frac{1}{15} - 1} \frac{d}{d x} (7 x + 5)$

Step 1.2.3

Replace all occurrences of $u$ with $7 x + 5$ .

$f' (x) = \frac{1}{15} \cdot {(7 x + 5)}^{\frac{1}{15} - 1} \frac{d}{d x} (7 x + 5)$

Step 1.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{15}{15}$ .

$f' (x) = \frac{1}{15} \cdot {(7 x + 5)}^{\frac{1}{15} - 1 \cdot \frac{15}{15}} \frac{d}{d x} (7 x + 5)$

Step 1.4

Combine $- 1$ and $\frac{15}{15}$ .

$f' (x) = \frac{1}{15} \cdot {(7 x + 5)}^{\frac{1}{15} + \frac{- 1 \cdot 15}{15}} \frac{d}{d x} (7 x + 5)$

Step 1.5

Combine the numerators over the common denominator.

$f' (x) = \frac{1}{15} \cdot {(7 x + 5)}^{\frac{1 - 1 \cdot 15}{15}} \frac{d}{d x} (7 x + 5)$

Step 1.6

Simplify the numerator.

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Step 1.6.1

Multiply $- 1$ by $15$ .

$f' (x) = \frac{1}{15} \cdot {(7 x + 5)}^{\frac{1 - 15}{15}} \frac{d}{d x} (7 x + 5)$

Step 1.6.2

Subtract $15$ from $1$ .

$f' (x) = \frac{1}{15} \cdot {(7 x + 5)}^{\frac{- 14}{15}} \frac{d}{d x} (7 x + 5)$

Step 1.7

Combine fractions.

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Step 1.7.1

Move the negative in front of the fraction.

$f' (x) = \frac{1}{15} \cdot {(7 x + 5)}^{- \frac{14}{15}} \frac{d}{d x} (7 x + 5)$

Step 1.7.2

Combine $\frac{1}{15}$ and ${(7 x + 5)}^{- \frac{14}{15}}$ .

$f' (x) = \frac{{(7 x + 5)}^{- \frac{14}{15}}}{15} \cdot \frac{d}{d x} (7 x + 5)$

Step 1.7.3

Move ${(7 x + 5)}^{- \frac{14}{15}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$f' (x) = \frac{1}{15 {(7 x + 5)}^{\frac{14}{15}}} \cdot \frac{d}{d x} (7 x + 5)$

Step 1.8

By the Sum Rule, the derivative of $7 x + 5$ with respect to $x$ is $\frac{d}{d x} [7 x] + \frac{d}{d x} [5]$ .

$f' (x) = \frac{1}{15 {(7 x + 5)}^{\frac{14}{15}}} \cdot (\frac{d}{d x} (7 x) + \frac{d}{d x} (5))$

Step 1.9

Since $7$ is constant with respect to $x$ , the derivative of $7 x$ with respect to $x$ is $7 \frac{d}{d x} [x]$ .

$f' (x) = \frac{1}{15 {(7 x + 5)}^{\frac{14}{15}}} \cdot (7 \frac{d}{d x} (x) + \frac{d}{d x} (5))$

Step 1.10

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f' (x) = \frac{1}{15 {(7 x + 5)}^{\frac{14}{15}}} \cdot (7 \cdot 1 + \frac{d}{d x} (5))$

Step 1.11

Multiply $7$ by $1$ .

$f' (x) = \frac{1}{15 {(7 x + 5)}^{\frac{14}{15}}} \cdot (7 + \frac{d}{d x} (5))$

Step 1.12

Since $5$ is constant with respect to $x$ , the derivative of $5$ with respect to $x$ is $0$ .

$f' (x) = \frac{1}{15 {(7 x + 5)}^{\frac{14}{15}}} \cdot (7 + 0)$

Step 1.13

Combine fractions.

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Step 1.13.1

Add $7$ and $0$ .

$f' (x) = \frac{1}{15 {(7 x + 5)}^{\frac{14}{15}}} \cdot 7$

Step 1.13.2

Combine $\frac{1}{15 {(7 x + 5)}^{\frac{14}{15}}}$ and $7$ .

