Calculus Examples

$f (x) = 4 x {(5 x + 3)}^{4}$

Step 1

Since $4$ is constant with respect to $x$ , the derivative of $4 x {(5 x + 3)}^{4}$ with respect to $x$ is $4 \frac{d}{d x} [x {(5 x + 3)}^{4}]$ .

$4 \frac{d}{d x} [x {(5 x + 3)}^{4}]$

Step 2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = {(5 x + 3)}^{4}$ .

$4 (x \frac{d}{d x} [{(5 x + 3)}^{4}] + {(5 x + 3)}^{4} \frac{d}{d x} [x])$

Step 3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{4}$ and $g (x) = 5 x + 3$ .

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Step 3.1

To apply the Chain Rule, set $u$ as $5 x + 3$ .

$4 (x (\frac{d}{d u} [u^{4}] \frac{d}{d x} [5 x + 3]) + {(5 x + 3)}^{4} \frac{d}{d x} [x])$

Step 3.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 4$ .

$4 (x (4 u^{3} \frac{d}{d x} [5 x + 3]) + {(5 x + 3)}^{4} \frac{d}{d x} [x])$

Step 3.3

Replace all occurrences of $u$ with $5 x + 3$ .

$4 (x (4 {(5 x + 3)}^{3} \frac{d}{d x} [5 x + 3]) + {(5 x + 3)}^{4} \frac{d}{d x} [x])$

Step 4

Differentiate.

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Step 4.1

By the Sum Rule, the derivative of $5 x + 3$ with respect to $x$ is $\frac{d}{d x} [5 x] + \frac{d}{d x} [3]$ .

$4 (x (4 {(5 x + 3)}^{3} (\frac{d}{d x} [5 x] + \frac{d}{d x} [3])) + {(5 x + 3)}^{4} \frac{d}{d x} [x])$

Step 4.2

Since $5$ is constant with respect to $x$ , the derivative of $5 x$ with respect to $x$ is $5 \frac{d}{d x} [x]$ .

$4 (x (4 {(5 x + 3)}^{3} (5 \frac{d}{d x} [x] + \frac{d}{d x} [3])) + {(5 x + 3)}^{4} \frac{d}{d x} [x])$

Step 4.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$4 (x (4 {(5 x + 3)}^{3} (5 \cdot 1 + \frac{d}{d x} [3])) + {(5 x + 3)}^{4} \frac{d}{d x} [x])$

Step 4.4

Multiply $5$ by $1$ .

$4 (x (4 {(5 x + 3)}^{3} (5 + \frac{d}{d x} [3])) + {(5 x + 3)}^{4} \frac{d}{d x} [x])$

Step 4.5

Since $3$ is constant with respect to $x$ , the derivative of $3$ with respect to $x$ is $0$ .

$4 (x (4 {(5 x + 3)}^{3} (5 + 0)) + {(5 x + 3)}^{4} \frac{d}{d x} [x])$

Step 4.6

Simplify the expression.

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Step 4.6.1

Add $5$ and $0$ .

$4 (x (4 {(5 x + 3)}^{3} \cdot 5) + {(5 x + 3)}^{4} \frac{d}{d x} [x])$

Step 4.6.2

Multiply $5$ by $4$ .

$4 (x (20 {(5 x + 3)}^{3}) + {(5 x + 3)}^{4} \frac{d}{d x} [x])$

Step 4.7

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$4 (x (20 {(5 x + 3)}^{3}) + {(5 x + 3)}^{4} \cdot 1)$

Step 4.8

Multiply ${(5 x + 3)}^{4}$ by $1$ .

$4 (x (20 {(5 x + 3)}^{3}) + {(5 x + 3)}^{4})$

Step 5

Simplify.

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Step 5.1

Apply the distributive property.

$4 (x (20 {(5 x + 3)}^{3})) + 4 {(5 x + 3)}^{4}$

Step 5.2

Multiply $20$ by $4$ .

$80 (x ({(5 x + 3)}^{3})) + 4 {(5 x + 3)}^{4}$

Step 5.3

Factor $4 {(5 x + 3)}^{3}$ out of $80 x {(5 x + 3)}^{3} + 4 {(5 x + 3)}^{4}$ .

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Step 5.3.1

Factor $4 {(5 x + 3)}^{3}$ out of $80 x {(5 x + 3)}^{3}$ .

$4 {(5 x + 3)}^{3} (20 x) + 4 {(5 x + 3)}^{4}$

Step 5.3.2

Factor $4 {(5 x + 3)}^{3}$ out of $4 {(5 x + 3)}^{4}$ .

$4 {(5 x + 3)}^{3} (20 x) + 4 {(5 x + 3)}^{3} (5 x + 3)$

Step 5.3.3

Factor $4 {(5 x + 3)}^{3}$ out of $4 {(5 x + 3)}^{3} (20 x) + 4 {(5 x + 3)}^{3} (5 x + 3)$ .

$4 {(5 x + 3)}^{3} (20 x + 5 x + 3)$

Step 5.4

Add $20 x$ and $5 x$ .

$4 {(5 x + 3)}^{3} (25 x + 3)$