Calculus Examples

$f (x) = \sin (x) \ln (5 x)$

Step 1

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = \sin (x)$ and $g (x) = \ln (5 x)$ .

$\sin (x) \frac{d}{d x} [\ln (5 x)] + \ln (5 x) \frac{d}{d x} [\sin (x)]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \ln (x)$ and $g (x) = 5 x$ .

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Step 2.1

To apply the Chain Rule, set $u$ as $5 x$ .

$\sin (x) (\frac{d}{d u} [\ln (u)] \frac{d}{d x} [5 x]) + \ln (5 x) \frac{d}{d x} [\sin (x)]$

Step 2.2

The derivative of $\ln (u)$ with respect to $u$ is $\frac{1}{u}$ .

$\sin (x) (\frac{1}{u} \frac{d}{d x} [5 x]) + \ln (5 x) \frac{d}{d x} [\sin (x)]$

Step 2.3

Replace all occurrences of $u$ with $5 x$ .

$\sin (x) (\frac{1}{5 x} \frac{d}{d x} [5 x]) + \ln (5 x) \frac{d}{d x} [\sin (x)]$

Step 3

Differentiate.

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Step 3.1

Combine $\frac{1}{5 x}$ and $\sin (x)$ .

$\frac{\sin (x)}{5 x} \frac{d}{d x} [5 x] + \ln (5 x) \frac{d}{d x} [\sin (x)]$

Step 3.2

Since $5$ is constant with respect to $x$ , the derivative of $5 x$ with respect to $x$ is $5 \frac{d}{d x} [x]$ .

$\frac{\sin (x)}{5 x} (5 \frac{d}{d x} [x]) + \ln (5 x) \frac{d}{d x} [\sin (x)]$

Step 3.3

Simplify terms.

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Step 3.3.1

Combine $5$ and $\frac{\sin (x)}{5 x}$ .

$\frac{5 \sin (x)}{5 x} \frac{d}{d x} [x] + \ln (5 x) \frac{d}{d x} [\sin (x)]$

Step 3.3.2

Cancel the common factor of $5$ .

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Step 3.3.2.1

Cancel the common factor.

$\frac{5 \sin (x)}{5 x} \frac{d}{d x} [x] + \ln (5 x) \frac{d}{d x} [\sin (x)]$

Step 3.3.2.2

Rewrite the expression.

$\frac{\sin (x)}{x} \frac{d}{d x} [x] + \ln (5 x) \frac{d}{d x} [\sin (x)]$

Step 3.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{\sin (x)}{x} \cdot 1 + \ln (5 x) \frac{d}{d x} [\sin (x)]$

Step 3.5

Multiply $\frac{\sin (x)}{x}$ by $1$ .

$\frac{\sin (x)}{x} + \ln (5 x) \frac{d}{d x} [\sin (x)]$

Step 4

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$\frac{\sin (x)}{x} + \ln (5 x) \cos (x)$

Step 5

Reorder terms.

$\cos (x) \ln (5 x) + \frac{\sin (x)}{x}$