Calculus Examples

$f (x) = e^{- 7 x^{2}}$

Step 1

Find the first derivative.

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Step 1.1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = - 7 x^{2}$ .

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Step 1.1.1

To apply the Chain Rule, set $u$ as $- 7 x^{2}$ .

$\frac{d}{d u} [e^{u}] \frac{d}{d x} [- 7 x^{2}]$

Step 1.1.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u} [a^{u}]$ is $a^{u} \ln (a)$ where $a$ = $e$ .

$e^{u} \frac{d}{d x} [- 7 x^{2}]$

Step 1.1.3

Replace all occurrences of $u$ with $- 7 x^{2}$ .

$e^{- 7 x^{2}} \frac{d}{d x} [- 7 x^{2}]$

Step 1.2

Differentiate.

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Step 1.2.1

Since $- 7$ is constant with respect to $x$ , the derivative of $- 7 x^{2}$ with respect to $x$ is $- 7 \frac{d}{d x} [x^{2}]$ .

$e^{- 7 x^{2}} (- 7 \frac{d}{d x} [x^{2}])$

Step 1.2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$e^{- 7 x^{2}} (- 7 (2 x))$

Step 1.2.3

Multiply $2$ by $- 7$ .

$e^{- 7 x^{2}} (- 14 x)$

Step 1.3

Simplify.

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Step 1.3.1

Reorder the factors of $e^{- 7 x^{2}} (- 14 x)$ .

$- 14 e^{- 7 x^{2}} x$

Step 1.3.2

Reorder factors in $- 14 e^{- 7 x^{2}} x$ .

$f' (x) = - 14 x e^{- 7 x^{2}}$

Step 2

Find the second derivative.

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Step 2.1

Since $- 14$ is constant with respect to $x$ , the derivative of $- 14 x e^{- 7 x^{2}}$ with respect to $x$ is $- 14 \frac{d}{d x} [x e^{- 7 x^{2}}]$ .

$- 14 \frac{d}{d x} [x e^{- 7 x^{2}}]$

Step 2.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = e^{- 7 x^{2}}$ .

$- 14 (x \frac{d}{d x} [e^{- 7 x^{2}}] + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 2.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = - 7 x^{2}$ .

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Step 2.3.1

To apply the Chain Rule, set $u$ as $- 7 x^{2}$ .

$- 14 (x (\frac{d}{d u} [e^{u}] \frac{d}{d x} [- 7 x^{2}]) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 2.3.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u} [a^{u}]$ is $a^{u} \ln (a)$ where $a$ = $e$ .

$- 14 (x (e^{u} \frac{d}{d x} [- 7 x^{2}]) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 2.3.3

Replace all occurrences of $u$ with $- 7 x^{2}$ .

$- 14 (x (e^{- 7 x^{2}} \frac{d}{d x} [- 7 x^{2}]) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 2.4

Differentiate.

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Step 2.4.1

Since $- 7$ is constant with respect to $x$ , the derivative of $- 7 x^{2}$ with respect to $x$ is $- 7 \frac{d}{d x} [x^{2}]$ .

$- 14 (x (e^{- 7 x^{2}} (- 7 \frac{d}{d x} [x^{2}])) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 2.4.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$- 14 (x (e^{- 7 x^{2}} (- 7 (2 x))) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 2.4.3

Multiply $2$ by $- 7$ .

$- 14 (x (e^{- 7 x^{2}} (- 14 x)) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 2.5

Raise $x$ to the power of $1$ .

$- 14 (x^{1} x (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 2.6

Raise $x$ to the power of $1$ .

$- 14 (x^{1} x^{1} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 2.7

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$- 14 (x^{1 + 1} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 2.8

Simplify the expression.

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Step 2.8.1

Add $1$ and $1$ .

$- 14 (x^{2} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 2.8.2

Move $- 14$ to the left of $e^{- 7 x^{2}}$ .

$- 14 (x^{2} (- 14 \cdot e^{- 7 x^{2}}) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 2.9

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- 14 (x^{2} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} \cdot 1)$

Step 2.10

Multiply $e^{- 7 x^{2}}$ by $1$ .

$- 14 (x^{2} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}})$

Step 2.11

Simplify.

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Step 2.11.1

Apply the distributive property.

$- 14 (x^{2} (- 14 e^{- 7 x^{2}})) - 14 e^{- 7 x^{2}}$

Step 2.11.2

Multiply $- 14$ by $- 14$ .