$f' (x) = \frac{7}{15 {(7 x + 5)}^{\frac{14}{15}}}$

Step 2

Find the second derivative.

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Step 2.1

Differentiate using the Constant Multiple Rule.

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Step 2.1.1

Since $\frac{7}{15}$ is constant with respect to $x$ , the derivative of $\frac{7}{15 {(7 x + 5)}^{\frac{14}{15}}}$ with respect to $x$ is $\frac{7}{15} \frac{d}{d x} [\frac{1}{{(7 x + 5)}^{\frac{14}{15}}}]$ .

$f'' (x) = \frac{7}{15} \cdot \frac{d}{d x} (\frac{1}{{(7 x + 5)}^{\frac{14}{15}}})$

Step 2.1.2

Apply basic rules of exponents.

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Step 2.1.2.1

Rewrite $\frac{1}{{(7 x + 5)}^{\frac{14}{15}}}$ as ${({(7 x + 5)}^{\frac{14}{15}})}^{- 1}$ .

$f'' (x) = \frac{7}{15} \cdot \frac{d}{d x} ({({(7 x + 5)}^{\frac{14}{15}})}^{- 1})$

Step 2.1.2.2

Multiply the exponents in ${({(7 x + 5)}^{\frac{14}{15}})}^{- 1}$ .

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Step 2.1.2.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f'' (x) = \frac{7}{15} \cdot \frac{d}{d x} ({(7 x + 5)}^{\frac{14}{15} \cdot - 1})$

Step 2.1.2.2.2

Multiply $\frac{14}{15} \cdot - 1$ .

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Step 2.1.2.2.2.1

Combine $\frac{14}{15}$ and $- 1$ .

$f'' (x) = \frac{7}{15} \cdot \frac{d}{d x} ({(7 x + 5)}^{\frac{14 \cdot - 1}{15}})$

Step 2.1.2.2.2.2

Multiply $14$ by $- 1$ .

$f'' (x) = \frac{7}{15} \cdot \frac{d}{d x} ({(7 x + 5)}^{\frac{- 14}{15}})$

Step 2.1.2.2.3

Move the negative in front of the fraction.

$f'' (x) = \frac{7}{15} \cdot \frac{d}{d x} ({(7 x + 5)}^{- \frac{14}{15}})$

Step 2.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{- \frac{14}{15}}$ and $g (x) = 7 x + 5$ .

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Step 2.2.1

To apply the Chain Rule, set $u$ as $7 x + 5$ .

$f'' (x) = \frac{7}{15} \cdot (\frac{d}{d u} (u^{- \frac{14}{15}}) \frac{d}{d x} (7 x + 5))$

Step 2.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = - \frac{14}{15}$ .

$f'' (x) = \frac{7}{15} \cdot (- \frac{14}{15} u^{- \frac{14}{15} - 1} \frac{d}{d x} (7 x + 5))$

Step 2.2.3

Replace all occurrences of $u$ with $7 x + 5$ .

$f'' (x) = \frac{7}{15} \cdot (- \frac{14}{15} \cdot {(7 x + 5)}^{- \frac{14}{15} - 1} \frac{d}{d x} (7 x + 5))$

Step 2.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{15}{15}$ .

$f'' (x) = \frac{7}{15} \cdot (- \frac{14}{15} \cdot {(7 x + 5)}^{- \frac{14}{15} - 1 \cdot \frac{15}{15}} \frac{d}{d x} (7 x + 5))$

Step 2.4

Combine $- 1$ and $\frac{15}{15}$ .

$f'' (x) = \frac{7}{15} \cdot (- \frac{14}{15} \cdot {(7 x + 5)}^{- \frac{14}{15} + \frac{- 1 \cdot 15}{15}} \frac{d}{d x} (7 x + 5))$

Step 2.5

Combine the numerators over the common denominator.

$f'' (x) = \frac{7}{15} \cdot (- \frac{14}{15} \cdot {(7 x + 5)}^{\frac{- 14 - 1 \cdot 15}{15}} \frac{d}{d x} (7 x + 5))$

Step 2.6

Simplify the numerator.

