Calculus Examples

$y = x^{3} - 6 x^{2} - 15 x + 4$

Step 1

Find the x-intercepts.

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Step 1.1

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = x^{3} - 6 x^{2} - 15 x + 4$

Step 1.2

Solve the equation.

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Step 1.2.1

Remove parentheses.

$0 = x^{3} - 6 x^{2} - 15 x + 4$

Step 1.2.2

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x \approx - 2.09052051, 0.24384848, 7.84667202$

Step 1.3

x-intercept(s) in point form.

x-intercept(s): $(- 2.09052051, 0), (0.24384848, 0), (7.84667202, 0)$

Step 2

Find the y-intercepts.

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Step 2.1

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = {(0)}^{3} - 6 {(0)}^{2} - 15 \cdot 0 + 4$

Step 2.2

Solve the equation.

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Step 2.2.1

Remove parentheses.

$y = 0^{3} - 6 {(0)}^{2} - 15 \cdot 0 + 4$

Step 2.2.2

Remove parentheses.

$y = 0^{3} - 6 \cdot 0^{2} - 15 \cdot 0 + 4$

Step 2.2.3

Remove parentheses.

$y = {(0)}^{3} - 6 {(0)}^{2} - 15 \cdot 0 + 4$

Step 2.2.4

Simplify ${(0)}^{3} - 6 {(0)}^{2} - 15 \cdot 0 + 4$ .

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Step 2.2.4.1

Simplify each term.

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Step 2.2.4.1.1

Raising $0$ to any positive power yields $0$ .

$y = 0 - 6 {(0)}^{2} - 15 \cdot 0 + 4$

Step 2.2.4.1.2

Raising $0$ to any positive power yields $0$ .

$y = 0 - 6 \cdot 0 - 15 \cdot 0 + 4$

Step 2.2.4.1.3

Multiply $- 6$ by $0$ .

$y = 0 + 0 - 15 \cdot 0 + 4$

Step 2.2.4.1.4

Multiply $- 15$ by $0$ .

$y = 0 + 0 + 0 + 4$

Step 2.2.4.2

Simplify by adding numbers.

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Step 2.2.4.2.1

Add $0$ and $0$ .

$y = 0 + 0 + 4$

Step 2.2.4.2.2

Add $0$ and $0$ .

$y = 0 + 4$

Step 2.2.4.2.3

Add $0$ and $4$ .

$y = 4$

Step 2.3

y-intercept(s) in point form.

y-intercept(s): $(0, 4)$

Step 3

List the intersections.

x-intercept(s): $(- 2.09052051, 0), (0.24384848, 0), (7.84667202, 0)$

y-intercept(s): $(0, 4)$

Step 4