Calculus Examples

$5 x^{3} + x y^{2} = 5 x^{3} y^{3}$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (5 x^{3} + x y^{2}) = \frac{d}{d x} (5 x^{3} y^{3})$

Step 2

Differentiate the left side of the equation.

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Step 2.1

By the Sum Rule, the derivative of $5 x^{3} + x y^{2}$ with respect to $x$ is $\frac{d}{d x} [5 x^{3}] + \frac{d}{d x} [x y^{2}]$ .

$\frac{d}{d x} [5 x^{3}] + \frac{d}{d x} [x y^{2}]$

Step 2.2

Evaluate $\frac{d}{d x} [5 x^{3}]$ .

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Step 2.2.1

Since $5$ is constant with respect to $x$ , the derivative of $5 x^{3}$ with respect to $x$ is $5 \frac{d}{d x} [x^{3}]$ .

$5 \frac{d}{d x} [x^{3}] + \frac{d}{d x} [x y^{2}]$

Step 2.2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$5 (3 x^{2}) + \frac{d}{d x} [x y^{2}]$

Step 2.2.3

Multiply $3$ by $5$ .

$15 x^{2} + \frac{d}{d x} [x y^{2}]$

Step 2.3

Evaluate $\frac{d}{d x} [x y^{2}]$ .

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Step 2.3.1

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = y^{2}$ .

$15 x^{2} + x \frac{d}{d x} [y^{2}] + y^{2} \frac{d}{d x} [x]$

Step 2.3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = y$ .

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Step 2.3.2.1

To apply the Chain Rule, set $u$ as $y$ .

$15 x^{2} + x (\frac{d}{d u} [u^{2}] \frac{d}{d x} [y]) + y^{2} \frac{d}{d x} [x]$

Step 2.3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$15 x^{2} + x (2 u \frac{d}{d x} [y]) + y^{2} \frac{d}{d x} [x]$

Step 2.3.2.3

Replace all occurrences of $u$ with $y$ .

$15 x^{2} + x (2 y \frac{d}{d x} [y]) + y^{2} \frac{d}{d x} [x]$

Step 2.3.3

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$15 x^{2} + x (2 y y') + y^{2} \frac{d}{d x} [x]$

Step 2.3.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$15 x^{2} + x (2 y y') + y^{2} \cdot 1$

Step 2.3.5

Move $2$ to the left of $x$ .

$15 x^{2} + 2 \cdot x y y' + y^{2} \cdot 1$

Step 2.3.6

Multiply $y^{2}$ by $1$ .

$15 x^{2} + 2 x y y' + y^{2}$

Step 2.4

Reorder terms.

$15 x^{2} + y^{2} + 2 x y y'$

Step 3

Differentiate the right side of the equation.

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Step 3.1

Since $5$ is constant with respect to $x$ , the derivative of $5 x^{3} y^{3}$ with respect to $x$ is $5 \frac{d}{d x} [x^{3} y^{3}]$ .

$5 \frac{d}{d x} [x^{3} y^{3}]$

Step 3.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{3}$ and $g (x) = y^{3}$ .

$5 (x^{3} \frac{d}{d x} [y^{3}] + y^{3} \frac{d}{d x} [x^{3}])$

Step 3.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{3}$ and $g (x) = y$ .

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Step 3.3.1

To apply the Chain Rule, set $u$ as $y$ .

$5 (x^{3} (\frac{d}{d u} [u^{3}] \frac{d}{d x} [y]) + y^{3} \frac{d}{d x} [x^{3}])$

Step 3.3.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 3$ .

$5 (x^{3} (3 u^{2} \frac{d}{d x} [y]) + y^{3} \frac{d}{d x} [x^{3}])$

Step 3.3.3

Replace all occurrences of $u$ with $y$ .

$5 (x^{3} (3 y^{2} \frac{d}{d x} [y]) + y^{3} \frac{d}{d x} [x^{3}])$

Step 3.4

Move $3$ to the left of $x^{3}$ .

