Calculus Examples

$9 \cos (x) - 9 \sin (x) = 0$

Step 1

Divide each term in the equation by $\cos (x)$ .

$\frac{9 \cos (x)}{\cos (x)} + \frac{- 9 \sin (x)}{\cos (x)} = \frac{0}{\cos (x)}$

Step 2

Cancel the common factor of $\cos (x)$ .

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Step 2.1

Cancel the common factor.

$\frac{9 \cos (x)}{\cos (x)} + \frac{- 9 \sin (x)}{\cos (x)} = \frac{0}{\cos (x)}$

Step 2.2

Divide $9$ by $1$ .

$9 + \frac{- 9 \sin (x)}{\cos (x)} = \frac{0}{\cos (x)}$

Step 3

Separate fractions.

$9 + \frac{- 9}{1} \cdot \frac{\sin (x)}{\cos (x)} = \frac{0}{\cos (x)}$

Step 4

Convert from $\frac{\sin (x)}{\cos (x)}$ to $\tan (x)$ .

$9 + \frac{- 9}{1} \cdot \tan (x) = \frac{0}{\cos (x)}$

Step 5

Divide $- 9$ by $1$ .

$9 - 9 \tan (x) = \frac{0}{\cos (x)}$

Step 6

Separate fractions.

$9 - 9 \tan (x) = \frac{0}{1} \cdot \frac{1}{\cos (x)}$

Step 7

Convert from $\frac{1}{\cos (x)}$ to $\sec (x)$ .

$9 - 9 \tan (x) = \frac{0}{1} \cdot \sec (x)$

Step 8

Divide $0$ by $1$ .

$9 - 9 \tan (x) = 0 \sec (x)$

Step 9

Multiply $0$ by $\sec (x)$ .

$9 - 9 \tan (x) = 0$

Step 10

Subtract $9$ from both sides of the equation.

$- 9 \tan (x) = - 9$

Step 11

Divide each term in $- 9 \tan (x) = - 9$ by $- 9$ and simplify.

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Step 11.1

Divide each term in $- 9 \tan (x) = - 9$ by $- 9$ .

$\frac{- 9 \tan (x)}{- 9} = \frac{- 9}{- 9}$

Step 11.2

Simplify the left side.

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Step 11.2.1

Cancel the common factor of $- 9$ .

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Step 11.2.1.1

Cancel the common factor.

$\frac{- 9 \tan (x)}{- 9} = \frac{- 9}{- 9}$

Step 11.2.1.2

Divide $\tan (x)$ by $1$ .

$\tan (x) = \frac{- 9}{- 9}$

Step 11.3

Simplify the right side.

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Step 11.3.1

Divide $- 9$ by $- 9$ .

$\tan (x) = 1$

Step 12

Take the inverse tangent of both sides of the equation to extract $x$ from inside the tangent.

$x = \arctan (1)$

Step 13

Simplify the right side.

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Step 13.1

The exact value of $\arctan (1)$ is $\frac{π}{4}$ .

$x = \frac{π}{4}$

Step 14

The tangent function is positive in the first and third quadrants. To find the second solution, add the reference angle from $π$ to find the solution in the fourth quadrant.

$x = π + \frac{π}{4}$

Step 15

Simplify $π + \frac{π}{4}$ .

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Step 15.1

To write $π$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$x = π \cdot \frac{4}{4} + \frac{π}{4}$

Step 15.2

Combine fractions.

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Step 15.2.1

Combine $π$ and $\frac{4}{4}$ .

$x = \frac{π \cdot 4}{4} + \frac{π}{4}$

Step 15.2.2

Combine the numerators over the common denominator.

$x = \frac{π \cdot 4 + π}{4}$

Step 15.3

Simplify the numerator.

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Step 15.3.1

Move $4$ to the left of $π$ .

$x = \frac{4 \cdot π + π}{4}$

Step 15.3.2

Add $4 π$ and $π$ .

$x = \frac{5 π}{4}$

Step 16

Find the period of $\tan (x)$ .

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Step 16.1

The period of the function can be calculated using $\frac{π}{| b |}$ .

$\frac{π}{| b |}$

Step 16.2

Replace $b$ with $1$ in the formula for period.

$\frac{π}{| 1 |}$

Step 16.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{π}{1}$

Step 16.4

Divide $π$ by $1$ .

$π$

Step 17

The period of the $\tan (x)$ function is $π$ so values will repeat every $π$ radians in both directions.

$x = \frac{π}{4} + π n, \frac{5 π}{4} + π n$ , for any integer $n$

Step 18

Consolidate the answers.

$x = \frac{π}{4} + π n$ , for any integer $n$