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Step 2.6.1

Multiply $- 1$ by $15$ .

$f'' (x) = \frac{7}{15} \cdot (- \frac{14}{15} \cdot {(7 x + 5)}^{\frac{- 14 - 15}{15}} \frac{d}{d x} (7 x + 5))$

Step 2.6.2

Subtract $15$ from $- 14$ .

$f'' (x) = \frac{7}{15} \cdot (- \frac{14}{15} \cdot {(7 x + 5)}^{\frac{- 29}{15}} \frac{d}{d x} (7 x + 5))$

Step 2.7

Combine fractions.

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Step 2.7.1

Move the negative in front of the fraction.

$f'' (x) = \frac{7}{15} \cdot (- \frac{14}{15} \cdot {(7 x + 5)}^{- \frac{29}{15}} \frac{d}{d x} (7 x + 5))$

Step 2.7.2

Combine ${(7 x + 5)}^{- \frac{29}{15}}$ and $\frac{14}{15}$ .

$f'' (x) = \frac{7}{15} \cdot (- \frac{{(7 x + 5)}^{- \frac{29}{15}} \cdot 14}{15} \cdot \frac{d}{d x} (7 x + 5))$

Step 2.7.3

Simplify the expression.

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Step 2.7.3.1

Move $14$ to the left of ${(7 x + 5)}^{- \frac{29}{15}}$ .

$f'' (x) = \frac{7}{15} \cdot (- \frac{14 \cdot {(7 x + 5)}^{- \frac{29}{15}}}{15} \cdot \frac{d}{d x} (7 x + 5))$

Step 2.7.3.2

Move ${(7 x + 5)}^{- \frac{29}{15}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$f'' (x) = \frac{7}{15} \cdot (- \frac{14}{15 {(7 x + 5)}^{\frac{29}{15}}} \cdot \frac{d}{d x} (7 x + 5))$

Step 2.7.4

Multiply $\frac{7}{15}$ by $\frac{14}{15 {(7 x + 5)}^{\frac{29}{15}}}$ .

$f'' (x) = - \frac{7 \cdot 14}{15 (15 {(7 x + 5)}^{\frac{29}{15}})} \cdot \frac{d}{d x} (7 x + 5)$

Step 2.7.5

Multiply.

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Step 2.7.5.1

Multiply $7$ by $14$ .

$f'' (x) = - \frac{98}{15 (15 {(7 x + 5)}^{\frac{29}{15}})} \cdot \frac{d}{d x} (7 x + 5)$

Step 2.7.5.2

Multiply $15$ by $15$ .

$f'' (x) = - \frac{98}{225 {(7 x + 5)}^{\frac{29}{15}}} \cdot \frac{d}{d x} (7 x + 5)$

Step 2.8

By the Sum Rule, the derivative of $7 x + 5$ with respect to $x$ is $\frac{d}{d x} [7 x] + \frac{d}{d x} [5]$ .

$f'' (x) = - \frac{98}{225 {(7 x + 5)}^{\frac{29}{15}}} \cdot (\frac{d}{d x} (7 x) + \frac{d}{d x} (5))$

Step 2.9

Since $7$ is constant with respect to $x$ , the derivative of $7 x$ with respect to $x$ is $7 \frac{d}{d x} [x]$ .

$f'' (x) = - \frac{98}{225 {(7 x + 5)}^{\frac{29}{15}}} \cdot (7 \frac{d}{d x} (x) + \frac{d}{d x} (5))$

Step 2.10

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f'' (x) = - \frac{98}{225 {(7 x + 5)}^{\frac{29}{15}}} \cdot (7 \cdot 1 + \frac{d}{d x} (5))$

Step 2.11

Multiply $7$ by $1$ .

$f'' (x) = - \frac{98}{225 {(7 x + 5)}^{\frac{29}{15}}} \cdot (7 + \frac{d}{d x} (5))$

Step 2.12

Since $5$ is constant with respect to $x$ , the derivative of $5$ with respect to $x$ is $0$ .