$5 (3 \cdot x^{3} y^{2} \frac{d}{d x} [y] + y^{3} \frac{d}{d x} [x^{3}])$

Step 3.5

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$5 (3 x^{3} y^{2} y' + y^{3} \frac{d}{d x} [x^{3}])$

Step 3.6

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$5 (3 x^{3} y^{2} y' + y^{3} (3 x^{2}))$

Step 3.7

Move $3$ to the left of $y^{3}$ .

$5 (3 x^{3} y^{2} y' + 3 \cdot y^{3} x^{2})$

Step 3.8

Simplify.

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Step 3.8.1

Apply the distributive property.

$5 (3 x^{3} y^{2} y') + 5 (3 y^{3} x^{2})$

Step 3.8.2

Combine terms.

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Step 3.8.2.1

Multiply $3$ by $5$ .

$15 (x^{3} y^{2} y') + 5 (3 y^{3} x^{2})$

Step 3.8.2.2

Multiply $3$ by $5$ .

$15 x^{3} y^{2} y' + 15 y^{3} x^{2}$

Step 4

Reform the equation by setting the left side equal to the right side.

$15 x^{2} + y^{2} + 2 x y y' = 15 x^{3} y^{2} y' + 15 y^{3} x^{2}$

Step 5

Solve for $y'$ .

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Step 5.1

Subtract $15 x^{3} y^{2} y'$ from both sides of the equation.

$15 x^{2} + y^{2} + 2 x y y' - 15 x^{3} y^{2} y' = 15 y^{3} x^{2}$

Step 5.2

Move all terms not containing $y'$ to the right side of the equation.

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Step 5.2.1

Subtract $15 x^{2}$ from both sides of the equation.

$y^{2} + 2 x y y' - 15 x^{3} y^{2} y' = 15 y^{3} x^{2} - 15 x^{2}$

Step 5.2.2

Subtract $y^{2}$ from both sides of the equation.

$2 x y y' - 15 x^{3} y^{2} y' = 15 y^{3} x^{2} - 15 x^{2} - y^{2}$

Step 5.3

Factor $x y y'$ out of $2 x y y' - 15 x^{3} y^{2} y'$ .

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Step 5.3.1

Factor $x y y'$ out of $2 x y y'$ .

$x y y' \cdot 2 - 15 x^{3} y^{2} y' = 15 y^{3} x^{2} - 15 x^{2} - y^{2}$

Step 5.3.2

Factor $x y y'$ out of $- 15 x^{3} y^{2} y'$ .

$x y y' \cdot 2 + x y y' (- 15 x^{2} y) = 15 y^{3} x^{2} - 15 x^{2} - y^{2}$

Step 5.3.3

Factor $x y y'$ out of $x y y' \cdot 2 + x y y' (- 15 x^{2} y)$ .

$x y y' (2 - 15 x^{2} y) = 15 y^{3} x^{2} - 15 x^{2} - y^{2}$

Step 5.4

Divide each term in $x y y' (2 - 15 x^{2} y) = 15 y^{3} x^{2} - 15 x^{2} - y^{2}$ by $x y (2 - 15 x^{2} y)$ and simplify.

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Step 5.4.1

Divide each term in $x y y' (2 - 15 x^{2} y) = 15 y^{3} x^{2} - 15 x^{2} - y^{2}$ by $x y (2 - 15 x^{2} y)$ .

$\frac{x y y' (2 - 15 x^{2} y)}{x y (2 - 15 x^{2} y)} = \frac{15 y^{3} x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.2

Simplify the left side.

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Step 5.4.2.1

Cancel the common factor of $x$ .

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Step 5.4.2.1.1

Cancel the common factor.

$\frac{x y y' (2 - 15 x^{2} y)}{x y (2 - 15 x^{2} y)} = \frac{15 y^{3} x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.2.1.2

Rewrite the expression.