$196 x^{2} e^{- 7 x^{2}} - 14 e^{- 7 x^{2}}$

Step 2.11.3

Reorder terms.

$196 e^{- 7 x^{2}} x^{2} - 14 e^{- 7 x^{2}}$

Step 2.11.4

Reorder factors in $196 e^{- 7 x^{2}} x^{2} - 14 e^{- 7 x^{2}}$ .

$f'' (x) = 196 x^{2} e^{- 7 x^{2}} - 14 e^{- 7 x^{2}}$

Step 3

Find the third derivative.

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Step 3.1

By the Sum Rule, the derivative of $196 x^{2} e^{- 7 x^{2}} - 14 e^{- 7 x^{2}}$ with respect to $x$ is $\frac{d}{d x} [196 x^{2} e^{- 7 x^{2}}] + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$ .

$\frac{d}{d x} [196 x^{2} e^{- 7 x^{2}}] + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2

Evaluate $\frac{d}{d x} [196 x^{2} e^{- 7 x^{2}}]$ .

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Step 3.2.1

Since $196$ is constant with respect to $x$ , the derivative of $196 x^{2} e^{- 7 x^{2}}$ with respect to $x$ is $196 \frac{d}{d x} [x^{2} e^{- 7 x^{2}}]$ .

$196 \frac{d}{d x} [x^{2} e^{- 7 x^{2}}] + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{2}$ and $g (x) = e^{- 7 x^{2}}$ .

$196 (x^{2} \frac{d}{d x} [e^{- 7 x^{2}}] + e^{- 7 x^{2}} \frac{d}{d x} [x^{2}]) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = - 7 x^{2}$ .

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Step 3.2.3.1

To apply the Chain Rule, set $u_{1}$ as $- 7 x^{2}$ .

$196 (x^{2} (\frac{d}{d u_{1}} [e^{u_{1}}] \frac{d}{d x} [- 7 x^{2}]) + e^{- 7 x^{2}} \frac{d}{d x} [x^{2}]) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.3.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{1}} [a^{u_{1}}]$ is $a^{u_{1}} \ln (a)$ where $a$ = $e$ .

$196 (x^{2} (e^{u_{1}} \frac{d}{d x} [- 7 x^{2}]) + e^{- 7 x^{2}} \frac{d}{d x} [x^{2}]) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.3.3

Replace all occurrences of $u_{1}$ with $- 7 x^{2}$ .

$196 (x^{2} (e^{- 7 x^{2}} \frac{d}{d x} [- 7 x^{2}]) + e^{- 7 x^{2}} \frac{d}{d x} [x^{2}]) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.4

Since $- 7$ is constant with respect to $x$ , the derivative of $- 7 x^{2}$ with respect to $x$ is $- 7 \frac{d}{d x} [x^{2}]$ .

$196 (x^{2} (e^{- 7 x^{2}} (- 7 \frac{d}{d x} [x^{2}])) + e^{- 7 x^{2}} \frac{d}{d x} [x^{2}]) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$196 (x^{2} (e^{- 7 x^{2}} (- 7 (2 x))) + e^{- 7 x^{2}} \frac{d}{d x} [x^{2}]) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.6

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$196 (x^{2} (e^{- 7 x^{2}} (- 7 (2 x))) + e^{- 7 x^{2}} (2 x)) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.7

Multiply $2$ by $- 7$ .

$196 (x^{2} (e^{- 7 x^{2}} (- 14 x)) + e^{- 7 x^{2}} (2 x)) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.8

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 3.2.8.1

Move $x$ .

$196 (x \cdot x^{2} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} (2 x)) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.8.2

Multiply $x$ by $x^{2}$ .

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Step 3.2.8.2.1

Raise $x$ to the power of $1$ .

$196 (x^{1} x^{2} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} (2 x)) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.8.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$196 (x^{1 + 2} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} (2 x)) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.8.3

Add $1$ and $2$ .

$196 (x^{3} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} (2 x)) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.2.9

Move $- 14$ to the left of $e^{- 7 x^{2}}$ .

$196 (x^{3} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (2 x)) + \frac{d}{d x} [- 14 e^{- 7 x^{2}}]$

Step 3.3

Evaluate $\frac{d}{d x} [- 14 e^{- 7 x^{2}}]$ .

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Step 3.3.1

Since $- 14$ is constant with respect to $x$ , the derivative of $- 14 e^{- 7 x^{2}}$ with respect to $x$ is $- 14 \frac{d}{d x} [e^{- 7 x^{2}}]$ .