$f'' (x) = - \frac{98}{225 {(7 x + 5)}^{\frac{29}{15}}} \cdot (7 + 0)$

Step 2.13

Combine fractions.

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Step 2.13.1

Add $7$ and $0$ .

$f'' (x) = - \frac{98}{225 {(7 x + 5)}^{\frac{29}{15}}} \cdot 7$

Step 2.13.2

Multiply $7$ by $- 1$ .

$f'' (x) = - 7 \frac{98}{225 {(7 x + 5)}^{\frac{29}{15}}}$

Step 2.13.3

Combine $- 7$ and $\frac{98}{225 {(7 x + 5)}^{\frac{29}{15}}}$ .

$f'' (x) = \frac{- 7 \cdot 98}{225 {(7 x + 5)}^{\frac{29}{15}}}$

Step 2.13.4

Simplify the expression.

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Step 2.13.4.1

Multiply $- 7$ by $98$ .

$f'' (x) = \frac{- 686}{225 {(7 x + 5)}^{\frac{29}{15}}}$

Step 2.13.4.2

Move the negative in front of the fraction.

$f'' (x) = - \frac{686}{225 {(7 x + 5)}^{\frac{29}{15}}}$

Step 3

Find the third derivative.

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Step 3.1

Differentiate using the Constant Multiple Rule.

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Step 3.1.1

Since $- \frac{686}{225}$ is constant with respect to $x$ , the derivative of $- \frac{686}{225 {(7 x + 5)}^{\frac{29}{15}}}$ with respect to $x$ is $- \frac{686}{225} \frac{d}{d x} [\frac{1}{{(7 x + 5)}^{\frac{29}{15}}}]$ .

$f''' (x) = - \frac{686}{225} \cdot \frac{d}{d x} \frac{1}{{(7 x + 5)}^{\frac{29}{15}}}$

Step 3.1.2

Apply basic rules of exponents.

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Step 3.1.2.1

Rewrite $\frac{1}{{(7 x + 5)}^{\frac{29}{15}}}$ as ${({(7 x + 5)}^{\frac{29}{15}})}^{- 1}$ .

$f''' (x) = - \frac{686}{225} \cdot \frac{d}{d x} {({(7 x + 5)}^{\frac{29}{15}})}^{- 1}$

Step 3.1.2.2

Multiply the exponents in ${({(7 x + 5)}^{\frac{29}{15}})}^{- 1}$ .

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Step 3.1.2.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f''' (x) = - \frac{686}{225} \cdot \frac{d}{d x} {(7 x + 5)}^{\frac{29}{15} \cdot - 1}$

Step 3.1.2.2.2

Multiply $\frac{29}{15} \cdot - 1$ .

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Step 3.1.2.2.2.1

Combine $\frac{29}{15}$ and $- 1$ .

$f''' (x) = - \frac{686}{225} \cdot \frac{d}{d x} {(7 x + 5)}^{\frac{29 \cdot - 1}{15}}$

Step 3.1.2.2.2.2

Multiply $29$ by $- 1$ .

$f''' (x) = - \frac{686}{225} \cdot \frac{d}{d x} {(7 x + 5)}^{\frac{- 29}{15}}$

Step 3.1.2.2.3

Move the negative in front of the fraction.

$f''' (x) = - \frac{686}{225} \cdot \frac{d}{d x} {(7 x + 5)}^{- \frac{29}{15}}$

Step 3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{- \frac{29}{15}}$ and $g (x) = 7 x + 5$ .

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Step 3.2.1

To apply the Chain Rule, set $u$ as $7 x + 5$ .

$f''' (x) = - \frac{686}{225} \cdot (\frac{d}{d u} (u^{- \frac{29}{15}}) \frac{d}{d x} (7 x + 5))$

Step 3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = - \frac{29}{15}$ .

$f''' (x) = - \frac{686}{225} \cdot (- \frac{29}{15} u^{- \frac{29}{15} - 1} \frac{d}{d x} (7 x + 5))$

Step 3.2.3

Replace all occurrences of $u$ with $7 x + 5$ .