$\frac{y y' (2 - 15 x^{2} y)}{y (2 - 15 x^{2} y)} = \frac{15 y^{3} x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.2.2

Cancel the common factor of $y$ .

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Step 5.4.2.2.1

Cancel the common factor.

$\frac{y y' (2 - 15 x^{2} y)}{y (2 - 15 x^{2} y)} = \frac{15 y^{3} x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.2.2.2

Rewrite the expression.

$\frac{y' (2 - 15 x^{2} y)}{2 - 15 x^{2} y} = \frac{15 y^{3} x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.2.3

Cancel the common factor of $2 - 15 x^{2} y$ .

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Step 5.4.2.3.1

Cancel the common factor.

$\frac{y' (2 - 15 x^{2} y)}{2 - 15 x^{2} y} = \frac{15 y^{3} x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.2.3.2

Divide $y'$ by $1$ .

$y' = \frac{15 y^{3} x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3

Simplify the right side.

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Step 5.4.3.1

Simplify each term.

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Step 5.4.3.1.1

Cancel the common factor of $y^{3}$ and $y$ .

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Step 5.4.3.1.1.1

Factor $y$ out of $15 y^{3} x^{2}$ .

$y' = \frac{y (15 y^{2} x^{2})}{x y (2 - 15 x^{2} y)} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.1.2

Cancel the common factors.

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Step 5.4.3.1.1.2.1

Factor $y$ out of $x y (2 - 15 x^{2} y)$ .

$y' = \frac{y (15 y^{2} x^{2})}{y (x (2 - 15 x^{2} y))} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.1.2.2

Cancel the common factor.

$y' = \frac{y (15 y^{2} x^{2})}{y (x (2 - 15 x^{2} y))} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.1.2.3

Rewrite the expression.

$y' = \frac{15 y^{2} x^{2}}{x (2 - 15 x^{2} y)} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.2

Cancel the common factor of $x^{2}$ and $x$ .

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Step 5.4.3.1.2.1

Factor $x$ out of $15 y^{2} x^{2}$ .

$y' = \frac{x (15 y^{2} x)}{x (2 - 15 x^{2} y)} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.2.2

Cancel the common factors.

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Step 5.4.3.1.2.2.1

Cancel the common factor.

$y' = \frac{x (15 y^{2} x)}{x (2 - 15 x^{2} y)} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.2.2.2

Rewrite the expression.

$y' = \frac{15 y^{2} x}{2 - 15 x^{2} y} + \frac{- 15 x^{2}}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.3

Cancel the common factor of $x^{2}$ and $x$ .

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Step 5.4.3.1.3.1

Factor $x$ out of $- 15 x^{2}$ .

$y' = \frac{15 y^{2} x}{2 - 15 x^{2} y} + \frac{x (- 15 x)}{x y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.3.2

Cancel the common factors.

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Step 5.4.3.1.3.2.1

Factor $x$ out of $x y (2 - 15 x^{2} y)$ .

$y' = \frac{15 y^{2} x}{2 - 15 x^{2} y} + \frac{x (- 15 x)}{x (y (2 - 15 x^{2} y))} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.3.2.2

Cancel the common factor.

$y' = \frac{15 y^{2} x}{2 - 15 x^{2} y} + \frac{x (- 15 x)}{x (y (2 - 15 x^{2} y))} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.3.2.3

Rewrite the expression.

$y' = \frac{15 y^{2} x}{2 - 15 x^{2} y} + \frac{- 15 x}{y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.4

Move the negative in front of the fraction.

$y' = \frac{15 y^{2} x}{2 - 15 x^{2} y} - \frac{15 x}{y (2 - 15 x^{2} y)} + \frac{- y^{2}}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.5

Cancel the common factor of $y^{2}$ and $y$ .

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Step 5.4.3.1.5.1

Factor $y$ out of $- y^{2}$ .

$y' = \frac{15 y^{2} x}{2 - 15 x^{2} y} - \frac{15 x}{y (2 - 15 x^{2} y)} + \frac{y (- y)}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.1.5.2

Cancel the common factors.