$196 (x^{3} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (2 x)) - 14 \frac{d}{d x} [e^{- 7 x^{2}}]$

Step 3.3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = - 7 x^{2}$ .

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Step 3.3.2.1

To apply the Chain Rule, set $u_{2}$ as $- 7 x^{2}$ .

$196 (x^{3} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (2 x)) - 14 (\frac{d}{d u_{2}} [e^{u_{2}}] \frac{d}{d x} [- 7 x^{2}])$

Step 3.3.2.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{2}} [a^{u_{2}}]$ is $a^{u_{2}} \ln (a)$ where $a$ = $e$ .

$196 (x^{3} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (2 x)) - 14 (e^{u_{2}} \frac{d}{d x} [- 7 x^{2}])$

Step 3.3.2.3

Replace all occurrences of $u_{2}$ with $- 7 x^{2}$ .

$196 (x^{3} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (2 x)) - 14 (e^{- 7 x^{2}} \frac{d}{d x} [- 7 x^{2}])$

Step 3.3.3

Since $- 7$ is constant with respect to $x$ , the derivative of $- 7 x^{2}$ with respect to $x$ is $- 7 \frac{d}{d x} [x^{2}]$ .

$196 (x^{3} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (2 x)) - 14 (e^{- 7 x^{2}} (- 7 \frac{d}{d x} [x^{2}]))$

Step 3.3.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$196 (x^{3} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (2 x)) - 14 (e^{- 7 x^{2}} (- 7 (2 x)))$

Step 3.3.5

Multiply $2$ by $- 7$ .

$196 (x^{3} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (2 x)) - 14 (e^{- 7 x^{2}} (- 14 x))$

Step 3.3.6

Multiply $- 14$ by $- 14$ .

$196 (x^{3} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (2 x)) + 196 e^{- 7 x^{2}} x$

Step 3.4

Simplify.

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Step 3.4.1

Apply the distributive property.

$196 (x^{3} (- 14 e^{- 7 x^{2}})) + 196 (e^{- 7 x^{2}} (2 x)) + 196 e^{- 7 x^{2}} x$

Step 3.4.2

Combine terms.

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Step 3.4.2.1

Multiply $- 14$ by $196$ .

$- 2744 (x^{3} (e^{- 7 x^{2}})) + 196 (e^{- 7 x^{2}} (2 x)) + 196 e^{- 7 x^{2}} x$

Step 3.4.2.2

Multiply $2$ by $196$ .

$- 2744 x^{3} e^{- 7 x^{2}} + 392 (e^{- 7 x^{2}} (x)) + 196 e^{- 7 x^{2}} x$

Step 3.4.2.3

Add $392 e^{- 7 x^{2}} x$ and $196 e^{- 7 x^{2}} x$ .

$- 2744 x^{3} e^{- 7 x^{2}} + 588 e^{- 7 x^{2}} x$

Step 3.4.3

Reorder terms.

$- 2744 e^{- 7 x^{2}} x^{3} + 588 e^{- 7 x^{2}} x$

Step 3.4.4

Reorder factors in $- 2744 e^{- 7 x^{2}} x^{3} + 588 e^{- 7 x^{2}} x$ .

$f''' (x) = - 2744 x^{3} e^{- 7 x^{2}} + 588 x e^{- 7 x^{2}}$

Step 4

Find the fourth derivative.

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Step 4.1

By the Sum Rule, the derivative of $- 2744 x^{3} e^{- 7 x^{2}} + 588 x e^{- 7 x^{2}}$ with respect to $x$ is $\frac{d}{d x} [- 2744 x^{3} e^{- 7 x^{2}}] + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$ .

$\frac{d}{d x} [- 2744 x^{3} e^{- 7 x^{2}}] + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2

Evaluate $\frac{d}{d x} [- 2744 x^{3} e^{- 7 x^{2}}]$ .

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Step 4.2.1

Since $- 2744$ is constant with respect to $x$ , the derivative of $- 2744 x^{3} e^{- 7 x^{2}}$ with respect to $x$ is $- 2744 \frac{d}{d x} [x^{3} e^{- 7 x^{2}}]$ .

$- 2744 \frac{d}{d x} [x^{3} e^{- 7 x^{2}}] + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{3}$ and $g (x) = e^{- 7 x^{2}}$ .

$- 2744 (x^{3} \frac{d}{d x} [e^{- 7 x^{2}}] + e^{- 7 x^{2}} \frac{d}{d x} [x^{3}]) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = - 7 x^{2}$ .

