Calculus Examples

$y = 17^{x}$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d y} (y) = \frac{d}{d y} (17^{x})$

Step 2

Differentiate using the Power Rule which states that $\frac{d}{d y} [y^{n}]$ is $n y^{n - 1}$ where $n = 1$ .

$1$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Differentiate using the chain rule, which states that $\frac{d}{d y} [f (g (y))]$ is $f' (g (y)) g' (y)$ where $f (y) = 17^{y}$ and $g (y) = x$ .

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Step 3.1.1

To apply the Chain Rule, set $u$ as $x$ .

$\frac{d}{d u} [17^{u}] \frac{d}{d y} [x]$

Step 3.1.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u} [a^{u}]$ is $a^{u} \ln (a)$ where $a$ = $17$ .

$17^{u} \ln (17) \frac{d}{d y} [x]$

Step 3.1.3

Replace all occurrences of $u$ with $x$ .

$17^{x} \ln (17) \frac{d}{d y} [x]$

Step 3.2

Rewrite $\frac{d}{d y} [x]$ as $x'$ .

$17^{x} \ln (17) x'$

Step 4

Reform the equation by setting the left side equal to the right side.

$1 = 17^{x} \ln (17) x'$

Step 5

Solve for $x'$ .

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Step 5.1

Rewrite the equation as $17^{x} \ln (17) x' = 1$ .

$17^{x} \ln (17) x' = 1$

Step 5.2

Divide each term in $17^{x} \ln (17) x' = 1$ by $17^{x} \ln (17)$ and simplify.

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Step 5.2.1

Divide each term in $17^{x} \ln (17) x' = 1$ by $17^{x} \ln (17)$ .

$\frac{17^{x} \ln (17) x'}{17^{x} \ln (17)} = \frac{1}{17^{x} \ln (17)}$

Step 5.2.2

Simplify the left side.

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Step 5.2.2.1

Cancel the common factor of $17^{x}$ .

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Step 5.2.2.1.1

Cancel the common factor.

$\frac{17^{x} \ln (17) x'}{17^{x} \ln (17)} = \frac{1}{17^{x} \ln (17)}$

Step 5.2.2.1.2

Rewrite the expression.

$\frac{\ln (17) x'}{\ln (17)} = \frac{1}{17^{x} \ln (17)}$

Step 5.2.2.2

Cancel the common factor of $\ln (17)$ .

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Step 5.2.2.2.1

Cancel the common factor.

$\frac{\ln (17) x'}{\ln (17)} = \frac{1}{17^{x} \ln (17)}$

Step 5.2.2.2.2

Divide $x'$ by $1$ .

$x' = \frac{1}{17^{x} \ln (17)}$

Step 6

Replace $x'$ with $\frac{d x}{d y}$ .

$\frac{d x}{d y} = \frac{1}{17^{x} \ln (17)}$