Calculus Examples

Find the Derivative - d/dx sin(x)sin(x)
sin(x)sin(x)
Step 1
Raise sin(x) to the power of 1.
ddx[sin1(x)sin(x)]
Step 2
Raise sin(x) to the power of 1.
ddx[sin1(x)sin1(x)]
Step 3
Use the power rule aman=am+n to combine exponents.
ddx[sin(x)1+1]
Step 4
Add 1 and 1.
ddx[sin2(x)]
Step 5
Differentiate using the chain rule, which states that ddx[f(g(x))] is f(g(x))g(x) where f(x)=x2 and g(x)=sin(x).
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Step 5.1
To apply the Chain Rule, set u as sin(x).
ddu[u2]ddx[sin(x)]
Step 5.2
Differentiate using the Power Rule which states that ddu[un] is nun-1 where n=2.
2uddx[sin(x)]
Step 5.3
Replace all occurrences of u with sin(x).
2sin(x)ddx[sin(x)]
2sin(x)ddx[sin(x)]
Step 6
The derivative of sin(x) with respect to x is cos(x).
2sin(x)cos(x)
Step 7
Simplify.
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Step 7.1
Reorder the factors of 2sin(x)cos(x).
2cos(x)sin(x)
Step 7.2
Reorder 2cos(x) and sin(x).
sin(x)(2cos(x))
Step 7.3
Reorder sin(x) and 2.
2sin(x)cos(x)
Step 7.4
Apply the sine double-angle identity.
sin(2x)
sin(2x)
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