$f''' (x) = - \frac{686}{225} \cdot (- \frac{29}{15} \cdot {(7 x + 5)}^{- \frac{29}{15} - 1} \frac{d}{d x} (7 x + 5))$

Step 3.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{15}{15}$ .

$f''' (x) = - \frac{686}{225} \cdot (- \frac{29}{15} \cdot {(7 x + 5)}^{- \frac{29}{15} - 1 \cdot \frac{15}{15}} \frac{d}{d x} (7 x + 5))$

Step 3.4

Combine $- 1$ and $\frac{15}{15}$ .

$f''' (x) = - \frac{686}{225} \cdot (- \frac{29}{15} \cdot {(7 x + 5)}^{- \frac{29}{15} + \frac{- 1 \cdot 15}{15}} \frac{d}{d x} (7 x + 5))$

Step 3.5

Combine the numerators over the common denominator.

$f''' (x) = - \frac{686}{225} \cdot (- \frac{29}{15} \cdot {(7 x + 5)}^{\frac{- 29 - 1 \cdot 15}{15}} \frac{d}{d x} (7 x + 5))$

Step 3.6

Simplify the numerator.

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Step 3.6.1

Multiply $- 1$ by $15$ .

$f''' (x) = - \frac{686}{225} \cdot (- \frac{29}{15} \cdot {(7 x + 5)}^{\frac{- 29 - 15}{15}} \frac{d}{d x} (7 x + 5))$

Step 3.6.2

Subtract $15$ from $- 29$ .

$f''' (x) = - \frac{686}{225} \cdot (- \frac{29}{15} \cdot {(7 x + 5)}^{\frac{- 44}{15}} \frac{d}{d x} (7 x + 5))$

Step 3.7

Combine fractions.

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Step 3.7.1

Move the negative in front of the fraction.

$f''' (x) = - \frac{686}{225} \cdot (- \frac{29}{15} \cdot {(7 x + 5)}^{- \frac{44}{15}} \frac{d}{d x} (7 x + 5))$

Step 3.7.2

Combine ${(7 x + 5)}^{- \frac{44}{15}}$ and $\frac{29}{15}$ .

$f''' (x) = - \frac{686}{225} \cdot (- \frac{{(7 x + 5)}^{- \frac{44}{15}} \cdot 29}{15} \cdot \frac{d}{d x} (7 x + 5))$

Step 3.7.3

Simplify the expression.

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Step 3.7.3.1

Move $29$ to the left of ${(7 x + 5)}^{- \frac{44}{15}}$ .

$f''' (x) = - \frac{686}{225} \cdot (- \frac{29 \cdot {(7 x + 5)}^{- \frac{44}{15}}}{15} \cdot \frac{d}{d x} (7 x + 5))$

Step 3.7.3.2

Move ${(7 x + 5)}^{- \frac{44}{15}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$f''' (x) = - \frac{686}{225} \cdot (- \frac{29}{15 {(7 x + 5)}^{\frac{44}{15}}} \cdot \frac{d}{d x} (7 x + 5))$

Step 3.7.3.3

Multiply $- 1$ by $- 1$ .

$f''' (x) = 1 (\frac{686}{225}) \cdot (\frac{29}{15 {(7 x + 5)}^{\frac{44}{15}}} \cdot \frac{d}{d x} (7 x + 5))$

Step 3.7.3.4

Multiply $\frac{686}{225}$ by $1$ .

$f''' (x) = \frac{686}{225} \cdot (\frac{29}{15 {(7 x + 5)}^{\frac{44}{15}}} \cdot \frac{d}{d x} (7 x + 5))$

Step 3.7.4

Multiply $\frac{29}{15 {(7 x + 5)}^{\frac{44}{15}}}$ by $\frac{686}{225}$ .

$f''' (x) = \frac{29 \cdot 686}{15 {(7 x + 5)}^{\frac{44}{15}} \cdot 225} \cdot \frac{d}{d x} (7 x + 5)$

Step 3.7.5

Multiply.

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Step 3.7.5.1

Multiply $29$ by $686$ .

