Calculus Examples

$3 x^{2} + 24 x + 54 = 6$

Step 1

Subtract $6$ from both sides of the equation.

$3 x^{2} + 24 x + 54 - 6 = 0$

Step 2

Subtract $6$ from $54$ .

$3 x^{2} + 24 x + 48 = 0$

Step 3

Factor the left side of the equation.

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Step 3.1

Factor $3$ out of $3 x^{2} + 24 x + 48$ .

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Step 3.1.1

Factor $3$ out of $3 x^{2}$ .

$3 (x^{2}) + 24 x + 48 = 0$

Step 3.1.2

Factor $3$ out of $24 x$ .

$3 (x^{2}) + 3 (8 x) + 48 = 0$

Step 3.1.3

Factor $3$ out of $48$ .

$3 x^{2} + 3 (8 x) + 3 \cdot 16 = 0$

Step 3.1.4

Factor $3$ out of $3 x^{2} + 3 (8 x)$ .

$3 (x^{2} + 8 x) + 3 \cdot 16 = 0$

Step 3.1.5

Factor $3$ out of $3 (x^{2} + 8 x) + 3 \cdot 16$ .

$3 (x^{2} + 8 x + 16) = 0$

Step 3.2

Factor using the perfect square rule.

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Step 3.2.1

Rewrite $16$ as $4^{2}$ .

$3 (x^{2} + 8 x + 4^{2}) = 0$

Step 3.2.2

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$8 x = 2 \cdot x \cdot 4$

Step 3.2.3

Rewrite the polynomial.

$3 (x^{2} + 2 \cdot x \cdot 4 + 4^{2}) = 0$

Step 3.2.4

Factor using the perfect square trinomial rule $a^{2} + 2 a b + b^{2} = {(a + b)}^{2}$ , where $a = x$ and $b = 4$ .

$3 {(x + 4)}^{2} = 0$

Step 4

Divide each term in $3 {(x + 4)}^{2} = 0$ by $3$ and simplify.

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Step 4.1

Divide each term in $3 {(x + 4)}^{2} = 0$ by $3$ .

$\frac{3 {(x + 4)}^{2}}{3} = \frac{0}{3}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $3$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{3 {(x + 4)}^{2}}{3} = \frac{0}{3}$

Step 4.2.1.2

Divide ${(x + 4)}^{2}$ by $1$ .

${(x + 4)}^{2} = \frac{0}{3}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide $0$ by $3$ .

${(x + 4)}^{2} = 0$

Step 5

Set the $x + 4$ equal to $0$ .

$x + 4 = 0$

Step 6

Subtract $4$ from both sides of the equation.

$x = - 4$