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Step 5.4.3.1.5.2.1

Factor $y$ out of $x y (2 - 15 x^{2} y)$ .

$y' = \frac{15 y^{2} x}{2 - 15 x^{2} y} - \frac{15 x}{y (2 - 15 x^{2} y)} + \frac{y (- y)}{y (x (2 - 15 x^{2} y))}$

Step 5.4.3.1.5.2.2

Cancel the common factor.

$y' = \frac{15 y^{2} x}{2 - 15 x^{2} y} - \frac{15 x}{y (2 - 15 x^{2} y)} + \frac{y (- y)}{y (x (2 - 15 x^{2} y))}$

Step 5.4.3.1.5.2.3

Rewrite the expression.

$y' = \frac{15 y^{2} x}{2 - 15 x^{2} y} - \frac{15 x}{y (2 - 15 x^{2} y)} + \frac{- y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.1.6

Move the negative in front of the fraction.

$y' = \frac{15 y^{2} x}{2 - 15 x^{2} y} - \frac{15 x}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.2

To write $\frac{15 y^{2} x}{2 - 15 x^{2} y}$ as a fraction with a common denominator, multiply by $\frac{y}{y}$ .

$y' = \frac{15 y^{2} x}{2 - 15 x^{2} y} \cdot \frac{y}{y} - \frac{15 x}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.3

Write each expression with a common denominator of $(2 - 15 x^{2} y) y$ , by multiplying each by an appropriate factor of $1$ .

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Step 5.4.3.3.1

Multiply $\frac{15 y^{2} x}{2 - 15 x^{2} y}$ by $\frac{y}{y}$ .

$y' = \frac{15 y^{2} x y}{(2 - 15 x^{2} y) y} - \frac{15 x}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.3.2

Reorder the factors of $(2 - 15 x^{2} y) y$ .

$y' = \frac{15 y^{2} x y}{y (2 - 15 x^{2} y)} - \frac{15 x}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.4

Combine the numerators over the common denominator.

$y' = \frac{15 y^{2} x y - 15 x}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.5

Simplify the numerator.

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Step 5.4.3.5.1

Factor $15 x$ out of $15 y^{2} x y - 15 x$ .

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Step 5.4.3.5.1.1

Factor $15 x$ out of $15 y^{2} x y$ .

$y' = \frac{15 x (y^{2} y) - 15 x}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.5.1.2

Factor $15 x$ out of $- 15 x$ .

$y' = \frac{15 x (y^{2} y) + 15 x (- 1)}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.5.1.3

Factor $15 x$ out of $15 x (y^{2} y) + 15 x (- 1)$ .

$y' = \frac{15 x (y^{2} y - 1)}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.5.2

Multiply $y^{2}$ by $y$ by adding the exponents.

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Step 5.4.3.5.2.1

Multiply $y^{2}$ by $y$ .

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Step 5.4.3.5.2.1.1

Raise $y$ to the power of $1$ .

$y' = \frac{15 x (y^{2} y^{1} - 1)}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.5.2.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y' = \frac{15 x (y^{2 + 1} - 1)}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.5.2.2

Add $2$ and $1$ .

$y' = \frac{15 x (y^{3} - 1)}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.5.3

Rewrite $1$ as $1^{3}$ .

$y' = \frac{15 x (y^{3} - 1^{3})}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.5.4

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = y$ and $b = 1$ .

$y' = \frac{15 x ((y - 1) (y^{2} + y \cdot 1 + 1^{2}))}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.5.5

Simplify.

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Step 5.4.3.5.5.1

Multiply $y$ by $1$ .

$y' = \frac{15 x ((y - 1) (y^{2} + y + 1^{2}))}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.5.5.2

One to any power is one.