$f''' (x) = \frac{19894}{15 {(7 x + 5)}^{\frac{44}{15}} \cdot 225} \cdot \frac{d}{d x} (7 x + 5)$

Step 3.7.5.2

Multiply $225$ by $15$ .

$f''' (x) = \frac{19894}{3375 {(7 x + 5)}^{\frac{44}{15}}} \cdot \frac{d}{d x} (7 x + 5)$

Step 3.8

By the Sum Rule, the derivative of $7 x + 5$ with respect to $x$ is $\frac{d}{d x} [7 x] + \frac{d}{d x} [5]$ .

$f''' (x) = \frac{19894}{3375 {(7 x + 5)}^{\frac{44}{15}}} \cdot (\frac{d}{d x} (7 x) + \frac{d}{d x} (5))$

Step 3.9

Since $7$ is constant with respect to $x$ , the derivative of $7 x$ with respect to $x$ is $7 \frac{d}{d x} [x]$ .

$f''' (x) = \frac{19894}{3375 {(7 x + 5)}^{\frac{44}{15}}} \cdot (7 \frac{d}{d x} (x) + \frac{d}{d x} (5))$

Step 3.10

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f''' (x) = \frac{19894}{3375 {(7 x + 5)}^{\frac{44}{15}}} \cdot (7 \cdot 1 + \frac{d}{d x} (5))$

Step 3.11

Multiply $7$ by $1$ .

$f''' (x) = \frac{19894}{3375 {(7 x + 5)}^{\frac{44}{15}}} \cdot (7 + \frac{d}{d x} (5))$

Step 3.12

Since $5$ is constant with respect to $x$ , the derivative of $5$ with respect to $x$ is $0$ .

$f''' (x) = \frac{19894}{3375 {(7 x + 5)}^{\frac{44}{15}}} \cdot (7 + 0)$

Step 3.13

Combine fractions.

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Step 3.13.1

Add $7$ and $0$ .

$f''' (x) = \frac{19894}{3375 {(7 x + 5)}^{\frac{44}{15}}} \cdot 7$

Step 3.13.2

Combine $\frac{19894}{3375 {(7 x + 5)}^{\frac{44}{15}}}$ and $7$ .

$f''' (x) = \frac{19894 \cdot 7}{3375 {(7 x + 5)}^{\frac{44}{15}}}$

Step 3.13.3

Multiply $19894$ by $7$ .

$f''' (x) = \frac{139258}{3375 {(7 x + 5)}^{\frac{44}{15}}}$

Step 4

Find the fourth derivative.

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Step 4.1

Differentiate using the Constant Multiple Rule.

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Step 4.1.1

Since $\frac{139258}{3375}$ is constant with respect to $x$ , the derivative of $\frac{139258}{3375 {(7 x + 5)}^{\frac{44}{15}}}$ with respect to $x$ is $\frac{139258}{3375} \frac{d}{d x} [\frac{1}{{(7 x + 5)}^{\frac{44}{15}}}]$ .

$f^{4} (x) = \frac{139258}{3375} \cdot \frac{d}{d x} (\frac{1}{{(7 x + 5)}^{\frac{44}{15}}})$

Step 4.1.2

Apply basic rules of exponents.

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Step 4.1.2.1

Rewrite $\frac{1}{{(7 x + 5)}^{\frac{44}{15}}}$ as ${({(7 x + 5)}^{\frac{44}{15}})}^{- 1}$ .

$f^{4} (x) = \frac{139258}{3375} \cdot \frac{d}{d x} ({({(7 x + 5)}^{\frac{44}{15}})}^{- 1})$

Step 4.1.2.2

Multiply the exponents in ${({(7 x + 5)}^{\frac{44}{15}})}^{- 1}$ .

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Step 4.1.2.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f^{4} (x) = \frac{139258}{3375} \cdot \frac{d}{d x} ({(7 x + 5)}^{\frac{44}{15} \cdot - 1})$

Step 4.1.2.2.2

Multiply $\frac{44}{15} \cdot - 1$ .

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Step 4.1.2.2.2.1

Combine $\frac{44}{15}$ and $- 1$ .