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Step 4.2.3.1

To apply the Chain Rule, set $u_{1}$ as $- 7 x^{2}$ .

$- 2744 (x^{3} (\frac{d}{d u_{1}} [e^{u_{1}}] \frac{d}{d x} [- 7 x^{2}]) + e^{- 7 x^{2}} \frac{d}{d x} [x^{3}]) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.3.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{1}} [a^{u_{1}}]$ is $a^{u_{1}} \ln (a)$ where $a$ = $e$ .

$- 2744 (x^{3} (e^{u_{1}} \frac{d}{d x} [- 7 x^{2}]) + e^{- 7 x^{2}} \frac{d}{d x} [x^{3}]) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.3.3

Replace all occurrences of $u_{1}$ with $- 7 x^{2}$ .

$- 2744 (x^{3} (e^{- 7 x^{2}} \frac{d}{d x} [- 7 x^{2}]) + e^{- 7 x^{2}} \frac{d}{d x} [x^{3}]) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.4

Since $- 7$ is constant with respect to $x$ , the derivative of $- 7 x^{2}$ with respect to $x$ is $- 7 \frac{d}{d x} [x^{2}]$ .

$- 2744 (x^{3} (e^{- 7 x^{2}} (- 7 \frac{d}{d x} [x^{2}])) + e^{- 7 x^{2}} \frac{d}{d x} [x^{3}]) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$- 2744 (x^{3} (e^{- 7 x^{2}} (- 7 (2 x))) + e^{- 7 x^{2}} \frac{d}{d x} [x^{3}]) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.6

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$- 2744 (x^{3} (e^{- 7 x^{2}} (- 7 (2 x))) + e^{- 7 x^{2}} (3 x^{2})) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.7

Multiply $2$ by $- 7$ .

$- 2744 (x^{3} (e^{- 7 x^{2}} (- 14 x)) + e^{- 7 x^{2}} (3 x^{2})) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.8

Multiply $x^{3}$ by $x$ by adding the exponents.

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Step 4.2.8.1

Move $x$ .

$- 2744 (x \cdot x^{3} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} (3 x^{2})) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.8.2

Multiply $x$ by $x^{3}$ .

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Step 4.2.8.2.1

Raise $x$ to the power of $1$ .

$- 2744 (x^{1} x^{3} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} (3 x^{2})) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.8.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$- 2744 (x^{1 + 3} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} (3 x^{2})) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.8.3

Add $1$ and $3$ .

$- 2744 (x^{4} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} (3 x^{2})) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.2.9

Move $- 14$ to the left of $e^{- 7 x^{2}}$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + \frac{d}{d x} [588 x e^{- 7 x^{2}}]$

Step 4.3

Evaluate $\frac{d}{d x} [588 x e^{- 7 x^{2}}]$ .

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Step 4.3.1

Since $588$ is constant with respect to $x$ , the derivative of $588 x e^{- 7 x^{2}}$ with respect to $x$ is $588 \frac{d}{d x} [x e^{- 7 x^{2}}]$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 \frac{d}{d x} [x e^{- 7 x^{2}}]$

Step 4.3.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = e^{- 7 x^{2}}$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x \frac{d}{d x} [e^{- 7 x^{2}}] + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 4.3.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = - 7 x^{2}$ .

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Step 4.3.3.1

To apply the Chain Rule, set $u_{2}$ as $- 7 x^{2}$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x (\frac{d}{d u_{2}} [e^{u_{2}}] \frac{d}{d x} [- 7 x^{2}]) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 4.3.3.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{2}} [a^{u_{2}}]$ is $a^{u_{2}} \ln (a)$ where $a$ = $e$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x (e^{u_{2}} \frac{d}{d x} [- 7 x^{2}]) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 4.3.3.3

Replace all occurrences of $u_{2}$ with $- 7 x^{2}$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x (e^{- 7 x^{2}} \frac{d}{d x} [- 7 x^{2}]) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 4.3.4

Since $- 7$ is constant with respect to $x$ , the derivative of $- 7 x^{2}$ with respect to $x$ is $- 7 \frac{d}{d x} [x^{2}]$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x (e^{- 7 x^{2}} (- 7 \frac{d}{d x} [x^{2}])) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 4.3.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x (e^{- 7 x^{2}} (- 7 (2 x))) + e^{- 7 x^{2}} \frac{d}{d x} [x])$

Step 4.3.6

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x (e^{- 7 x^{2}} (- 7 (2 x))) + e^{- 7 x^{2}} \cdot 1)$