$y' = \frac{15 x ((y - 1) (y^{2} + y + 1))}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

$y' = \frac{15 x (y - 1) (y^{2} + y + 1)}{y (2 - 15 x^{2} y)} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.6

To write $\frac{15 x (y - 1) (y^{2} + y + 1)}{y (2 - 15 x^{2} y)}$ as a fraction with a common denominator, multiply by $\frac{x}{x}$ .

$y' = \frac{15 x (y - 1) (y^{2} + y + 1)}{y (2 - 15 x^{2} y)} \cdot \frac{x}{x} - \frac{y}{x (2 - 15 x^{2} y)}$

Step 5.4.3.7

To write $- \frac{y}{x (2 - 15 x^{2} y)}$ as a fraction with a common denominator, multiply by $\frac{y}{y}$ .

$y' = \frac{15 x (y - 1) (y^{2} + y + 1)}{y (2 - 15 x^{2} y)} \cdot \frac{x}{x} - \frac{y}{x (2 - 15 x^{2} y)} \cdot \frac{y}{y}$

Step 5.4.3.8

Write each expression with a common denominator of $y (2 - 15 x^{2} y) x$ , by multiplying each by an appropriate factor of $1$ .

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Step 5.4.3.8.1

Multiply $\frac{15 x (y - 1) (y^{2} + y + 1)}{y (2 - 15 x^{2} y)}$ by $\frac{x}{x}$ .

$y' = \frac{15 x (y - 1) (y^{2} + y + 1) x}{y (2 - 15 x^{2} y) x} - \frac{y}{x (2 - 15 x^{2} y)} \cdot \frac{y}{y}$

Step 5.4.3.8.2

Multiply $\frac{y}{x (2 - 15 x^{2} y)}$ by $\frac{y}{y}$ .

$y' = \frac{15 x (y - 1) (y^{2} + y + 1) x}{y (2 - 15 x^{2} y) x} - \frac{y \cdot y}{x (2 - 15 x^{2} y) y}$

Step 5.4.3.8.3

Reorder the factors of $y (2 - 15 x^{2} y) x$ .

$y' = \frac{15 x (y - 1) (y^{2} + y + 1) x}{x y (2 - 15 x^{2} y)} - \frac{y \cdot y}{x (2 - 15 x^{2} y) y}$

Step 5.4.3.8.4

Reorder the factors of $x (2 - 15 x^{2} y) y$ .

$y' = \frac{15 x (y - 1) (y^{2} + y + 1) x}{x y (2 - 15 x^{2} y)} - \frac{y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.9

Combine the numerators over the common denominator.

$y' = \frac{15 x (y - 1) (y^{2} + y + 1) x - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10

Simplify the numerator.

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Step 5.4.3.10.1

Multiply $x$ by $x$ by adding the exponents.

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Step 5.4.3.10.1.1

Move $x$ .

$y' = \frac{15 (x \cdot x) (y - 1) (y^{2} + y + 1) - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.1.2

Multiply $x$ by $x$ .

$y' = \frac{15 x^{2} (y - 1) (y^{2} + y + 1) - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.2

Apply the distributive property.

$y' = \frac{(15 x^{2} y + 15 x^{2} \cdot - 1) (y^{2} + y + 1) - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.3

Multiply $- 1$ by $15$ .

$y' = \frac{(15 x^{2} y - 15 x^{2}) (y^{2} + y + 1) - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.4

Expand $(15 x^{2} y - 15 x^{2}) (y^{2} + y + 1)$ by multiplying each term in the first expression by each term in the second expression.

$y' = \frac{15 x^{2} y \cdot y^{2} + 15 x^{2} y \cdot y + 15 x^{2} y \cdot 1 - 15 x^{2} y^{2} - 15 x^{2} y - 15 x^{2} \cdot 1 - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.5

Simplify each term.

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Step 5.4.3.10.5.1

Multiply $y$ by $y^{2}$ by adding the exponents.

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Step 5.4.3.10.5.1.1

Move $y^{2}$ .

