Calculus Examples

$f (x) = \sqrt{x} - 6 \sqrt[3]{x}$

Step 1

By the Sum Rule, the derivative of $\sqrt{x} - 6 \sqrt[3]{x}$ with respect to $x$ is $\frac{d}{d x} [\sqrt{x}] + \frac{d}{d x} [- 6 \sqrt[3]{x}]$ .

$\frac{d}{d x} [\sqrt{x}] + \frac{d}{d x} [- 6 \sqrt[3]{x}]$

Step 2

Evaluate $\frac{d}{d x} [\sqrt{x}]$ .

Tap for more steps...

Step 2.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$\frac{d}{d x} [x^{\frac{1}{2}}] + \frac{d}{d x} [- 6 \sqrt[3]{x}]$

Step 2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = \frac{1}{2}$ .

$\frac{1}{2} x^{\frac{1}{2} - 1} + \frac{d}{d x} [- 6 \sqrt[3]{x}]$

Step 2.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{1}{2} x^{\frac{1}{2} - 1 \cdot \frac{2}{2}} + \frac{d}{d x} [- 6 \sqrt[3]{x}]$

Step 2.4

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{1}{2} x^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} + \frac{d}{d x} [- 6 \sqrt[3]{x}]$

Step 2.5

Combine the numerators over the common denominator.

$\frac{1}{2} x^{\frac{1 - 1 \cdot 2}{2}} + \frac{d}{d x} [- 6 \sqrt[3]{x}]$

Step 2.6

Simplify the numerator.

Tap for more steps...

Step 2.6.1

Multiply $- 1$ by $2$ .

$\frac{1}{2} x^{\frac{1 - 2}{2}} + \frac{d}{d x} [- 6 \sqrt[3]{x}]$

Step 2.6.2

Subtract $2$ from $1$ .

$\frac{1}{2} x^{\frac{- 1}{2}} + \frac{d}{d x} [- 6 \sqrt[3]{x}]$

Step 2.7

Move the negative in front of the fraction.

$\frac{1}{2} x^{- \frac{1}{2}} + \frac{d}{d x} [- 6 \sqrt[3]{x}]$

Step 3

Evaluate $\frac{d}{d x} [- 6 \sqrt[3]{x}]$ .

Tap for more steps...

Step 3.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{x}$ as $x^{\frac{1}{3}}$ .

$\frac{1}{2} x^{- \frac{1}{2}} + \frac{d}{d x} [- 6 x^{\frac{1}{3}}]$

Step 3.2

Since $- 6$ is constant with respect to $x$ , the derivative of $- 6 x^{\frac{1}{3}}$ with respect to $x$ is $- 6 \frac{d}{d x} [x^{\frac{1}{3}}]$ .

$\frac{1}{2} x^{- \frac{1}{2}} - 6 \frac{d}{d x} [x^{\frac{1}{3}}]$

Step 3.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = \frac{1}{3}$ .

$\frac{1}{2} x^{- \frac{1}{2}} - 6 (\frac{1}{3} x^{\frac{1}{3} - 1})$

Step 3.4

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{1}{2} x^{- \frac{1}{2}} - 6 (\frac{1}{3} x^{\frac{1}{3} - 1 \cdot \frac{3}{3}})$

Step 3.5

Combine $- 1$ and $\frac{3}{3}$ .

$\frac{1}{2} x^{- \frac{1}{2}} - 6 (\frac{1}{3} x^{\frac{1}{3} + \frac{- 1 \cdot 3}{3}})$

Step 3.6

Combine the numerators over the common denominator.

$\frac{1}{2} x^{- \frac{1}{2}} - 6 (\frac{1}{3} x^{\frac{1 - 1 \cdot 3}{3}})$

Step 3.7

Simplify the numerator.

Tap for more steps...

Step 3.7.1

Multiply $- 1$ by $3$ .

$\frac{1}{2} x^{- \frac{1}{2}} - 6 (\frac{1}{3} x^{\frac{1 - 3}{3}})$

Step 3.7.2

Subtract $3$ from $1$ .

$\frac{1}{2} x^{- \frac{1}{2}} - 6 (\frac{1}{3} x^{\frac{- 2}{3}})$

Step 3.8

Move the negative in front of the fraction.

$\frac{1}{2} x^{- \frac{1}{2}} - 6 (\frac{1}{3} x^{- \frac{2}{3}})$

Step 3.9

Combine $\frac{1}{3}$ and $x^{- \frac{2}{3}}$ .

$\frac{1}{2} x^{- \frac{1}{2}} - 6 \frac{x^{- \frac{2}{3}}}{3}$

Step 3.10

Combine $- 6$ and $\frac{x^{- \frac{2}{3}}}{3}$ .

$\frac{1}{2} x^{- \frac{1}{2}} + \frac{- 6 x^{- \frac{2}{3}}}{3}$

Step 3.11

Move $x^{- \frac{2}{3}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{2} x^{- \frac{1}{2}} + \frac{- 6}{3 x^{\frac{2}{3}}}$

Step 3.12

Factor $3$ out of $- 6$ .

$\frac{1}{2} x^{- \frac{1}{2}} + \frac{3 \cdot - 2}{3 x^{\frac{2}{3}}}$

Step 3.13

Cancel the common factors.

Tap for more steps...

Step 3.13.1

Factor $3$ out of $3 x^{\frac{2}{3}}$ .

$\frac{1}{2} x^{- \frac{1}{2}} + \frac{3 \cdot - 2}{3 (x^{\frac{2}{3}})}$

Step 3.13.2

Cancel the common factor.

$\frac{1}{2} x^{- \frac{1}{2}} + \frac{3 \cdot - 2}{3 x^{\frac{2}{3}}}$

Step 3.13.3

Rewrite the expression.

$\frac{1}{2} x^{- \frac{1}{2}} + \frac{- 2}{x^{\frac{2}{3}}}$

Step 3.14

Move the negative in front of the fraction.

$\frac{1}{2} x^{- \frac{1}{2}} - \frac{2}{x^{\frac{2}{3}}}$

Step 4

Simplify.

Tap for more steps...

Step 4.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{2} \cdot \frac{1}{x^{\frac{1}{2}}} - \frac{2}{x^{\frac{2}{3}}}$

Step 4.2

Multiply $\frac{1}{2}$ by $\frac{1}{x^{\frac{1}{2}}}$ .

$\frac{1}{2 x^{\frac{1}{2}}} - \frac{2}{x^{\frac{2}{3}}}$