Step 4.3.7

Multiply $2$ by $- 7$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x (e^{- 7 x^{2}} (- 14 x)) + e^{- 7 x^{2}} \cdot 1)$

Step 4.3.8

Raise $x$ to the power of $1$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x^{1} x (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} \cdot 1)$

Step 4.3.9

Raise $x$ to the power of $1$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x^{1} x^{1} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} \cdot 1)$

Step 4.3.10

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x^{1 + 1} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} \cdot 1)$

Step 4.3.11

Add $1$ and $1$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x^{2} (e^{- 7 x^{2}} \cdot (- 14)) + e^{- 7 x^{2}} \cdot 1)$

Step 4.3.12

Move $- 14$ to the left of $e^{- 7 x^{2}}$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x^{2} (- 14 \cdot e^{- 7 x^{2}}) + e^{- 7 x^{2}} \cdot 1)$

Step 4.3.13

Multiply $e^{- 7 x^{2}}$ by $1$ .

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}} (3 x^{2})) + 588 (x^{2} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}})$

Step 4.4

Simplify.

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Step 4.4.1

Apply the distributive property.

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}})) - 2744 (e^{- 7 x^{2}} (3 x^{2})) + 588 (x^{2} (- 14 e^{- 7 x^{2}}) + e^{- 7 x^{2}})$

Step 4.4.2

Apply the distributive property.

$- 2744 (x^{4} (- 14 e^{- 7 x^{2}})) - 2744 (e^{- 7 x^{2}} (3 x^{2})) + 588 (x^{2} (- 14 e^{- 7 x^{2}})) + 588 e^{- 7 x^{2}}$

Step 4.4.3

Combine terms.

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Step 4.4.3.1

Multiply $- 14$ by $- 2744$ .

$38416 (x^{4} (e^{- 7 x^{2}})) - 2744 (e^{- 7 x^{2}} (3 x^{2})) + 588 (x^{2} (- 14 e^{- 7 x^{2}})) + 588 e^{- 7 x^{2}}$

Step 4.4.3.2

Multiply $3$ by $- 2744$ .

$38416 x^{4} e^{- 7 x^{2}} - 8232 (e^{- 7 x^{2}} (x^{2})) + 588 (x^{2} (- 14 e^{- 7 x^{2}})) + 588 e^{- 7 x^{2}}$

Step 4.4.3.3

Multiply $- 14$ by $588$ .

$38416 x^{4} e^{- 7 x^{2}} - 8232 e^{- 7 x^{2}} x^{2} - 8232 (x^{2} (e^{- 7 x^{2}})) + 588 e^{- 7 x^{2}}$

Step 4.4.3.4

Subtract $8232 x^{2} e^{- 7 x^{2}}$ from $- 8232 e^{- 7 x^{2}} x^{2}$ .

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Step 4.4.3.4.1

Move $e^{- 7 x^{2}}$ .

$38416 x^{4} e^{- 7 x^{2}} - 8232 x^{2} e^{- 7 x^{2}} - 8232 x^{2} e^{- 7 x^{2}} + 588 e^{- 7 x^{2}}$

Step 4.4.3.4.2

Subtract $8232 x^{2} e^{- 7 x^{2}}$ from $- 8232 x^{2} e^{- 7 x^{2}}$ .

$38416 x^{4} e^{- 7 x^{2}} - 16464 x^{2} e^{- 7 x^{2}} + 588 e^{- 7 x^{2}}$

Step 4.4.4

Reorder terms.

$38416 e^{- 7 x^{2}} x^{4} - 16464 e^{- 7 x^{2}} x^{2} + 588 e^{- 7 x^{2}}$

Step 4.4.5

Reorder factors in $38416 e^{- 7 x^{2}} x^{4} - 16464 e^{- 7 x^{2}} x^{2} + 588 e^{- 7 x^{2}}$ .

$f^{4} (x) = 38416 x^{4} e^{- 7 x^{2}} - 16464 x^{2} e^{- 7 x^{2}} + 588 e^{- 7 x^{2}}$

Step 5

The fourth derivative of $f (x)$ with respect to $x$ is $38416 x^{4} e^{- 7 x^{2}} - 16464 x^{2} e^{- 7 x^{2}} + 588 e^{- 7 x^{2}}$ .

$38416 x^{4} e^{- 7 x^{2}} - 16464 x^{2} e^{- 7 x^{2}} + 588 e^{- 7 x^{2}}$