$y' = \frac{15 x^{2} (y^{2} y) + 15 x^{2} y \cdot y + 15 x^{2} y \cdot 1 - 15 x^{2} y^{2} - 15 x^{2} y - 15 x^{2} \cdot 1 - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.5.1.2

Multiply $y^{2}$ by $y$ .

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Step 5.4.3.10.5.1.2.1

Raise $y$ to the power of $1$ .

$y' = \frac{15 x^{2} (y^{2} y^{1}) + 15 x^{2} y \cdot y + 15 x^{2} y \cdot 1 - 15 x^{2} y^{2} - 15 x^{2} y - 15 x^{2} \cdot 1 - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.5.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y' = \frac{15 x^{2} y^{2 + 1} + 15 x^{2} y \cdot y + 15 x^{2} y \cdot 1 - 15 x^{2} y^{2} - 15 x^{2} y - 15 x^{2} \cdot 1 - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.5.1.3

Add $2$ and $1$ .

$y' = \frac{15 x^{2} y^{3} + 15 x^{2} y \cdot y + 15 x^{2} y \cdot 1 - 15 x^{2} y^{2} - 15 x^{2} y - 15 x^{2} \cdot 1 - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.5.2

Multiply $y$ by $y$ by adding the exponents.

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Step 5.4.3.10.5.2.1

Move $y$ .

$y' = \frac{15 x^{2} y^{3} + 15 x^{2} (y \cdot y) + 15 x^{2} y \cdot 1 - 15 x^{2} y^{2} - 15 x^{2} y - 15 x^{2} \cdot 1 - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.5.2.2

Multiply $y$ by $y$ .

$y' = \frac{15 x^{2} y^{3} + 15 x^{2} y^{2} + 15 x^{2} y \cdot 1 - 15 x^{2} y^{2} - 15 x^{2} y - 15 x^{2} \cdot 1 - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.5.3

Multiply $15$ by $1$ .

$y' = \frac{15 x^{2} y^{3} + 15 x^{2} y^{2} + 15 x^{2} y - 15 x^{2} y^{2} - 15 x^{2} y - 15 x^{2} \cdot 1 - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.5.4

Multiply $- 15$ by $1$ .

$y' = \frac{15 x^{2} y^{3} + 15 x^{2} y^{2} + 15 x^{2} y - 15 x^{2} y^{2} - 15 x^{2} y - 15 x^{2} - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.6

Combine the opposite terms in $15 x^{2} y^{3} + 15 x^{2} y^{2} + 15 x^{2} y - 15 x^{2} y^{2} - 15 x^{2} y - 15 x^{2}$ .

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Step 5.4.3.10.6.1

Subtract $15 x^{2} y^{2}$ from $15 x^{2} y^{2}$ .

$y' = \frac{15 x^{2} y^{3} + 15 x^{2} y + 0 - 15 x^{2} y - 15 x^{2} - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.6.2

Add $15 x^{2} y^{3} + 15 x^{2} y$ and $0$ .

$y' = \frac{15 x^{2} y^{3} + 15 x^{2} y - 15 x^{2} y - 15 x^{2} - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.6.3

Subtract $15 x^{2} y$ from $15 x^{2} y$ .

$y' = \frac{15 x^{2} y^{3} + 0 - 15 x^{2} - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.6.4

Add $15 x^{2} y^{3}$ and $0$ .

$y' = \frac{15 x^{2} y^{3} - 15 x^{2} - y \cdot y}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.7

Multiply $y$ by $y$ by adding the exponents.

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Step 5.4.3.10.7.1

Move $y$ .

$y' = \frac{15 x^{2} y^{3} - 15 x^{2} - (y \cdot y)}{x y (2 - 15 x^{2} y)}$

Step 5.4.3.10.7.2

Multiply $y$ by $y$ .

$y' = \frac{15 x^{2} y^{3} - 15 x^{2} - y^{2}}{x y (2 - 15 x^{2} y)}$

Step 6

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = \frac{15 x^{2} y^{3} - 15 x^{2} - y^{2}}{x y (2 - 15 x^{2} y)}$