Calculus Examples

$e^{\frac{8}{x}}$

Step 1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = \frac{8}{x}$ .

Tap for more steps...

Step 1.1

To apply the Chain Rule, set $u$ as $\frac{8}{x}$ .

$\frac{d}{d u} [e^{u}] \frac{d}{d x} [\frac{8}{x}]$

Step 1.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u} [a^{u}]$ is $a^{u} \ln (a)$ where $a$ = $e$ .

$e^{u} \frac{d}{d x} [\frac{8}{x}]$

Step 1.3

Replace all occurrences of $u$ with $\frac{8}{x}$ .

$e^{\frac{8}{x}} \frac{d}{d x} [\frac{8}{x}]$

Step 2

Differentiate.

Tap for more steps...

Step 2.1

Since $8$ is constant with respect to $x$ , the derivative of $\frac{8}{x}$ with respect to $x$ is $8 \frac{d}{d x} [\frac{1}{x}]$ .

$e^{\frac{8}{x}} (8 \frac{d}{d x} [\frac{1}{x}])$

Step 2.2

Rewrite $\frac{1}{x}$ as $x^{- 1}$ .

$e^{\frac{8}{x}} (8 \frac{d}{d x} [x^{- 1}])$

Step 2.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = - 1$ .

$e^{\frac{8}{x}} (8 (- x^{- 2}))$

Step 2.4

Multiply $- 1$ by $8$ .

$e^{\frac{8}{x}} (- 8 x^{- 2})$

Step 3

Simplify.

Tap for more steps...

Step 3.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$e^{\frac{8}{x}} (- 8 \frac{1}{x^{2}})$

Step 3.2

Combine terms.

Tap for more steps...

Step 3.2.1

Combine $- 8$ and $\frac{1}{x^{2}}$ .

$e^{\frac{8}{x}} \frac{- 8}{x^{2}}$

Step 3.2.2

Move the negative in front of the fraction.

$e^{\frac{8}{x}} (- \frac{8}{x^{2}})$

Step 3.2.3

Combine $e^{\frac{8}{x}}$ and $\frac{8}{x^{2}}$ .

$- \frac{e^{\frac{8}{x}} \cdot 8}{x^{2}}$

Step 3.2.4

Move $8$ to the left of $e^{\frac{8}{x}}$ .

$- \frac{8 e^{\frac{8}{x}}}{x^{2}}$