$f^{4} (x) = \frac{139258}{3375} \cdot \frac{d}{d x} ({(7 x + 5)}^{\frac{44 \cdot - 1}{15}})$

Step 4.1.2.2.2.2

Multiply $44$ by $- 1$ .

$f^{4} (x) = \frac{139258}{3375} \cdot \frac{d}{d x} ({(7 x + 5)}^{\frac{- 44}{15}})$

Step 4.1.2.2.3

Move the negative in front of the fraction.

$f^{4} (x) = \frac{139258}{3375} \cdot \frac{d}{d x} ({(7 x + 5)}^{- \frac{44}{15}})$

Step 4.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{- \frac{44}{15}}$ and $g (x) = 7 x + 5$ .

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Step 4.2.1

To apply the Chain Rule, set $u$ as $7 x + 5$ .

$f^{4} (x) = \frac{139258}{3375} \cdot (\frac{d}{d u} (u^{- \frac{44}{15}}) \frac{d}{d x} (7 x + 5))$

Step 4.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = - \frac{44}{15}$ .

$f^{4} (x) = \frac{139258}{3375} \cdot (- \frac{44}{15} u^{- \frac{44}{15} - 1} \frac{d}{d x} (7 x + 5))$

Step 4.2.3

Replace all occurrences of $u$ with $7 x + 5$ .

$f^{4} (x) = \frac{139258}{3375} \cdot (- \frac{44}{15} \cdot {(7 x + 5)}^{- \frac{44}{15} - 1} \frac{d}{d x} (7 x + 5))$

Step 4.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{15}{15}$ .

$f^{4} (x) = \frac{139258}{3375} \cdot (- \frac{44}{15} \cdot {(7 x + 5)}^{- \frac{44}{15} - 1 \cdot \frac{15}{15}} \frac{d}{d x} (7 x + 5))$

Step 4.4

Combine $- 1$ and $\frac{15}{15}$ .

$f^{4} (x) = \frac{139258}{3375} \cdot (- \frac{44}{15} \cdot {(7 x + 5)}^{- \frac{44}{15} + \frac{- 1 \cdot 15}{15}} \frac{d}{d x} (7 x + 5))$

Step 4.5

Combine the numerators over the common denominator.

$f^{4} (x) = \frac{139258}{3375} \cdot (- \frac{44}{15} \cdot {(7 x + 5)}^{\frac{- 44 - 1 \cdot 15}{15}} \frac{d}{d x} (7 x + 5))$

Step 4.6

Simplify the numerator.

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Step 4.6.1

Multiply $- 1$ by $15$ .

$f^{4} (x) = \frac{139258}{3375} \cdot (- \frac{44}{15} \cdot {(7 x + 5)}^{\frac{- 44 - 15}{15}} \frac{d}{d x} (7 x + 5))$

Step 4.6.2

Subtract $15$ from $- 44$ .

$f^{4} (x) = \frac{139258}{3375} \cdot (- \frac{44}{15} \cdot {(7 x + 5)}^{\frac{- 59}{15}} \frac{d}{d x} (7 x + 5))$

Step 4.7

Combine fractions.

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Step 4.7.1

Move the negative in front of the fraction.

$f^{4} (x) = \frac{139258}{3375} \cdot (- \frac{44}{15} \cdot {(7 x + 5)}^{- \frac{59}{15}} \frac{d}{d x} (7 x + 5))$

Step 4.7.2

Combine ${(7 x + 5)}^{- \frac{59}{15}}$ and $\frac{44}{15}$ .

$f^{4} (x) = \frac{139258}{3375} \cdot (- \frac{{(7 x + 5)}^{- \frac{59}{15}} \cdot 44}{15} \cdot \frac{d}{d x} (7 x + 5))$

Step 4.7.3

Simplify the expression.

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Step 4.7.3.1

Move $44$ to the left of ${(7 x + 5)}^{- \frac{59}{15}}$ .

