Calculus Examples

$f (x) = \frac{4 x}{x^{2} - 25}$

Step 1

Find where the expression $\frac{4 x}{x^{2} - 25}$ is undefined.

$x = - 5, x = 5$

Step 2

Since $\frac{4 x}{x^{2} - 25}$ $\to$ $- \infty$ as $x$ $\to$ $- 5$ from the left and $\frac{4 x}{x^{2} - 25}$ $\to$ $\infty$ as $x$ $\to$ $- 5$ from the right, then $x = - 5$ is a vertical asymptote.

$x = - 5$

Step 3

Since $\frac{4 x}{x^{2} - 25}$ $\to$ $- \infty$ as $x$ $\to$ $5$ from the left and $\frac{4 x}{x^{2} - 25}$ $\to$ $\infty$ as $x$ $\to$ $5$ from the right, then $x = 5$ is a vertical asymptote.

$x = 5$

Step 4

List all of the vertical asymptotes:

$x = - 5, 5$

Step 5

Consider the rational function $R (x) = \frac{a x^{n}}{b x^{m}}$ where $n$ is the degree of the numerator and $m$ is the degree of the denominator.

1. If $n < m$ , then the x-axis, $y = 0$ , is the horizontal asymptote.

2. If $n = m$ , then the horizontal asymptote is the line $y = \frac{a}{b}$ .

3. If $n > m$ , then there is no horizontal asymptote (there is an oblique asymptote).

Step 6

Find $n$ and $m$ .

$n = 1$

$m = 2$

Step 7

Since $n < m$ , the x-axis, $y = 0$ , is the horizontal asymptote.

$y = 0$

Step 8

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

No Oblique Asymptotes

Step 9

This is the set of all asymptotes.

Vertical Asymptotes: $x = - 5, 5$

Horizontal Asymptotes: $y = 0$

No Oblique Asymptotes

Step 10