Calculus Examples

$y = x^{6} \ln (x) - \frac{1}{4} x^{4}$

Step 1

By the Sum Rule, the derivative of $x^{6} \ln (x) - \frac{1}{4} x^{4}$ with respect to $x$ is $\frac{d}{d x} [x^{6} \ln (x)] + \frac{d}{d x} [- \frac{1}{4} x^{4}]$ .

$\frac{d}{d x} [x^{6} \ln (x)] + \frac{d}{d x} [- \frac{1}{4} x^{4}]$

Step 2

Evaluate $\frac{d}{d x} [x^{6} \ln (x)]$ .

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Step 2.1

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{6}$ and $g (x) = \ln (x)$ .

$x^{6} \frac{d}{d x} [\ln (x)] + \ln (x) \frac{d}{d x} [x^{6}] + \frac{d}{d x} [- \frac{1}{4} x^{4}]$

Step 2.2

The derivative of $\ln (x)$ with respect to $x$ is $\frac{1}{x}$ .

$x^{6} \frac{1}{x} + \ln (x) \frac{d}{d x} [x^{6}] + \frac{d}{d x} [- \frac{1}{4} x^{4}]$

Step 2.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 6$ .

$x^{6} \frac{1}{x} + \ln (x) (6 x^{5}) + \frac{d}{d x} [- \frac{1}{4} x^{4}]$

Step 2.4

Combine $x^{6}$ and $\frac{1}{x}$ .

$\frac{x^{6}}{x} + \ln (x) (6 x^{5}) + \frac{d}{d x} [- \frac{1}{4} x^{4}]$

Step 2.5

Cancel the common factor of $x^{6}$ and $x$ .

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Step 2.5.1

Factor $x$ out of $x^{6}$ .

$\frac{x \cdot x^{5}}{x} + \ln (x) (6 x^{5}) + \frac{d}{d x} [- \frac{1}{4} x^{4}]$

Step 2.5.2

Cancel the common factors.

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Step 2.5.2.1

Raise $x$ to the power of $1$ .

$\frac{x \cdot x^{5}}{x^{1}} + \ln (x) (6 x^{5}) + \frac{d}{d x} [- \frac{1}{4} x^{4}]$

Step 2.5.2.2

Factor $x$ out of $x^{1}$ .

$\frac{x \cdot x^{5}}{x \cdot 1} + \ln (x) (6 x^{5}) + \frac{d}{d x} [- \frac{1}{4} x^{4}]$

Step 2.5.2.3

Cancel the common factor.

$\frac{x \cdot x^{5}}{x \cdot 1} + \ln (x) (6 x^{5}) + \frac{d}{d x} [- \frac{1}{4} x^{4}]$

Step 2.5.2.4

Rewrite the expression.

$\frac{x^{5}}{1} + \ln (x) (6 x^{5}) + \frac{d}{d x} [- \frac{1}{4} x^{4}]$

Step 2.5.2.5

Divide $x^{5}$ by $1$ .

$x^{5} + \ln (x) (6 x^{5}) + \frac{d}{d x} [- \frac{1}{4} x^{4}]$

Step 3

Evaluate $\frac{d}{d x} [- \frac{1}{4} x^{4}]$ .

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Step 3.1

Since $- \frac{1}{4}$ is constant with respect to $x$ , the derivative of $- \frac{1}{4} x^{4}$ with respect to $x$ is $- \frac{1}{4} \frac{d}{d x} [x^{4}]$ .

$x^{5} + \ln (x) (6 x^{5}) - \frac{1}{4} \frac{d}{d x} [x^{4}]$

Step 3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$x^{5} + \ln (x) (6 x^{5}) - \frac{1}{4} (4 x^{3})$

Step 3.3

Multiply $4$ by $- 1$ .

$x^{5} + \ln (x) (6 x^{5}) - 4 (\frac{1}{4}) x^{3}$

Step 3.4

Combine $- 4$ and $\frac{1}{4}$ .

$x^{5} + \ln (x) (6 x^{5}) + \frac{- 4}{4} x^{3}$

Step 3.5

Combine $\frac{- 4}{4}$ and $x^{3}$ .

$x^{5} + \ln (x) (6 x^{5}) + \frac{- 4 x^{3}}{4}$

Step 3.6

Cancel the common factor of $- 4$ and $4$ .

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Step 3.6.1

Factor $4$ out of $- 4 x^{3}$ .

$x^{5} + \ln (x) (6 x^{5}) + \frac{4 (- x^{3})}{4}$

Step 3.6.2

Cancel the common factors.

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Step 3.6.2.1

Factor $4$ out of $4$ .

$x^{5} + \ln (x) (6 x^{5}) + \frac{4 (- x^{3})}{4 (1)}$

Step 3.6.2.2

Cancel the common factor.

$x^{5} + \ln (x) (6 x^{5}) + \frac{4 (- x^{3})}{4 \cdot 1}$

Step 3.6.2.3

Rewrite the expression.

$x^{5} + \ln (x) (6 x^{5}) + \frac{- x^{3}}{1}$

Step 3.6.2.4

Divide $- x^{3}$ by $1$ .

$x^{5} + \ln (x) (6 x^{5}) - x^{3}$

Step 4

Reorder terms.

$x^{5} - x^{3} + 6 x^{5} \ln (x)$