$f^{4} (x) = \frac{139258}{3375} \cdot (- \frac{44 \cdot {(7 x + 5)}^{- \frac{59}{15}}}{15} \cdot \frac{d}{d x} (7 x + 5))$

Step 4.7.3.2

Move ${(7 x + 5)}^{- \frac{59}{15}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$f^{4} (x) = \frac{139258}{3375} \cdot (- \frac{44}{15 {(7 x + 5)}^{\frac{59}{15}}} \cdot \frac{d}{d x} (7 x + 5))$

Step 4.7.4

Multiply $\frac{139258}{3375}$ by $\frac{44}{15 {(7 x + 5)}^{\frac{59}{15}}}$ .

$f^{4} (x) = - \frac{139258 \cdot 44}{3375 (15 {(7 x + 5)}^{\frac{59}{15}})} \cdot \frac{d}{d x} (7 x + 5)$

Step 4.7.5

Multiply.

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Step 4.7.5.1

Multiply $139258$ by $44$ .

$f^{4} (x) = - \frac{6127352}{3375 (15 {(7 x + 5)}^{\frac{59}{15}})} \cdot \frac{d}{d x} (7 x + 5)$

Step 4.7.5.2

Multiply $15$ by $3375$ .

$f^{4} (x) = - \frac{6127352}{50625 {(7 x + 5)}^{\frac{59}{15}}} \cdot \frac{d}{d x} (7 x + 5)$

Step 4.8

By the Sum Rule, the derivative of $7 x + 5$ with respect to $x$ is $\frac{d}{d x} [7 x] + \frac{d}{d x} [5]$ .

$f^{4} (x) = - \frac{6127352}{50625 {(7 x + 5)}^{\frac{59}{15}}} \cdot (\frac{d}{d x} (7 x) + \frac{d}{d x} (5))$

Step 4.9

Since $7$ is constant with respect to $x$ , the derivative of $7 x$ with respect to $x$ is $7 \frac{d}{d x} [x]$ .

$f^{4} (x) = - \frac{6127352}{50625 {(7 x + 5)}^{\frac{59}{15}}} \cdot (7 \frac{d}{d x} (x) + \frac{d}{d x} (5))$

Step 4.10

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f^{4} (x) = - \frac{6127352}{50625 {(7 x + 5)}^{\frac{59}{15}}} \cdot (7 \cdot 1 + \frac{d}{d x} (5))$

Step 4.11

Multiply $7$ by $1$ .

$f^{4} (x) = - \frac{6127352}{50625 {(7 x + 5)}^{\frac{59}{15}}} \cdot (7 + \frac{d}{d x} (5))$

Step 4.12

Since $5$ is constant with respect to $x$ , the derivative of $5$ with respect to $x$ is $0$ .

$f^{4} (x) = - \frac{6127352}{50625 {(7 x + 5)}^{\frac{59}{15}}} \cdot (7 + 0)$

Step 4.13

Combine fractions.

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Step 4.13.1

Add $7$ and $0$ .

$f^{4} (x) = - \frac{6127352}{50625 {(7 x + 5)}^{\frac{59}{15}}} \cdot 7$

Step 4.13.2

Multiply $7$ by $- 1$ .

$f^{4} (x) = - 7 \frac{6127352}{50625 {(7 x + 5)}^{\frac{59}{15}}}$

Step 4.13.3

Combine $- 7$ and $\frac{6127352}{50625 {(7 x + 5)}^{\frac{59}{15}}}$ .

$f^{4} (x) = \frac{- 7 \cdot 6127352}{50625 {(7 x + 5)}^{\frac{59}{15}}}$

Step 4.13.4

Simplify the expression.

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Step 4.13.4.1

Multiply $- 7$ by $6127352$ .

$f^{4} (x) = \frac{- 42891464}{50625 {(7 x + 5)}^{\frac{59}{15}}}$

Step 4.13.4.2

Move the negative in front of the fraction.

$f^{4} (x) = - \frac{42891464}{50625 {(7 x + 5)}^{\frac{59}{15}}}$

Step 5

The fourth derivative of $f (x)$ with respect to $x$ is $- \frac{42891464}{50625 {(7 x + 5)}^{\frac{59}{15}}}$ .

$- \frac{42891464}{50625 {(7 x + 5)}^{\frac{59}{15}}}$